I've got the following bit of code to work in showing the actual PHP file source code, but it doesn't show include() or require() files and I'd like it to..
-------------- source.php -------------- if(strlen($php)>0){ $php = $DOCUMENT_ROOT . $php; if (ereg("(\.php)$",$php) && !ereg("\/\.\.", $php)){ require("head.php"); echo "<font class=\"source\">\n\n"; show_source("$php"); echo "\n\n</font>\n"; require("foot.php"); } else{ require("head.php"); echo "<font class=\"s\">\n"; echo " There's been an error..\n"; echo "</font>\n"; require("foot.php"); } exit; } ---------------------------- I've checked the manual and google, but I'm not too sure the keywords I'd used were correct as I didn't find any results.. I looked at highlight_file() but it would seem to cause the same output as show_source() neglecting to include the php code within head.php and foot.php.. Is there a function I'm missing that would somehow allow me to add the head.php and foot.php code within the source code output page? Will I need to add something to the head.php and foot.php files to have them included? I'm a bit of a php newbie, so sorry if my terminology isn't correct.. TIA.. Take care.. peace.. eriol -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php