[PHP] variable function call (Re: [PHP] unset a function?)

2002-01-31 Thread Bas Jobsen
Hello, Thanks all. I will rename the second function. Now if have: if($wat==naam)$temp=make_naam($this); else if($wat==anderenaam)$temp=make_anderenaam($this); //etc.. But i would prefer something like $temp=make_$wat($this); How can i do this? Tnx, Bas -- PHP General Mailing List

Re: [PHP] variable function call (Re: [PHP] unset a function?)

2002-01-31 Thread Jeff Van Campen
Hey Bas, BVBut i would prefer something like BV$temp=make_$wat($this); I think you might want something along these lines: eval(make_$wat($this);); HTH -jeff -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL

Re: [PHP] variable function call (Re: [PHP] unset a function?)

2002-01-31 Thread bvr
Hoi Bas, $func = make_ . $wat; $temp = $$func($this); bvr. On Thu, 31 Jan 2002 11:55:12 +0100, Bas Jobsen wrote: Hello, Thanks all. I will rename the second function. Now if have: if($wat==naam)$temp=make_naam($this); else if($wat==anderenaam)$temp=make_anderenaam($this); //etc.. But

Re: [PHP] variable function call (Re: [PHP] unset a function?)

2002-01-31 Thread Lars Torben Wilson
On Thu, 2002-01-31 at 02:55, Bas Jobsen wrote: Hello, Thanks all. I will rename the second function. Now if have: if($wat==naam)$temp=make_naam($this); else if($wat==anderenaam)$temp=make_anderenaam($this); //etc.. But i would prefer something like $temp=make_$wat($this); How

Re: [PHP] variable function call (Re: [PHP] unset a function?)

2002-01-31 Thread Bas Jobsen
Hello, $func = make_ . $wat; $temp = $$func($this); I think one $. $func = make_ . $wat; $temp = $func($this); will work Bas Op donderdag 31 januari 2002 12:17, schreef u: Hoi Bas, $func = make_ . $wat; $temp = $$func($this); bvr. On Thu, 31 Jan 2002 11:55:12 +0100, Bas Jobsen