I was reading through the PHP manual and got to the section on constructors. <snip> class A { function A() { echo "I am the constructor of A.<br>\n"; } function B() { echo "I am a regular function named B in class A.<br>\n"; echo "I am not a constructor in A.<br>\n"; } } class B extends A { function C() { echo "I am a regular function.<br>\n"; } } // This will call B() as a constructor. $b = new B; In PHP 3, the function B() in class A will suddenly become a constructor in class B, although it was never intended to be. The rule in PHP 3 is: 'A constructor is a function of the same name as the class.'. PHP 3 does not care if the function is being defined in class B, or if it has been inherited. This is fixed in PHP 4 by modifying the rule to: 'A constructor is a function of the same name as the class it is being defined in.'. Thus in PHP 4, the class B would have no constructor function of its own and the constructor of the base class would have been called, printing 'I am the constructor of A.<br>'. </snip> It says that when a new class B was made, that the class B would have no constructor, because the function B() was in the base class. Instead the class B was supposed to derive it's constructor from class A and output 'I am the constructor of A.<br>' When I tried this script, this did not happen and the Function B() was called as the constructor of class B, even though the function was in the base class...can anyone help to clear up this matter????? thanx -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]