Re: [PHP] formating numbers date

2002-12-04 Thread Jeff Bluemel
I'm displaying a date that I get from a informix database query - the date format is as follows; 2002-12-04 23:21:49 I want it to display as 12/4/2002 11:21:49 PM Jeff Jason Wong [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... On Wednesday 04 December 2002

Re: [PHP] formating numbers date

2002-12-04 Thread Justin French
Hi, ? $date = '2002-12-04 23:21:49'; $newdate = date('m/d/Y', strtotime($date)); echo $newdate; ? Should do the trick -- although I haven't stripped out the leading 0 in either the day or month, hence it will echo 12/04/2002, not 12/4/2002. Season to taste, Justin on 05/12/02 10:58 AM,

Re: [PHP] formating numbers date

2002-12-04 Thread Rick Widmer
At 04:58 PM 12/4/02 -0700, Jeff Bluemel wrote: I'm displaying a date that I get from a informix database query - the date format is as follows; 2002-12-04 23:21:49 I want it to display as 12/4/2002 11:21:49 PM $Hour = substr( $Date, 11, 2 ); if( $Hour ) 12 { $Hour = $Hour - 12; $AMPM =

Re: [PHP] formating numbers date

2002-12-04 Thread Justin French
on 05/12/02 11:15 AM, Justin French ([EMAIL PROTECTED]) wrote: Hi, ? $date = '2002-12-04 23:21:49'; $newdate = date('m/d/Y', strtotime($date)); echo $newdate; ? Whooops, forgot the time bit! Should be ? $date = '2002-12-04 23:21:49'; $newdate = date('n/j/Y g:i:s a', strtotime($date));

Re: [PHP] formating numbers date

2002-12-04 Thread Justin French
on 05/12/02 11:37 AM, Rick Widmer ([EMAIL PROTECTED]) wrote: $Hour = substr( $Date, 11, 2 ); if( $Hour ) 12 { $Hour = $Hour - 12; $AMPM = 'PM'; } else { $AMPM = 'AM'; } echo substr( $Date, 5, 2 ), '/', substr( $Date, 8, 2 ), '/', substr( $Date, 0, 4 ), ' ', $Hour, substr( $Date,

Re: [PHP] formating numbers date

2002-12-04 Thread Jeff Bluemel
thanks... I will play with this, and let ya know if I have a problem... looks easy enough. Jeff Justin French [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... on 05/12/02 11:15 AM, Justin French ([EMAIL PROTECTED]) wrote: Hi, ? $date = '2002-12-04

Re: [PHP] formating numbers date

2002-12-04 Thread Rick Widmer
At 11:51 AM 12/5/02 +1100, Justin French wrote: on 05/12/02 11:37 AM, Rick Widmer ([EMAIL PROTECTED]) wrote: $Hour = substr( $Date, 11, 2 ); if( $Hour ) 12 { $Hour = $Hour - 12; $AMPM = 'PM'; } else { $AMPM = 'AM'; } echo substr( $Date, 5, 2 ), '/', substr( $Date, 8, 2 ), '/',

Re: [PHP] formating numbers date

2002-12-04 Thread Justin French
on 05/12/02 12:47 PM, Rick Widmer ([EMAIL PROTECTED]) wrote: Yes, it is simpler to code, but it also takes almost twice as long to run. 1000 iterations with strtotime: 0.2296 seconds 1000 iterations with substr:0.1308 seconds Doesn't matter much if you only do it once, but it can add

Re: [PHP] formating numbers date

2002-12-04 Thread Jeff Bluemel
worked great... the other method may be a little quicker, but this code is easier for me to understand, and although it is used in a loop there really is no visible difference in how quickly it displays. thanks, Jeff Justin French [EMAIL PROTECTED] wrote in message [EMAIL

Re: [PHP] formating numbers date

2002-12-03 Thread Jeff Bluemel
ok - I've been looking through this... the number_format is working great (actually I finally found that function right before I read your response), but the date format doesn't seem to allow me to pass it a date. Jeff Kevin Stone [EMAIL PROTECTED] wrote in message

Re: [PHP] formating numbers date

2002-12-03 Thread Jason Wong
On Wednesday 04 December 2002 08:29, Jeff Bluemel wrote: ... but the date format doesn't seem to allow me to pass it a date. Your code? -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications