Re: [PHP] always last

: [PHP] always last Hi, I need a little bit of help. My variable $team in the option block is always set to the last variable that is readI would like it to contain the option that the user clicks.Please help me! My Select works properly ... $result = @mysql_query

Re: [PHP] always last

Van:Andrey Hristov [EMAIL PROTECTED] Aan:[EMAIL PROTECTED] Datum verz. Thu, 23 Aug 2001 18:33:53 +0300 Onderwerp: Re: [PHP] always last Use a counter when fetching from the DB if you use while the $counter=0; while(list

[PHP] always last

Hi, I need a little bit of help. My variable $team in the option block is always set to the last variable that is readI would like it to contain the option that the user clicks.Please help me! My Select works properly ... $result = @mysql_query($sql,$connection) or die(Couldn't

Re: [PHP] always last

On 23 Aug 01, at 11:10, Jeremy Morano wrote: $result = @mysql_query($sql,$connection) or die(Couldn't execute query.); while ($row = mysql_fetch_array($result)) { $uid = $row['uid'] $team = $row['team']; if ($uid == $row['uid']) { $option_block .= option value=\$uid\