Re: [PHP] date -> day

2001-06-26 Thread David Robley
On Tue, 26 Jun 2001 00:28, Tyler Longren wrote: > Hello, > > I have something like this: > $Month = "6"; > $Year = "2001"; > $Date = "1"; > > Is there any relatively simple way to get the day out of that? For > example, the day for 6-1-2001 would be Friday. > > Thanks, > Tyler If that info comes

Re: [PHP] date -> day

2001-06-26 Thread Gyozo Papp
date('l', mktime(0,0,0, $Month, $Day, $Year)); - Original Message - From: "Tyler Longren" <[EMAIL PROTECTED]> To: "php-general" <[EMAIL PROTECTED]> Sent: 2001. június 25. 16:58 Subject: [PHP] date -> day > Hello, > > I hav

Re: [PHP] date -> day

2001-06-26 Thread infoz
ECTED]> Sent: Monday, June 25, 2001 10:58 AM Subject: [PHP] date -> day > Hello, > > I have something like this: > $Month = "6"; > $Year = "2001"; > $Date = "1"; > > Is there any relatively simple way to get the day out of that? For ex

Re: [PHP] date -> day

2001-06-25 Thread Philip Olson
mktime can be pretty useful : $year = 2001; $month = 6; $day = 1; print date('l',mktime(0,0,0,$month,$day,$year)); as it creates a unix timestamp, and date() appreciates that. Regards, Philip On Mon, 25 Jun 2001, Tyler Longren wrote: > Hello, > > I have something like this: >

[PHP] date -> day

2001-06-25 Thread Tyler Longren
Hello, I have something like this: $Month = "6"; $Year = "2001"; $Date = "1"; Is there any relatively simple way to get the day out of that? For example, the day for 6-1-2001 would be Friday. Thanks, Tyler -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROT