I am very new to the PHP application and would like to create a new project.
I would like to have a file to save my application level variable and
functions.
I would like to know does PHP have any default file name and file path for
this file like Web.config file for ASP.Net and Application.cfm
On Fri, Mar 22, 2013 at 10:22 AM, inu...@gmail.com wrote:
I am very new to the PHP application and would like to create a new project.
I would like to have a file to save my application level variable and
functions.
I would like to know does PHP have any default file name and file path for
2013/3/22 inu...@gmail.com
I am very new to the PHP application and would like to create a new
project.
I would like to have a file to save my application level variable and
functions.
I would like to know does PHP have any default file name and file path for
this file like Web.config file
On 22 Mar 2013, at 14:22, inu...@gmail.com wrote:
I am very new to the PHP application and would like to create a new project.
I would like to have a file to save my application level variable and
functions.
I would like to know does PHP have any default file name and file path for
this
On Fri, Mar 22, 2013 at 10:26 AM, Stuart Dallas stu...@3ft9.com wrote:
On 22 Mar 2013, at 14:22, inu...@gmail.com wrote:
I am very new to the PHP application and would like to create a new
project.
I would like to have a file to save my application level variable and
functions.
I
So here's some new observations on the instance variables being NULL.
As far as we found out this is the sequence of events:
1. Apache (MPM) received request A which executes a php script.
2. Within this script during the unserialization of an object an
exception is thrown.
3. This exception is
As a little clarification: The Apache server in question is configured as a
MPM prefork.
On Wed, Aug 15, 2012 at 4:28 PM, Reto Kaiser r...@cargomedia.ch wrote:
So here's some new observations on the instance variables being NULL.
As far as we found out this is the sequence of events:
1.
Hi,
Thanks for your input Robert and Volmar! I have googled again with
instance variable instead of class variable - but have not found
any similar reports.
I'm pretty sure those are the same objects. The application usually
runs alright. We only see the instance variables becoming NULL since
Hi,
We have since deployed another webserver machine and observe the exact
same behavior there.
So it is not a hardware problem.
We have also disabled various php modules, but this didn't help either.
Any debug suggestions are welcome! :)
Reto
On Tue, Aug 14, 2012 at 10:40 AM, Reto Kaiser
I'm not real clear on what's happening. Are you saying that if you assign
values to the protected class members, and then immediately read them,
that they're null? So, there's code something like this:
class Foo {
public function Something() {
$this-foo = 1;
//shows null instead
On 08/12/2012 05:32 AM, Reto Kaiser wrote:
Hi,
So I have this strange situation where I assign a classvariable a
value, but when I read the value it is NULL.
Does anyone have an idea what could cause this, or how to further debug?
Thanks,
Reto
What is your error reporting set to?
Do you
Hey,
We have:
error_reporting((E_ALL | E_STRICT) ~(E_NOTICE | E_USER_NOTICE));
Displaying errors is disabled:
display_errors = Off
We have a custom error handler which logs all errors to a file.
In this file we receive byeffect errors, like that the second argument
to array_key_exists should
On 12-08-12 08:32 AM, Reto Kaiser wrote:
Hi,
So I have this strange situation where I assign a classvariable a
value, but when I read the value it is NULL.
The class has one variable declared:
=
class A {
private $_cookies;
}
=
That is a private instance variable NOT
It's only a hint, but You start checking if the Object Ids are the same or not.
2012/8/13 Robert Cummings rob...@interjinn.com:
On 12-08-12 08:32 AM, Reto Kaiser wrote:
Hi,
So I have this strange situation where I assign a classvariable a
value, but when I read the value it is NULL.
The
Hi,
So I have this strange situation where I assign a classvariable a
value, but when I read the value it is NULL.
The class has one variable declared:
=
class A {
private $_cookies;
}
=
In a method of this class I assign this classvariable plus an
undeclared
There are essentially 2 ways:
1. All POSTed data is present in the $_POST superglobal array. So you
could just loop over that, ignore the fields you already knew were there,
and the data remaining is then essentially the data you seek. The keys in
the $_POST array are the fieldnames you are
more boxes as per user require.
