[snip]
I have an application that allows the users to input a formula:
(Width*Height)/144
This formula gets updated with a part's specific width height and
actually returns:
(36.0*58.0)/144
I use preg_replace to replace Width and Height with values from the
following array:
[Width] =
Try;
$foo = preg_replace($find,$replace,$partFormula);
return $foo
Unfortunately no. I also tried making the formula look like this:
?php (36.0*58.0)/144 ?
and returning it with:
eval('?' . $a . '?php ');
Mike
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[snip]
Try;
$foo = preg_replace($find,$replace,$partFormula);
return $foo
Unfortunately no. I also tried making the formula look like this:
?php (36.0*58.0)/144 ?
and returning it with:
eval('?' . $a . '?php ');
[/snip]
Let's do an experiment. Place these two lines of code in a page,
Let's do an experiment. Place these two lines of code in a page, then load
it in a browser;
?php
$foo = (36.0*58.0)/144;
echo $foo;
?
works fine for me. If you change
?php (36.0*58.0)/144 ?
to
?php echo (36.0*58.0)/144; ?
Yep, that does work. Thanks Jay.
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