How do I check a string for it to only contain numbers?
if(!ereg(([0-9]+),$string)){
print It contains characters other than numbers;
}else{
print Only numbers;
}
Can anyone give some feedback...
regards,
Bart
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Subject: [PHP] ereg-digits only...
How do I check a string for it to only contain numbers?
if(!ereg(([0-9]+),$string)){
print It contains characters other than numbers;
}else
if ((int($string)==($string)) ($string0)) {then positive integer}
not sure exactly, but try
Why not use the RE's? I usually use preg_* so I'll give the example
using these...
if (preg_match (/^\d+$/, $string)) {
print (Yep... Only digits.);
} else {
prnt (Noop! There are non-digit
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Cc: PHP
Subject: Re: [PHP] ereg-digits only...
if ((int($string)==($string)) ($string0)) {then positive integer}
not sure exactly, but try
Valentin Petruchek (aki Zliy Pes)
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http://zliypes.com.ua
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From: Daniel Kushner [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Cc: PHP [EMAIL PROTECTED]
Sent: Tuesday, February 12, 2002 4:00 PM
Subject: RE: [PHP] ereg-digits only...
That wouldn't work!
1) You meant to write: if (((int)$string==$string
On Tue, 2002-02-12 at 03:04, B. Verbeek wrote:
How do I check a string for it to only contain numbers?
if(!ereg(([0-9]+),$string)){
print It contains characters other than numbers;
}else{
print Only numbers;
}
Can anyone give some feedback...
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