Hi All,
I am a basic user of PHP and I have need of reading the dynamic HTML
form
field as a variable in PHP so it will be great if someone can share some
good link or snip for quick understanding.
Thanks,
Devang
http://lmgtfy.com/?q=how+to+pass+and+receive
know how to pass variable but having difficulties when I use the
dynamic
form field in HTML that add more boxes as per user require.
Hi All,
I am a basic user of PHP and I have need of reading the dynamic HTML
form
field as a variable in PHP so it will be great if someone can share
some
Hi All,
I am a basic user of PHP and I have need of reading the dynamic HTML form
field as a variable in PHP so it will be great if someone can share some
good link or snip for quick understanding.
Thanks,
Devang
Hi All,
I am a basic user of PHP and I have need of reading the dynamic HTML form
field as a variable in PHP so it will be great if someone can share some
good link or snip for quick understanding.
Thanks,
Devang
http://lmgtfy.com/?q=how+to+pass+and+receive+a+PHP+variable
When just
in PHP so it will be great if someone can share some
good link or snip for quick understanding.
Thanks,
Devang
http://lmgtfy.com/?q=how+to+pass+and+receive+a+PHP+variable
When just starting out, Google is your friend.
Or did I misunderstand your question?
-Govinda
Devang,
Please
.
Hi All,
I am a basic user of PHP and I have need of reading the dynamic HTML
form
field as a variable in PHP so it will be great if someone can share some
good link or snip for quick understanding.
Thanks,
Devang
http://lmgtfy.com/?q=how+to+pass+and+receive+a+PHP+variable
When just
On 11 April 2011 20:28, Ethan Rosenberg eth...@earthlink.net wrote:
Dear list -
I an writing a script that will simulate a chess board. On a move from e2
to e6 [see below] the variable in e2 is never assigned to e6. Here are some
code snippets:
?php
session_start();
session_name(Chess);
Dear list -
I an writing a script that will simulate a chess board. On a move
from e2 to e6 [see below] the variable in e2 is never assigned to
e6. Here are some code snippets:
?php
session_start();
session_name(Chess);
error_reporting(1);
if ($_SESSION['flag'] != 1)
{
$flag = 1;
echo br
On 3/25/2011 12:09 PM, markb wrote:
Very rusty with PHP.
We moved our web site to a new hosting service (godaddy). PHP changed
from 4x to 5.2.17.
I can no longer change $_SESSION variables after the first use.
First call to form - start session create variables
Second call - can read variables,
On 3/25/2011 12:09 PM, markb wrote:
Very rusty with PHP.
We moved our web site to a new hosting service (godaddy). PHP changed
from 4x to 5.2.17.
I can no longer change $_SESSION variables after the first use.
First call to form - start session create variables
Second call - can read variables,
On 3/25/2011 12:09 PM, markb wrote:
Very rusty with PHP.
We moved our web site to a new hosting service (godaddy). PHP changed
from 4x to 5.2.17.
I can no longer change $_SESSION variables after the first use.
First call to form - start session create variables
Second call - can read variables,
Hi Danny,
On Friday, March 11, 2011, 7:28:10 PM, you wrote:
I have a form that has a long list of radio-bottons inside of it. The
radio-buttons are dynamically created via php and MySQL.
Here is an example of one of the radio buttons:
input type=radio name=?php print
On 03/11/2011 01:28 PM, Danny wrote:
Hi guys,
I have a form that has a long list of radio-bottons inside of it. The
radio-buttons are dynamically created via php and MySQL.
Here is an example of one of the radio buttons:
input type=radio name=?php print (radio_.$result_from_mysql) ; ?
You could use foreach to iterate through the post variables until you
encounter a match:
foreach ($_POST as $key = $value){
if (substr($key, 0, 6) == radio_) {
$buttonName = $key;
$buttonValue = 4value;
break 2;
}
}
I haven't tried the above code, but I hope
On 3/11/2011 12:03 PM, Shawn McKenzie wrote:
On 03/11/2011 01:28 PM, Danny wrote:
Hi guys,
I have a form that has a long list of radio-bottons inside of it. The
radio-buttons are dynamically created via php and MySQL.
