Hello,
1)
Ok, with mysqli, to fetch data from a database to a select drop down list, we
would do something like this right? :
?php
$result = $mysqli-query(SELECT id_cliente, nome_cliente FROM cliente);
echo select id='listacliente' name='listacliente';
while($row =
On Sun, Apr 5, 2009 at 10:08 PM, MEM tal...@gmail.com wrote:
Hello,
1)
Ok, with mysqli, to fetch data from a database to a select drop down list,
we would do something like this right? :
?php
$result = $mysqli-query(SELECT id_cliente, nome_cliente FROM cliente);
echo select
why did you forget to use the debugging functions :
print_r()
and var_dump() for the results?
So, you'll get some idea beforehand of posting the problem here. I am
looking at the code in a hurry so I cant help you much right away.
Lenin
http://www.twitter.com/nine_L www.twitter.com/nine_L
Because I’ve never debug on my entire life of programming (2 months). :D
In the meanwhile, I will search how to debug using print_r and var_dump.
ROFL ha hahaha
echo 'pre', print_r($array),'/pre'; // here pre is used to
keep the way its outputed in HTML
echo 'pre',
On Behalf Of 9el
On Sun, Apr 5, 2009 at 10:08 PM, MEM mailto:tal...@gmail.com
tal...@gmail.com wrote:
Hello,
1)
Ok, with mysqli, to fetch data from a database to a select drop down list,
we would do something like this right? :
?php
$result = $mysqli-query(SELECT id_cliente, nome_cliente
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