when I echo menu($id) I get the current page's title.
How do I print it's peers and it's single parent?
You will need a second query to ask for all the children of the parent:
$peer_query = select id as child_id, title from meta_data where pid =
$pid;
$peers = mysql_query($query) or
Thx.
I a bit of a n00b so don't always understand.
I is a lot clearer now thank you
--
JJ Harrison
[EMAIL PROTECTED]
www.tececo.com
Richard Lynch [EMAIL PROTECTED] wrote in message
news:20020703212954.BFUU903.sccrmhc03.attbi.com@[192.168.1.103]...
when I echo menu($id) I get the current
Thanks for that info.
I am still a bit new to programming/PHP to fully grasp that but I am sure I
will in time.
*anyway*
when I echo menu($id) I get the current page's title.
How do I print it's peers and it's single parent?
--
JJ Harrison
[EMAIL PROTECTED]
www.tececo.com
P.S. I originally
I have a table with id, pid(parent), title and page_name(url) fields.
The vars provided to the script are the current page's title, id and
pid(parent)
You can look up the parent and in the database, so it's not horribly
important that those be provided.
*UNLESS* you have a heterarchy, and not
Hi Richard:
Nice to have you back on the list. I've noticed your replies are not
winding up back in the threads due to the Reference header not being set
by Outlook.
While this isn't going to cause the end of the world, it'd be nice if they
were there.
Enjoy,
--Dan
--
PHP
On Mon, Jul 01, 2002 at 08:00:39PM -0400, Analysis Solutions wrote:
Hi Richard:
Oops. Meant to reply directly to Ricahrd. Sorry 'bout that.
--Dan
--
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