Hi Kevin,
I find it a bit awkward to mix variables and arrays in a pseudo
array. But I guess you have reasons...
Anyhow, maybe this is what you want:
$variable1=one;
$variable2=two;
$variable3 = array();
$variable3[0]=three;
$variable4 = array();
$variable4[0]=four;
$j=1;
Hoping someone can help me with this. Below I have an example of what
I'm trying to accomplish.
Bottom line.. I need to print out $variable3[0] and $variable4[0]
and my problem is that I'm trying to generate the variable name. I can
get this to work with $variable1 and $variable2 which are not
2002 13:38
Para: php-general
Asunto: [PHP] generating variable names
Hoping someone can help me with this. Below I have an example of what
I'm trying to accomplish.
Bottom line.. I need to print out $variable3[0] and $variable4[0] and my
problem is that I'm trying to generate the variable name. I
You can allso do like this:
$i = 1;
${test. $i} = 123;
echo $test1;
___
Marcus Rasmussen
[EMAIL PROTECTED]
On 21-09-01 at 11:21 _lallous wrote:
you can always use eval to create a variable too!
?
$i = 1;
eval(\$test$i=123;);
echo $test1;
?
Neil Freeman
Hi there,
How do I generate variable names 'on the fly'? I wish to have variable
names along the lines of $genre_category_1, $genre_category_2,
$genre_category_3 etc.
Ideally it would be along the lines of this...
###
$current_field_number = 1;
$genre_number_fields = 7;
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