Here is an example of one of the radio buttons:
input type=radio
On 03/11/2011 02:33 PM, Jim Lucas wrote:
On 3/11/2011 12:03 PM, Shawn McKenzie wrote:
On 03/11/2011 01:28 PM, Danny wrote:
Hi guys,
I have a form that has a long list of radio-bottons inside of it. The
radio-buttons are dynamically created via php and MySQL.
Here is an example of one of
On 3/11/2011 2:43 PM, Geoff Lane wrote:
[snip]
You could use foreach to iterate through the post variables until you
encounter a match:
foreach ($_POST as $key = $value){
if (substr($key, 0, 6) == radio_) {
$buttonName = $key;
$buttonValue = 4value;
break 2;
Hi guys,
I am trying to generate an abstract Singleton class for use in arbitrary
classes, like
class Foo extends Singleton {}
and generate a new class with Foo - getInstance();
How can I manage to use this with an unkown number of parameters like
Foo - getInstance('a', 'b'); ?
Something
On Wed, Dec 15, 2010 at 2:11 PM, Sebastian Detert php-maill...@elygor.dewrote:
Hi guys,
I am trying to generate an abstract Singleton class for use in arbitrary
classes, like
class Foo extends Singleton {}
and generate a new class with Foo - getInstance();
Until traits release I think
-Original Message-
From: Nathan Nobbe [mailto:quickshif...@gmail.com]
Sent: Wednesday, December 15, 2010 1:31 PM
To: Sebastian Detert
Cc: php-general@lists.php.net
Subject: Re: [PHP] Singleton with variable parameters
On Wed, Dec 15, 2010 at 2:11 PM, Sebastian Detert php-
maill
foreach ($_POST as $key=$post) {
$post=str_replace( , +, $post);
$url.=$key.=.$post.;
}
Hi Bob,
One thing I see is that you're appending values on to the end of a url that
already has 2 values, so you should place the at the beginning of your
line instead of at the
On Wednesday 24 November 2010,
Bob Keightley bob.keight...@virgin.net wrote:
I already have a curl script that gets the web page, but it doesn't pass
the parameters
Hello Bob,
Being new to PHP I haven't the first idea how to modify it so that it
does.
Script is as follows:
$url =
Guess I've not explained this very well.
The external page I am fetching using another curl script has asp query
hyperlinks in it. I do not know the variable names in each query or the
values they have.
All I want to do is replace the external url referenced in those links with
a url which is
-Original Message-
From: Bob Keightley [mailto:bob.keight...@virgin.net]
Sent: Wednesday, November 24, 2010 11:25 AM
To: php-general@lists.php.net
Subject: Re: [PHP] curl and variable parameters in hyperlink
Guess I've not explained this very well.
The external page I am
Thanks to all for your interest so far but as I said, new to PHP. Changed
POST to GET and all now working fine!
Tommy, the third party site is fully aware of what I am doing. We pay them
to use the data, as do lots of other companies in our industry. Supplying
data is what they do. We could
First use of Curl so probably a very simple problem - I have a script which
loads a third party web page into my site. That page contains links which
have variable parameters i.e. www.blahblah.asp?param1=xxxparam2=yyy.
Any clues as to what I need to do to pass these parameters in a curl script
:12 PM
To: php-general@lists.php.net
Subject: [PHP] curl and variable parameters in hyperlink
First use of Curl so probably a very simple problem - I have a script which
loads a third party web page into my site. That page contains links which
have variable parameters i.e. www.blahblah.asp
I already have a curl script that gets the web page, but it doesn't pass the
parameters
Being new to PHP I haven't the first idea how to modify it so that it does.
