. in the required fields array
- Original Message -
From: George Whiffen [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, November 21, 2001 7:28 AM
Subject: Re: [PHP] How do I convert from perl to php? - Reality Check
Taxation
So I would have to write a seperate if condition for each
So I would have to write a seperate if condition for each form input field i wanted
to require? that doesn't make for a very dynamic script...
if(!(isset($name) isset($address) isset($phone)) {
echo You left one empty.;
}
Reality Check: We write code to solve real world
define the variable as an input from a form
2. in the required fields array
- Original Message -
From: George Whiffen [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, November 21, 2001 7:28 AM
Subject: Re: [PHP] How do I convert from perl to php? - Reality Check
Taxation
So I would
I am a perl user trying to convert to php
how would i turn this perl into php?
use CGI;
$name = param(name);
$address = param(address);
$phone = param(phone);
@required = qw( name address phone );
foreach $key($required)
{
if (!$$key) { out(You left one empty.); }
}
??
if(!(isset($name) isset($address) isset($phone)) {
echo You left one empty.;
}
On Tue, 20 Nov 2001 [EMAIL PROTECTED] wrote:
I am a perl user trying to convert to php
how would i turn this perl into php?
use CGI;
$name = param(name);
$address = param(address);
$phone =
Try something like this:
while (list($name, $value) = each($HTTP_POST_VARS)) {
if ((strlen($value) 1) ($name == name || $name ==
address || $name == phone)) {
$error .= You left $name empty br;
}
}
if ($error) {
echo $error;
}
That's one way to do
Beauty!
/mt
At 02:08 PM 11/20/2001 -0800, Rasmus Lerdorf wrote:
if(!(isset($name) isset($address) isset($phone)) {
echo You left one empty.;
}
On Tue, 20 Nov 2001 [EMAIL PROTECTED] wrote:
I am a perl user trying to convert to php
how would i turn this perl into php?
use CGI;
Message -
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, November 20, 2001 2:21 PM
Subject: Re: Re: [PHP] How do I convert from perl to php?
So I would have to write a seperate if condition for each form input field
i wanted to require? that doesn't make for a very dynamic script
?
$required = array('name','address','phone');
$has_empty = 0;
foreach ($required as $var) {
if (!is_set($$var)) $has_empty = 1;
}
if ($has_empty) print 'You left one empty.';
?
You don't need to use the $has_empty variable, but I thought it would be
better to just display the
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