$your_timestamp+=gmmktime(0,0,0,1,1,1972);
Regards,
Andrey
- Original Message -
From: Dave Carrera [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, March 18, 2002 10:11 AM
Subject: [PHP-DB] How to add 2 years to todays date ?
Hi All
I think the subject line says it all.
At 10:19 18.03.02 +0200, Andrey Hristov [EMAIL PROTECTED] wrote:
$your_timestamp+=gmmktime(0,0,0,1,1,1972);
Try:
$your_timestamp =
mktime(date(H),date(i),date(s),date(m),date(d),(date(Y)+2));
Is there anything why this would not work?
Martin
Isn't the hack with gmmktime() faster? It is clean if the code knows what is 1,1,1970
and how Unixtime is measured.
Andrey
- Original Message -
From: Martin Schichl [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, March 18, 2002 10:29 AM
Subject: Re: [PHP] Re: [PHP-DB] How to add
At 10:35 18.03.02 +0200, Andrey wrote:
Isn't the hack with gmmktime() faster? It is clean if the code knows
what is 1,1,1970 and how Unixtime is measured.
Seems that you'r right, as
mktime(date(H),date(i),date(s),date(m),date(d),(date(Y)+2))
calls six times the function date ...
Martin
Hi
A variation
echo date(d/m/Y,strtotime(+2 years))
Tom
At 06:29 PM 18/03/2002, Martin Schichl wrote:
At 10:19 18.03.02 +0200, Andrey Hristov [EMAIL PROTECTED] wrote:
$your_timestamp+=gmmktime(0,0,0,1,1,1972);
Try:
$your_timestamp =
-Original Message-
From: Andrey Hristov [mailto:[EMAIL PROTECTED]]
Sent: 18 March 2002 08:20
$your_timestamp+=gmmktime(0,0,0,1,1,1972);
Well, that depends on your definition of year -- the problem here is that it makes
no allowances for leap years, so (for example) 2-mar-2003
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