Very helpful & much appreciated.
Richard Davey wrote:
> Hello John,
>
> Wednesday, February 25, 2004, 6:26:41 PM, you wrote:
>
> JTJ> Richard,
> JTJ> Thanks. Should I still include the die ?
>
> JTJ> $glquery = mysql_query($sql) or die("Invalid query: " . mysql_error());
>
> It's up to you, I nev
Hello John,
Wednesday, February 25, 2004, 6:26:41 PM, you wrote:
JTJ> Richard,
JTJ> Thanks. Should I still include the die ?
JTJ> $glquery = mysql_query($sql) or die("Invalid query: " . mysql_error());
It's up to you, I never do. It won't give you a very clean exit if an
error occurs.
--
Best
Richard,
Thanks. Should I still include the die ?
$myconnection = mysql_connect($server,$user,$pass);
mysql_select_db($db,$myconnection);
$eventid = $link_date;
$sql = 'SELECT * FROM '.$table.' where eventid like \''.$eventid.'\';';
$glquery = mysql_query($sql) or die("Invalid query: " . mysql_e
Bao,
I have only one entry where eventid = 2004-02-28. if (!$glquery) does not result in
anything either.
Jason,
Where in the manual would I look? I looked at
http://www.php.net/manual/en/function.mysql-query.php but don't find anything
inspiring.
It does not die, so I can't check if it is fal
On Thursday 26 February 2004 01:53, John Taylor-Johnston wrote:
> Here is my code. $sql works correctly, but am not sure I did this line
> correct:
Your query ($sql) is incorrect and will not work. See manual for why.
> $glquery = mysql_query($sql);
>
> because "if ($glquery)" always returns som
Hello John,
Wednesday, February 25, 2004, 5:53:13 PM, you wrote:
JTJ> Here is my code. $sql works correctly, but am not sure I did this line correct:
JTJ> $glquery = mysql_query($sql);
JTJ> because "if ($glquery)" always returns something. I want to know if it returns
NULL.
mysql_query will ret
John Taylor-Johnston wrote:
Bao or anyone,
Here is my code. $sql works correctly, but am not sure I did this line correct:
$glquery = mysql_query($sql);
because "if ($glquery)" always returns something. I want to know if it returns NULL.
Gee, I was goofed up by your last $sql:) Now you can
Bao or anyone,
Here is my code. $sql works correctly, but am not sure I did this line correct:
$glquery = mysql_query($sql);
because "if ($glquery)" always returns something. I want to know if it returns NULL.
Thanks for your time,
John
---snip-
$myconnection = mysql_c
On Thursday 26 February 2004 01:31, John Taylor-Johnston wrote:
> I'm trying to figure out something. I found some calendar making code. For
> each table cell, I want to add $day around $day if an entry
> exists in $db.$table
>
> $sql = 'SELECT * FROM '.$db.'.'.$table.' where eventid like '.$eventi
John Taylor-Johnston wrote:
I'm trying to figure out something. I found some calendar making code. For each table cell, I want to add $day around $day if an entry exists in $db.$table
$sql = 'SELECT * FROM '.$db.'.'.$table.' where eventid like '.$eventid.';';
if ($sql ??)
This will do:
I'm trying to figure out something. I found some calendar making code. For each table
cell, I want to add $day around $day if an entry exists in $db.$table
$sql = 'SELECT * FROM '.$db.'.'.$table.' where eventid like '.$eventid.';';
if ($sql ??)
{echo "$day";
}else{
echo "$day";
}
How do I code
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