How can i take the variable name inside a function, ex:
definition:
function example( $ex ){
echo Variable Name is $ex ; // how to do this?
}
use:
example($ball);
output: Variable Name is ball;
another:
example($sportCar);
output: Variable Name is sportCar;
is that possible?
--
Jônata Tyska Carvalho wrote:
How can i take the variable name inside a function, ex:
definition:
function example( $ex ){
echo Variable Name is $ex ; // how to do this?
}
use:
example($ball);
output: Variable Name is ball;
another:
example($sportCar);
output: Variable
Would something like this work?
Definition:
function example($$ex) {
echo Variable Name is $ex;
}
example($ball);
I'm fairly new to php and not so familiar with variable variables, but I
thought I'd throw it out there as a thought!
Andy
On 10/11/06, Jochem Maas [EMAIL PROTECTED] wrote:
Andy Hultgren wrote:
Would something like this work?
did you try it? ;-)
it won't work
Definition:
function example($$ex) {
echo Variable Name is $ex;
}
example($ball);
I'm fairly new to php and not so familiar with variable variables, but I
thought I'd throw it out there
u no... I suppose I should have though! :)
On 10/11/06, Jochem Maas [EMAIL PROTECTED] wrote:
Andy Hultgren wrote:
Would something like this work?
did you try it? ;-)
it won't work
Definition:
function example($$ex) {
echo Variable Name is $ex;
}
example($ball);
I'm
Check this out: http://www.php.net/manual/en/functions.arguments.php
Specifically this example:
Making arguments be passed by reference
By default, function arguments are passed by value (so that if you change
the value of the argument within the function, it does not get changed
outside of
On 10/11/06, Andy Hultgren [EMAIL PROTECTED] wrote:
?php
function add_some_extra($string)
{
$string .= 'and something extra.';
}
$str = 'This is a string, ';
add_some_extra($str);
echo $str;// outputs 'This is a string, and something extra.'
?
I think that does what you want?
In the
On 10/11/06, Paul Scott [EMAIL PROTECTED] wrote:
On Wed, 2006-10-11 at 13:19 -0400, Eric Butera wrote:
In the add_some_extra example you gave he wants the named value of the
passed parameter which is $str.
Isn't that what the Reflection API is there for?
--Paul
All Email originating
On Wed, 2006-10-11 at 13:19 -0400, Eric Butera wrote:
In the add_some_extra example you gave he wants the named value of the
passed parameter which is $str.
Isn't that what the Reflection API is there for?
--Paul
All Email originating from UWC is covered by disclaimer
On Wed, October 11, 2006 9:58 am, Jônata Tyska Carvalho wrote:
How can i take the variable name inside a function, ex:
definition:
function example( $ex ){
echo Variable Name is $ex ; // how to do this?
}
use:
example($ball);
output: Variable Name is ball;
another:
On Wed, October 11, 2006 12:19 pm, Eric Butera wrote:
On 10/11/06, Andy Hultgren [EMAIL PROTECTED] wrote:
?php
function add_some_extra($string)
{
$string .= 'and something extra.';
}
$str = 'This is a string, ';
add_some_extra($str);
echo $str;// outputs 'This is a string, and
On Wed, October 11, 2006 2:21 pm, Richard Lynch wrote:
If you really really really know what you are doing, you can do this:
And if you make no typos like I just did... :-)
function example($name){
// global $name; //Whoops!
global $$name; //note the TWO $ symbols!
echo The variable
i know what i want to do, and im not a rookie in php.
example of a use:
debug($vetNames);
output:
The variable vetNames has the follow properties:
key1 = value1,
key2 = value2
just one example. need it for another things.
On 10/11/06, Richard Lynch [EMAIL PROTECTED] wrote:
On
On Wed, 2006-10-11 at 19:02 -0300, Jônata Tyska Carvalho wrote:
i know what i want to do, and im not a rookie in php.
example of a use:
debug($vetNames);
output:
The variable vetNames has the follow properties:
key1 = value1,
key2 = value2
Example:
?php
function fooA( $fooA )
{
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