Wan I insatiate an object I want to pass a database resource that can be
used throughout the object. The below code should indicate what I want but
I get the error mysql_query(): supplied argument is not a valid MySQL-Link
resource. I guess this is because $this-$db = $db is wrong.
Ben
* Thus wrote Ben Edwards ([EMAIL PROTECTED]):
Wan I insatiate an object I want to pass a database resource that can be
used throughout the object. The below code should indicate what I want but
I get the error mysql_query(): supplied argument is not a valid MySQL-Link
resource. I guess
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