Script is as follows:
$url = http://www.xx.com/query.asp?param1=val1param2=val2;;
foreach ($_POST as $key=$post) {
or other non-variable syntax elements such as - or ::.
eval() can do this because it parses the code as PHP. Variable variables
take the *variable name* contained in the variable and look it up in the
current scope. This is a variable name:
ini_array
This is not:
ini_array['agis_core
On 10-08-26 09:54 AM, João Cândido de Souza Neto wrote:
I know that in PHP I can use this:
$var1 = text;
$var2 = '$var1';
4cho $$var2;
So it gives me text.
It would if you didn't have typos and the wrong quotes in the above :)
My question is, is there a way of doing it with constant like
Really cool...
Thanks and fogive me by my mistake. hehe
--
João Cândido de Souza Neto
Robert Cummings rob...@interjinn.com escreveu na mensagem
news:4c76743a.2060...@interjinn.com...
On 10-08-26 09:54 AM, João Cândido de Souza Neto wrote:
I know that in PHP I can use this:
$var1 = text;
Hi,
define('MYCONST', 'something');
$my = 'my';
$const = 'const';
is it possible to get the value of MYCONST using variables $my and $const_
Br
Tanel
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Use the constant() function:
echo constant( $my . $const );
http://www.php.net/manual/en/function.constant.php
-Original Message-
From: Tanel Tammik [mailto:keevit...@gmail.com]
Sent: Friday, June 04, 2010 3:08 PM
To: php-general@lists.php.net
Subject: [PHP] constant from variable
Hi
On Fri, 2010-06-04 at 22:07 +0300, Tanel Tammik wrote:
Hi,
define('MYCONST', 'something');
$my = 'my';
$const = 'const';
is it possible to get the value of MYCONST using variables $my and $const_
Br
Tanel
I don't really see how you can? The only correlation at all is
Sumit Sharma wrote:
Hi,
I have developed a listing site which is totally class based. Now when it
authenticates a user login and set appropriate class variables to true and
set user info in user class variables, value of all the set variables are
lost when I forward the user to members
On Wed, 2009-09-09 at 10:36 -0500, Shawn McKenzie wrote:
Sumit Sharma wrote:
Hi,
I have developed a listing site which is totally class based. Now when it
authenticates a user login and set appropriate class variables to true and
set user info in user class variables, value of all the
--
From: Ashley Sheridan a...@ashleysheridan.co.uk
Date: Wed, Sep 9, 2009 at 9:14 PM
Subject: Re: [PHP] Re: Class variable value lost
To: Shawn McKenzie nos...@mckenzies.net
Cc: Sumit Sharma sumitp...@gmail.com, PHP General Mailing List
php-general@lists.php.net
On Wed, 2009-09-09 at 10:36 -0500, Shawn
On Wed, Sep 9, 2009 at 11:58 AM, Sumit Sharma sumitp...@gmail.com wrote:
What I have done is declared one User class in a separate file and created
its object there only. After this included this file in all other file which
are using its object. So the object is creating only once and included
issue than setting $_SESSION variables.
-- Forwarded message --
From: Ashley Sheridan a...@ashleysheridan.co.uk
Date: Wed, Sep 9, 2009 at 9:14 PM
Subject: Re: [PHP] Re: Class variable value lost
To: Shawn McKenzie nos...@mckenzies.net
Cc: Sumit Sharma sumitp...@gmail.com, PHP
Sumit Sharma wrote:
What I have done is declared one User class in a separate file and created
its object there only. After this included this file in all other file which
are using its object. So the object is creating only once and included in
every other file only once. Now when I over
The object only exists for that instance of the script, so when the user
navigates to the next page, the object is freed up from the memory.
There are a couple of ways you could get round this:
* don't navigate away from the page, and use AJAX calls to update
parts of the page
Lars Nielsen wrote:
Hi,
How do i access a variable from inside a class? ex. I want to use
$template_dir inside Template.
$template_dir = 'templates/';
class templateParser {
var $output;
function templateParser($templateFile='default_template.htm')
{
This might seem silly but here's what I'm trying to do
Suppose I have some kind of check variable - say for example
$abort_now. Or it could be a function. Something to be evaluated to a
value.
I want to execute a block of statements, but after EACH statement
executes, check the value of
On Tue, Jun 30, 2009 at 06:31:54PM -0500, Flint Million wrote:
This might seem silly but here's what I'm trying to do
Suppose I have some kind of check variable - say for example
$abort_now. Or it could be a function. Something to be evaluated to a
value.
I want to execute a block of
On Jun 30, 2009, at 10:48 PM, Paul M Foster pa...@quillandmouse.com
wrote:
On Tue, Jun 30, 2009 at 06:31:54PM -0500, Flint Million wrote:
This might seem silly but here's what I'm trying to do
Suppose I have some kind of check variable - say for example
$abort_now. Or it could be a
On Tue, Jun 30, 2009 at 11:21:03PM -0400, Phpster wrote:
On Jun 30, 2009, at 10:48 PM, Paul M Foster pa...@quillandmouse.com
wrote:
snip
FWIW, I've had to do this exact thing with regard to form validation,
except I'm not looping. Check each condition, and if it fails, never
mind
Hi Guys! Well I tried the INNER JOIN and still can not get it to echo the
AdminID so I know it isn't working, (what kind of things should I think
about that could make it not work) so far the only query that did work and
return the AdminID was my original I believe it was referred to as hosed
Terion Miller wrote:
Hi Guys! Well I tried the INNER JOIN and still can not get it to echo
the AdminID so I know it isn't working, (what kind of things should I
think about that could make it not work) so far the only query that
did work and return the AdminID was my original I believe it
Hi Again
Here is the query and code I tried:
$sql = SELECT * FROM workorders WHERE AdminID = (SELECT AdminID FROM admin
WHERE UserName = '
. mysql_real_escape_string($_SESSION['user']) . ');
$result2 = mysql_query ($sql);
$row2 = mysql_fetch_assoc ($result2);
$printrow =
Terion Miller wrote:
Hi Again
Here is the query and code I tried:
$sql = SELECT * FROM workorders WHERE AdminID = (SELECT AdminID FROM
admin WHERE UserName = '
. mysql_real_escape_string($_SESSION['user']) . ');
$result2 = mysql_query ($sql);
$row2 = mysql_fetch_assoc
Well upon looking it was number 2, I had no orders in the workorder table,
but here is an oddity I wonder if someone can explain if I run this simple
query:
$query = SELECT * FROM admin, workorders
WHERE admin.UserName = '.$_SESSION['user'].' ;
It returns adminID = 7 (my number is
Terion Miller wrote:
Well upon looking it was number 2, I had no orders in the workorder table,
but here is an oddity I wonder if someone can explain if I run this simple
query:
$query = SELECT * FROM admin, workorders
WHERE admin.UserName = '.$_SESSION['user'].' ;
It returns
Shawn McKenzie wrote:
Terion Miller wrote:
Well upon looking it was number 2, I had no orders in the workorder table,
but here is an oddity I wonder if someone can explain if I run this simple
query:
$query = SELECT * FROM admin, workorders
WHERE admin.UserName =
Not sure if I'm wording this right, what I am trying to do is look in two
tables, match the ID to use to pull information
Here's my code but it's not right, although it is picking up the user from
the session, I will also post what my variable debugging lists:
$query = SELECT
On Wed, Jan 28, 2009 at 3:18 PM, Terion Miller webdev.ter...@gmail.com wrote:
Not sure if I'm wording this right, what I am trying to do is look in two
tables, match the ID to use to pull information
Here's my code but it's not right, although it is picking up the user from
the session, I
Well I'm stuck I have the AdminID but now I can't seem to use it to pull
workorders with that AdminID . I couldn't get your block to work Andrew :(
I think I'm just not using it right now that I have it...lol
On Wed, Jan 28, 2009 at 2:26 PM, Andrew Ballard aball...@gmail.com wrote:
On Wed,
Well I'm stuck I have the AdminID but now I can't seem to use it to pull
workorders with that AdminID . I couldn't get your block to work Andrew :(
I think I'm just not using it right now that I have it...lol
Because there is ambiguity w/r/t the columns you are selecting, you'll
need to use
I just read it 3 times and I don't understand it.
