Look for errors in the line above this one. PHP doesn't know what SQL is...it's just a
string to PHP.
---John Holmes...
- Original Message -
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, May 29, 2002 9:03 AM
Subject: [PHP] Parse Error(newbie)
I get a
[EMAIL PROTECTED] wrote:
$query = SELECT * FROM news ORDER BY id DESC LIMIT 1;
I believe that it is an error in the SQL statement
Nope, looks fine. Show us the previous few lines, the error is probably in
those somewhere.
--
Stuart
--
PHP General Mailing List (http://www.php.net/)
To
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I get a parse error on this line
$query = SELECT * FROM news ORDER BY id DESC LIMIT 1;
I believe that it is an error in the SQL statement
Nothing wrong with that. Let's have the whole error msg and
-
From: Nick Wilson [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, May 29, 2002 11:08 PM
Subject: Re: [PHP] Parse Error(newbie)
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* and then [EMAIL PROTECTED] declared
I get a parse error on this line
$query = SELECT * FROM
On Wednesday 29 May 2002 21:13, [EMAIL PROTECTED] wrote:
Here is the function:
function print_new_story(){
$query = SELECT * FROM news ORDER BY id DESC LIMIT 1;
$result = mysql_query($query);
$num_results = mysql_num_rows($result);
for ($i=0; $i $num_results; $i++)
{
$row =
: Jason Wong [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, May 29, 2002 11:11 PM
Subject: Re: [PHP] Parse Error(newbie)
On Wednesday 29 May 2002 21:13, [EMAIL PROTECTED] wrote:
Here is the function:
function print_new_story(){
$query = SELECT * FROM news ORDER BY id DESC LIMIT 1
mysql_query(delete from conf_event where time ( time() );
You're missing the ending there.
Niklas
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: 29. toukokuuta 2002 16:20
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Parse Error(newbie)
Line 81 is $query
]
Subject: Re: [PHP] Parse Error(newbie)
Line 81 is $query.
I showed it in my first email.
I suspect this line is the one causing the trouble(It is about four
lines above the start of the function and is the only previous PHP
statement) mysql_query(delete from conf_event where time ( time
Notepad at the moment as I can't change the settings of my computer due to
lack of privilages
- Original Message -
From: Jason Wong [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, May 29, 2002 11:26 PM
Subject: Re: [PHP] Parse Error(newbie)
On Wednesday 29 May 2002 21:22
On Wednesday 29 May 2002 21:45, [EMAIL PROTECTED] wrote:
Notepad at the moment as I can't change the settings of my computer due to
lack of privilages
You have my sympathy :)
--
Jason Wong - Gremlins Associates - www.gremlins.com.hk
Open Source Software Systems Integrators
* Web Design
On Mon, 27 May 2002 [EMAIL PROTECTED] wrote:
I know it is probably something obvious but the following gives me a
parse error and as a newbie I am having trouble locating it.
$query = select * from news WHERE id = $_get['id'];
A lot of people have answered this already, but just for a
, 2002 2:18 AM
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Parse Error(Newbie)
On Mon, 27 May 2002 [EMAIL PROTECTED] wrote:
I know it is probably something obvious but the following gives me a
parse error and as a newbie I am having trouble locating it.
$query = select
try this:
$query = select * from news WHERE id = '$_get['id']';
the double quote right before the $ is ending the string, from that point
on everything is an error.
Matt
On Mon, 27 May 2002 [EMAIL PROTECTED] wrote:
I know it is probably something obvious but the following gives me a parse
Another thing you may want to try is the following line:
$query = select * from news WHERE id = ' . $_get['id'] . ';
Matt
On Mon, 27 May 2002 [EMAIL PROTECTED] wrote:
I know it is probably something obvious but the following gives me a parse error and
as a newbie I am having trouble
$query = select * from news WHERE id = $_get['id'];
you've got quotes within quotes - either change the inner quotes to single
quotes, or escape them
$query = select * from news WHERE id = '$_get[id]';
or
$query = select * from news WHERE id = \$_get['id']\;
-Original Message-
From:
can you show us the lines above that line? say the previous 2 lines?.. also
depending on what server your on you might want to try
$query = SELECT * FROM news WHERE id = $_get['id'];
but that line is ok ... with parse errors it's often, well i've found this
any way, that it's the line above the
-Original Message-
I know it is probably something obvious but the following gives me a
parse error and as a newbie I am having trouble locating it.
$query = select * from news WHERE id = $_get['id'];
-Original Message-
Any time you end up with two characters together is a
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I get a parse error on line 114 can anyone see the problem?
Sorry if it is something obvious :}
for ($i=0; $i $num_results; $i++)
110. {
111. $row = mysql_fetch_array($result);
112. echo 'a
why now just write:
for ($i=0; $i $num_results; $i++) {
$row = mysql_fetch_array($result);
echo a href=\.$row['url'].\link text/a;
-Original Message-
From: Nick Wilson [mailto:[EMAIL PROTECTED]]
Sent: 23 May 2002 12:28 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Parse Error
On jeudi, mai 23, 2002, at 01:27 , Nick Wilson wrote:
I get a parse error on line 114 can anyone see the problem?
Sorry if it is something obvious :}
for ($i=0; $i $num_results; $i++)
110. {
111. $row = mysql_fetch_array($result);
112. echo 'a href=';
113. echo $row['url'];
114. echo
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