i found this a bit confusing, why were you putting $$ infront of a variable instead of just $?
-- -------------------------------------------------------------->> Jasper Howard :: Database Administration Velocity7 1.530.470.9292 http://www.Velocity7.com/ <<-------------------------------------------------------------- "Neil" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > > > Not sure if its me or the configuration of PHP > > I am trying to get the value of a variable, a variable variable > > ie > > // From Form > $name = "My Name"; > ----------------------------------- > > // from a list of values in a file > $var="name"; > > $value=$$var; > i// I thought I could do something as simple as this to get the correct > value "My Name" into $value. > > print " $value "; > // should print "My Name", I zip. > > I have played around with this bit of code from operators part of the > manual and this does not appear to work, well for me at least. > > $foo = "test"; > $$bar = "this is"; > > echo "${$bar} $foo"; // prints "this is test" > Note: it is the same as > echo "$test $foo"; // ***** for me it only prints out "test" > > > Any Ideas > > Cheers > > Neil > > > > > > > > > > > > Regards > > Chester Cairns > ------------------------------------------------------------- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
