* Thus wrote Tyler Longren ([EMAIL PROTECTED]):
hmmm...perhaps that was it. When I had this issue before, someone told me
to check mysql_affected_rows() when using issuing an UPDATE query. I'll
give that a shot.
Correct, mysql_affected_rows() on a query that doesn't return rows
(insert,
From: Tyler Longren [EMAIL PROTECTED]
I'm running an UPDATE query on my table. After executing the query, I
check
mysql_error() to see if there's any errors:
if (mysql_error() == ) {
// success
}
else {
// failure
}
mysql_error() is always empty even if the query didn't succeed.
PROTECTED]
Sent: Wednesday, August 06, 2003 3:35 PM
Subject: Re: [PHP] mysql_error() problem?
From: Tyler Longren [EMAIL PROTECTED]
I'm running an UPDATE query on my table. After executing the query, I
check
mysql_error() to see if there's any errors:
if (mysql_error
Hi,
I'm running an UPDATE query on my table. After executing the query, I check
mysql_error() to see if there's any errors:
if (mysql_error() == ) {
// success
}
else {
// failure
}
mysql_error() is always empty even if the query didn't succeed. So it
always thinks it succeeds. I
I am using the below function (error_db) witch is called thus:-
function query_db( $sql, $db ) {
$result = mysql_query( $sql, $db ) or
error_db( $sql, $db );
return $result;
}
But $sqlerr is always blank (it is set with '$sqlerr = mysql_error( $db
);'). Any idea why?
Ben
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