I must be brain dead today since I can't get my syntax correct.
Simple MySQL query to return a list of last_name. No problem. Each
last name returned needs to be assigned to a unique variable like
name1, name2, name3, etc.
How about $names[1], $names[2], $names[3]?
JM
--
PHP
I must be brain dead today since I can't get my syntax correct.
Simple MySQL query to return a list of last_name. No problem. Each
last name returned needs to be assigned to a unique variable like
name1, name2, name3, etc.
How about $names[1], $names[2], $names[3]?
JM
To
$x = 0;
my_name_array = array();
While($row=mysql_fetch_array($result))
{
my_name_array[$x] = $row[last_name];
}
Jeremy Schreckhise
-Original Message-
From: Albert Padley [mailto:[EMAIL PROTECTED]
Sent: Thursday, February 02, 2006 1:15 PM
To: php-general@lists.php.net
Oops you might want to increment $x++ after the assignment.
-Original Message-
From: Programmer [mailto:[EMAIL PROTECTED]
Sent: Thursday, February 02, 2006 1:49 PM
To: 'Albert Padley'; php-general@lists.php.net
Subject: RE: [PHP] Unique Names for Variable in Loop
$x = 0
Yes, that's it. Thanks for the swift kick.
AP
On Feb 2, 2006, at 12:37 PM, Jim Moseby wrote:
I must be brain dead today since I can't get my syntax correct.
Simple MySQL query to return a list of last_name. No problem. Each
last name returned needs to be assigned to a unique variable like
On Thu, February 2, 2006 1:15 pm, Albert Padley wrote:
I must be brain dead today since I can't get my syntax correct.
Simple MySQL query to return a list of last_name. No problem. Each
last name returned needs to be assigned to a unique variable like
name1, name2, name3, etc.
Somebody just
No need to subscript them, my_name_array[] will work just fine.
Miles
At 03:49 PM 2/2/2006, Programmer wrote:
$x = 0;
my_name_array = array();
While($row=mysql_fetch_array($result))
{
my_name_array[$x] = $row[last_name];
}
Jeremy Schreckhise
-Original Message-
From:
or you can forget about keeping track of the indexes and just use
array_push or the even simpler $names[]=$row['lastname'];
Jim Moseby wrote:
I must be brain dead today since I can't get my syntax correct.
Simple MySQL query to return a list of last_name. No problem. Each
last name returned
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