Re: [PHP] putting variables in a variable

2009-07-21 Thread Mark Kelly
Ross, If I understand correctly what you want to do, you're almost there... You need: $myimage1 = image1.jpg; $myimage2 = image2.jpg; $myimage3 = image3.jpg; $body .= table tr tdimg src=\$myimage1\/td /tr tr tdimg src=\$myimage2\/td /tr tr tdimg src=\$myimage3\/td /tr

Re: [PHP] putting variables in a variable

2008-04-24 Thread Yannick Warnier
Le lundi 28 mars 2011 à 12:06 +0100, Hulf a écrit : Hi, I am making and HTML email. I have 3 images to put in. Currently I have $body .= table tr tdimg src=\image1.jpg\/td /tr tr td/td /tr /table ; ideally I would like to have $myimage1 = image1.jpg;

Re: [PHP] putting variables in a variable

2008-04-19 Thread revDAVE
On 3/28/2011 4:06 AM, Hulf [EMAIL PROTECTED] wrote: Hi, I am making and HTML email. I have 3 images to put in. Currently I have $body .= table tr tdimg src=\image1.jpg\/td /tr tr td/td /tr /table ; ideally I would like to have $myimage1 = image1.jpg;

[PHP] putting variables in a variable

2008-03-28 Thread Hulf
Hi, I am making and HTML email. I have 3 images to put in. Currently I have $body .= table tr tdimg src=\image1.jpg\/td /tr tr td/td /tr /table ; ideally I would like to have $myimage1 = image1.jpg; $myimage2 = image2.jpg; $myimage3 = image3.jpg; and put them into the HTML

Re: [PHP] putting variables in a variable

2008-03-28 Thread Daniel Brown
On Mon, Mar 28, 2011 at 7:06 AM, Hulf [EMAIL PROTECTED] wrote: Hi, I am making and HTML email. I have 3 images to put in. Currently I have $body .= table tr tdimg src=\image1.jpg\/td /tr tr td/td /tr /table ; ideally I would like to have $myimage1 =

Re: [PHP] putting variables in a variable

2008-03-28 Thread Wolf
Hulf [EMAIL PROTECTED] wrote: Hi, I am making and HTML email. I have 3 images to put in. Currently I have $body .= table tr tdimg src=\image1.jpg\/td /tr tr td/td /tr /table ; ideally I would like to have $myimage1 = image1.jpg; $myimage2 =