hi there,
Have u tried this...
?php
$string = 'foo';
print preg_replace(/^\s$string\s/,' ','bfoo foo foobar.') . \n;
print eregi_replace(^[[:space:]].$string.[[:space:]],' ','bfoo
foo alfoobar.') . \n;
?
This is not working properly..
Output I got is
bfoo foo foobar.
* Desikan ([EMAIL PROTECTED]) [Feb 09. 2002 03:33]:
hi there,
Backatcha,
Have u tried this...
?php
$string = 'foo';
print preg_replace(/^\s$string\s/,' ','bfoo foo foobar.') . \n;
print eregi_replace(^[[:space:]].$string.[[:space:]],' ','bfoo
foo alfoobar.') . \n;
?
* Desikan ([EMAIL PROTECTED]) [Feb 09. 2002 02:17]:
Hi there,
Hi,
Please help me out in the following...
?php
$is='is';
echo eregi_replace( .$is. , ,This is a test string which contains
is in dismissal);
?
Actually I want to replace is alone from the string and not all the
words
* Desikan ([EMAIL PROTECTED]) [Feb 09. 2002 02:52]:
hi Thanks,
Sure,
But I want to do thr replace operation for
regular exprerssion and not exactly for the string alone...
like ^and$,a*, etc
?php
$string = 'foo';
print preg_replace(/^\s$string\s/,' ',' foo foobar.') .
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