if the output of graph.php is a URL, your code should work. <img src="/images/mypic.jpg">
if graph outputs the image itself, you have to do it a bit different: in the html it should look like: <img src="graph.php?..."> and graph.php should do something like: header("Content-Type: image/gif"); echo $imagecontent; Hope that helps Michael "Moschitz Martin" <[EMAIL PROTECTED]> schrieb im Newsbeitrag [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > What is wrong with the following statement? The Picture which is generated > in graf.php is not displayed. > > echo "<img src="; > include(" graf.php "); > echo ">"; > > thanxs > martin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php