, the first character in a file name is lost
using the PHP "basename" function. Below is an excerpt from a Horde
webmail server's log that shows the error.
More reading can be found on the Horde list here:
http://marc.info/?l=horde&m=124653708009981&w=2
and here
On Thursday, April 25, 2002, at 09:54 AM, Matt Friedman wrote:
> Replace the "\" with "/" using str_replace or some such function before
> using basename. Windows will handle either kind of path. Linux does not
> know the "\" as a file path separator. It only knows "/"
Just make sure that you
ROBERT MCPEAK <[EMAIL PROTECTED]> wrote:
> In other words:
>
> basename(/usr/blah/doh/yuck/wow/abigfile.html)
>
> resolves to : abigfile.html
>
> but
>
> basename(adirectory\onawindowsbox\abigfile.html)
>
> does not resovle to abigfile.html.
>
> Does anybody have a workaround for this?
Conv
ia.com
-Original Message-
From: ROBERT MCPEAK [mailto:[EMAIL PROTECTED]]
Sent: Thursday April 25, 2002 9:41 AM
To: [EMAIL PROTECTED]
Subject: [PHP] basename unix/windows
I'm running php on linux and wish to use basename() to get the file name
from a windows path.
basename() on our
ROBERT MCPEAK wrote:
> basename(/usr/blah/doh/yuck/wow/abigfile.html)
>
> resolves to : abigfile.html
>
> but
>
> basename(adirectory\onawindowsbox\abigfile.html)
>
> does not resovle to abigfile.html.
>
> Does anybody have a workaround for this?
>
What about str_replace()?
--
PHP General
I'm running php on linux and wish to use basename() to get the file name
from a windows path.
basename() on our linux/php box can't seem to cope with the use of
backslash (\) in the Windows paths I'm feeding it.
In other words:
basename(/usr/blah/doh/yuck/wow/abigfile.html)
resolves to : abig
Oh yes, I dont like warnings. Thanks for pointing that out
Renze Munnik wrote:
> On Mon, Aug 20, 2001 at 03:42:34PM -0400, Gerard Samuel wrote:
>
>>$file = basename ($path);
>>$file = $file.php3;
>>
>>
>
> You might want to consider using,
>
> $file = basename ($path);
> $file = "$file.php3";
On Mon, Aug 20, 2001 at 03:42:34PM -0400, Gerard Samuel wrote:
> $file = basename ($path);
> $file = $file.php3;
>
You might want to consider using,
$file = basename ($path);
$file = "$file.php3"; // <-- !
instead, if you don't like warnings.
$file = $file.php3
isn't the way to do
$file = basename ($path);
$file = $file.php3;
Jeremy Morano wrote:
> Hello,
>
> Can someone please show me how to use basename() correctly?
> This is what I am doing:
>
> $file = basename ($path);
> $file = basename ($path,".php3");
>
> This is the error I'm gettig:
>
> Warning: Wrong paramet
Hello,
Can someone please show me how to use basename() correctly?
This is what I am doing:
$file = basename ($path);
$file = basename ($path,".php3");
This is the error I'm gettig:
Warning: Wrong parameter count for basename() in
/home/virtual/ppcu/home/httpd/html/jeremy/stats4.php on line 43
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