On Fri, 21 Aug 2009 15:16:11 +0200, ak...@telkomsa.net (Arno Kuhl) wrote:
-Original Message-
From: Clancy [mailto:clanc...@cybec.com.au]
Sent: 21 August 2009 01:26 PM
To: php-general@lists.php.net
Subject: [PHP] Invoking functions stored in a separate directory?
I am developing an idea
Clancy wrote:
$ok = include (HOST_PATH.'/Halla.php');
Because you are assigning the result of the include to a variable. Try
include (HOST_PATH.'/Halla.php');
and it will work as you expect. And similarly for
define ('HOST_PATH','../Engine');
Cheers
--
David Robley
Dynamic linking
On Sat, 22 Aug 2009 20:37:17 +0930, robl...@aapt.net.au (David Robley) wrote:
Clancy wrote:
$ok = include (HOST_PATH.'/Halla.php');
Because you are assigning the result of the include to a variable. Try
include (HOST_PATH.'/Halla.php');
and it will work as you expect. And similarly for
-Original Message-
From: Clancy [mailto:clanc...@cybec.com.au]
Sent: 21 August 2009 01:26 PM
To: php-general@lists.php.net
Subject: [PHP] Invoking functions stored in a separate directory?
I am developing an idea for a website engine which can be shared between
several different
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