[PHP] include from another URL

Hi there, I'm new to these groups so forgive me if I'm asking at the wrong place (tell me where then :) Ok, I'm not PHP guru but I need to create a simple script that would do this: Include a content from another URL into the current output. I have done something like this: -- code start ht

Re: [PHP] Include from another URL?

* Thus wrote Nik ([EMAIL PROTECTED]): > Include a content from another URL into the current output. I have done > something like > this: > > -- code start > include 'http://myotherurl.com:8080'; > ?> > -- code end You want to use readfile() instead. http://php.net/readfile Curt -- "

Re: [PHP] Include from another URL?

Great! Worked as expected. Thanks. Now it is time to ask how do I handle form (HTTP POST request) data into the URL. Can the same fopen() work as well? Thanks, Nik "Chris Boget" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > > Include a content from another URL into the current out

Re: [PHP] Include from another URL?

> Include a content from another URL into the current output. I have done > something like this: Look into the fopen() function. I also believe that the file() function can also take a URL, but I'm not sure. Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://

[PHP] Include from another URL?

Hi there, I'm new to these groups so forgive me if I'm asking at the wrong place (tell me where then :) Ok, I'm not PHP guru but I need to create a simple script that would do this: Include a content from another URL into the current output. I have done something like this: -- code start htt