On Wed, Jan 28, 2009 at 3:22 PM, Christoph Boget
christoph.bo...@gmail.comwrote:
Well I'm stuck I have the AdminID but now I can't seem to use it to pull
workorders with that AdminID . I couldn't get your block to work Andrew
:(
I think
On Wed, Jan 28, 2009 at 4:22 PM, Christoph Boget
christoph.bo...@gmail.com wrote:
Well I'm stuck I have the AdminID but now I can't seem to use it to pull
workorders with that AdminID . I couldn't get your block to work Andrew :(
I think I'm just not using it right now that I have it...lol
On Wed, Jan 28, 2009 at 4:31 PM, Terion Miller webdev.ter...@gmail.com wrote:
On Wed, Jan 28, 2009 at 3:22 PM, Christoph Boget christoph.bo...@gmail.com
wrote:
Well I'm stuck I have the AdminID but now I can't seem to use it to pull
workorders with that AdminID . I couldn't get your block
Terion Miller wrote:
Well I'm stuck I have the AdminID but now I can't seem to use it to pull
workorders with that AdminID . I couldn't get your block to work Andrew :(
I think I'm just not using it right now that I have it...lol
On Wed, Jan 28, 2009 at 2:26 PM, Andrew Ballard
Because there is ambiguity w/r/t the columns you are selecting, you'll
need to use aliases.
http://dev.mysql.com/doc/refman/5.1/en/identifiers.html
In your code, when you are referencing the column, do so using the
alias. That should solve your problem.
I just read it 3 times and I
Shawn McKenzie wrote:
Terion Miller wrote:
Well I'm stuck I have the AdminID but now I can't seem to use it to pull
workorders with that AdminID . I couldn't get your block to work Andrew :(
I think I'm just not using it right now that I have it...lol
On Wed, Jan 28, 2009 at 2:26 PM,
On Wed, Jan 28, 2009 at 3:43 PM, Shawn McKenzie nos...@mckenzies.netwrote:
Shawn McKenzie wrote:
Terion Miller wrote:
Well I'm stuck I have the AdminID but now I can't seem to use it to pull
workorders with that AdminID . I couldn't get your block to work Andrew
:(
I think I'm just
Terion Miller wrote:
On Wed, Jan 28, 2009 at 3:43 PM, Shawn McKenzie nos...@mckenzies.netwrote:
Shawn McKenzie wrote:
Terion Miller wrote:
Well I'm stuck I have the AdminID but now I can't seem to use it to pull
workorders with that AdminID . I couldn't get your block to work Andrew
:(
I
On Wed, Jan 28, 2009 at 4:00 PM, Shawn McKenzie nos...@mckenzies.netwrote:
Terion Miller wrote:
On Wed, Jan 28, 2009 at 3:43 PM, Shawn McKenzie nos...@mckenzies.net
wrote:
Shawn McKenzie wrote:
Terion Miller wrote:
Well I'm stuck I have the AdminID but now I can't seem to use it to
On Wed, Jan 28, 2009 at 4:12 PM, Terion Miller webdev.ter...@gmail.comwrote:
On Wed, Jan 28, 2009 at 4:00 PM, Shawn McKenzie nos...@mckenzies.netwrote:
Terion Miller wrote:
On Wed, Jan 28, 2009 at 3:43 PM, Shawn McKenzie nos...@mckenzies.net
wrote:
Shawn McKenzie wrote:
Terion
Here are my variables when I reveal them, I am picking up the right
adminID I can't figure out why it's returning random orders though:
$querySELECT admin.AdminID, workorders.AdminID FROM admin,
workorders WHERE admin.UserName = 'tmiller'
$result Resource id #5
$row
key
Here are my variables when I reveal them, I am picking up the right adminID
I can't figure out why it's returning random orders though:
$querySELECT admin.AdminID, workorders.AdminID FROM admin, workorders WHERE
admin.UserName = 'tmiller'
Please please please trim your posts to relevant
I'm not sure what you mean by trim the posts, please explain so I can spare
folks from redundant text.
