Hi,
imagejpeg($dst_img);
This actually outputs the image, so your result is not unexpected.
Try this instead:
imagejpeg($dst_img, /path/and/filename/to/newfile.jpg);
Regards
Joakim Andersson
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Hi,
Output the correct headers before you output the image
ie
header(Content-type: image/jpeg);
imagejpeg($dst_img, '', 50);
Remove all print statements from this code. You cannot output anything but
the headers and the image itself.
Use imagecopyresampled if you can. It gives much better
On Monday 24 June 2002 18:57, Phil Ewington wrote:
Hi,
I am trying to copy and resize an image using imagecopyresized() and
cannot seem to crack it. Below is the code I am using, can anyone tell
me why I keep getting and invalid image resource warning and is this
the src or dest parameter
Don't know if this helps, but the following works on my system.
Hugh
?php
$picture=../photos/$userfile_name;
$size=getimagesize($picture);
$height=$size[1];
$width=$size[0];
$max=200; // maximum dimension
if ($height$width)
{
$nheight=$max;
$nwidth=$width/($height/$max);
}
else
{
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