Paul Jinks wrote:
Hi all
I've been asked to put simple database interactivity on an academic
site. They want users to enter a few details of their projects so other
researchers can search and compare funding etc. How difficult can that
be, I thought
I've built the database in MySQL and
Hi Paul,
Why you are closing your connection before finishing your work on
the database?
Zareef Ahmed
- Original Message -
From: Paul Jinks [EMAIL PROTECTED]
To: php-general@lists.php.net
Sent: Friday, December 09, 2005 6:50 AM
Subject: [PHP] PHP/MySql noob falls at first
Hi
[snip]
?
while($ouput_row = mysql_fetch_array($result)) {
?
[/snip]
Try:
while($ouput_row = mysql_fetch_array($result, MYSQL_ASSOC))
[snip]
?=$output_row[projTitle]?br /
[/snip]
You have missed the ; (semicolon) after [projTitle] also
Dan
-Original Message-
From: Paul
Paul Jinks wrote:
snip
?
while($ouput_row = mysql_fetch_array($result)) {
?
?=$output_row[projTitle]?br /
snip
Paul - is this the actual code that you are using? - because you have a
typo in your while statement - $ouput_row instead of $output_row - means
that when you
Paul Jinks wrote:
Rory McKinley wrote:
Paul Jinks wrote:
snip
?
while($ouput_row = mysql_fetch_array($result)) {
?
?=$output_row[projTitle]?br /
snip
Paul - is this the actual code that you are using? - because you have a
typo in your while statement - $ouput_row
I would hate to see a time clock that tabulated how many hours I
wasted with typos and stupid things like that.
On 12/9/05, Rory McKinley [EMAIL PROTECTED] wrote:
Paul Jinks wrote:
Rory McKinley wrote:
Paul Jinks wrote:
snip
?
while($ouput_row =
For future reference, during testing, you can set your error reporting
levels ( i think) in php.ini to output a notice regarding a variable
that does not exist - would have helped you spot the error! I normally
use the Zend debugger which does quite a good job of telling me that I
am an
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