Your post made perfect sense to me about the INNER JOIN , I looked it up
but it is not returning the AdminID, maybe my syntax is wrong?
$query = SELECT admin.AdminID , workorders.AdminID
Terion Miller wrote:
I'm not sure what you mean by trim the posts, please explain so I can
spare folks from redundant text.
Before you post, remove any text that you're not referencing (in this
case I removed my suggestion).
Your post made perfect sense to me about the INNER JOIN , I
Your post made perfect sense to me about the INNER JOIN , I looked it up
but it is not returning the AdminID, maybe my syntax is wrong?
$query = SELECT admin.AdminID , workorders.AdminID
FROM admin
INNER JOIN
workorders
ON AdminID(admin,
Well I tried both ways and still cannot get it to pick up the AdminID,
$query SELECT admin.AdminID , workorders.AdminID FROM admin INNER JOIN
workorders on AdminID WHERE admin.UserName = 'tmiller'
$result
$row
$SortBy WorkOrderID DESC
$Page 1
$PerPage30
$StartPage 0
$sql
Terion Miller wrote:
Your post made perfect sense to me about the INNER JOIN , I
looked it up but it is not returning the AdminID, maybe my
syntax is wrong?
$query = SELECT admin.AdminID , workorders.AdminID
FROM admin
The main problem is that you've never explained what you want to get
from the query. The replies have used your code as an example and I'm
pretty sure that's not what you want. Unless I totally mis-understand
what you want, you have 2 options:
1. Use the 2 queries that I gave you in a
Chris wrote:
The main problem is that you've never explained what you want to get
from the query. The replies have used your code as an example and I'm
pretty sure that's not what you want. Unless I totally mis-understand
what you want, you have 2 options:
1. Use the 2 queries that I
Hello,
suppose there is a file at http://otherhost.com/remote.php that looks
like this:
?php
if (!isset($safe_flag))
{
die(hacking attempt);
}
echo You are in;
?
Suppose i executed the following php file at http://myhost.com/local.php
?php
require_once(http://otherhost.com/remote.php;);
2009/1/7 Daniel Kolbo kolb0...@umn.edu:
suppose there is a file at http://otherhost.com/remote.php that looks like
this:
?php
if (!isset($safe_flag))
{
die(hacking attempt);
}
echo You are in;
?
Suppose i executed the following php file at http://myhost.com/local.php
?php
If register_globals is on (ewww!) at otherhost.com, then ?safe_flag on the
URL will get in.
This is one of the reasons why register_globals should be OFF.
NOTE:
The code you gave does not describe the circumstances whereby $safe_flag is
set. There could be all manner of other issues
c...@l-i-e.com wrote:
If register_globals is on (ewww!) at otherhost.com, then ?safe_flag on the
URL will get in.
This is one of the reasons why register_globals should be OFF.
NOTE:
The code you gave does not describe the circumstances whereby $safe_flag is
set. There could be all manner
What I am trying to do is to
pass an aggregate variable which is the sum of
some smaller variable.
This var also need to finish in the form of $.YY .
Pointers please.
--
Member - Liberal International
This is [EMAIL PROTECTED] Ici [EMAIL PROTECTED]
God, Queen and country! Beware
The Doctor wrote:
What I am trying to do is to
pass an aggregate variable which is the sum of
some smaller variable.
This var also need to finish in the form of $.YY .
Pointers please.
Most of the above can be done using number_format(). The dollar sign you will
have to add
On Fri, Oct 10, 2008 at 1:33 PM, The Doctor [EMAIL PROTECTED] wrote:
What I am trying to do is to
pass an aggregate variable which is the sum of
some smaller variable.
This var also need to finish in the form of $.YY .
Pointers please.
Would you care to explain a little further what
On Fri, Oct 10, 2008 at 01:48:01PM -0400, Andrew Ballard wrote:
On Fri, Oct 10, 2008 at 1:33 PM, The Doctor [EMAIL PROTECTED] wrote:
What I am trying to do is to
pass an aggregate variable which is the sum of
some smaller variable.
This var also need to finish in the form of $.YY .
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