[PHP] phpmyadmin is installed, now how to access it?

2001-10-28 Thread Chip

I just installed the FreeBSD port for PHPMyAdmin and was reading the docs on 
the php wizard site but cannot figure out how to actually access the 
interface. Is it through a particular port like webmin? Can some clue me in 
please?
-- 
Chip W.

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Re: [PHP] phpmyadmin is installed, now how to access it?

2001-10-28 Thread Jason Brooke

In your web browser like you would any other web interface on your machine

jason

- Original Message -
From: Chip [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Sunday, October 28, 2001 4:39 PM
Subject: [PHP] phpmyadmin is installed, now how to access it?


 I just installed the FreeBSD port for PHPMyAdmin and was reading the docs
on
 the php wizard site but cannot figure out how to actually access the
 interface. Is it through a particular port like webmin? Can some clue me
in
 please?
 --
 Chip W.

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[PHP] HELP: Still Learning

2001-10-28 Thread jtjohnston

Still learning! But need syntax help. This works:


 $myconnection =
 mysql_pconnect($host,MyAccount,MyPassword);
 ...
 $news = mysql_query(SHOW TABLE STATUS FROM MyAccount LIKE
 'MyTable');
 ...

This does not:


 $MyAccount = MyAccount;
 $MyTable = MyTable;
 $MyPassword = MyPassword;

 $myconnection =
 mysql_pconnect($host,$MyTable,$MyPassword);
 ...
 $news = mysql_query(SHOW TABLE STATUS FROM MyAccount LIKE
 'MyTable');
 ...

So? ... How do I use $MyAccount, $MyTable  $MyPassword correctly? ...
I'm creating a function.inc ...

An email post  reply would help ... (help me get to bed faster tonight
:) )

John



[PHP] Toronto PHP user group active.

2001-10-28 Thread Dariush

Toronto PHP user group active.

Welcoming all php developers with questions and answers.

If we get enough people we will be setting up meetings but again based
on how many people we can have.

www.realsoftstudio.com
[EMAIL PROTECTED]



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Re: [PHP] Arrays

2001-10-28 Thread Christian Reiniger

On Friday 26 October 2001 10:17, Ashley M. Kirchner wrote:
 I'd like to create an array of available resources, and be able
 to check it every time.  What I'd like to do is something like;

 $site = array( section1 = #, section2 = #, etc.. )

 where section* is a STRING variable and # is an INT  (if it's
 even possible to do that)

 Once I have this setup properly, I'm going to have a routine that
 extracts data from PATH_INFO, namely '$section' and '$page' which
 should then be checked against the array:

 - if $section exists in the array

[...]

http://www.php.net/manual/en/ref.array.php

-- 
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LGDC Webmaster (http://lgdc.sunsite.dk/)

Drink wet cement. Get stoned.

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Re: [PHP] Include Precompiled C binaries

2001-10-28 Thread Christian Reiniger

On Friday 26 October 2001 22:32, Daelic wrote:
 I was debating perl Vs. PHP with a friend, and he came up with this:

 Perl can include compiled C binaries without backprocessing them,
 which is a pretty useful trick.

Ask him what he means with backprocessing

-- 
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CPU not found. retry, abort, ignore?

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Re: [PHP] Re: Problem redirecting

2001-10-28 Thread Nikola Karovi

You have to put Header(  "Location:http://www.mydomain.com/mypage.html"); on
top of your php code


- Original Message -
From: Justin Garrett [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: 28. listopad 2001 07:00
Subject: [PHP] Re: Problem redirecting


 From the manual:

 Remember that the header() function must be called before any actual
output
 is sent, either by normal HTML tags blank lines in a file, or from PHP.

 This is the cause of your error.  Something is sending output before your
 call to header();

 --
 Justin Garrett

 "Don" [EMAIL PROTECTED] wrote in message
 000c01c15f67$1a06ad80$[EMAIL PROTECTED]">news:000c01c15f67$1a06ad80$[EMAIL PROTECTED]...
 Hi,

 I have a form which when submitted, calls an html page which contains PHP
 code.  Within that code, I wish to redirect my users to another page under
 certain conditions.  So, in my code, I have the following lines:

 Header(  "Location:http://www.mydomain.com/mypage.html");
 exit;

 However, when the above is run, I get the following error generated:

 Warning: Cannot add header information - headers already sent by (output
 started at /usr/local/www/vhosts/mydomain.com/htdocs/mypage.html:7) in
 ../phpscript/general/formmail.php on line 100

 Does anyone know what this error means?

 hanks,
 Don






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Re: [PHP] HELP: Still Learning

2001-10-28 Thread Christian Reiniger

On Sunday 28 October 2001 07:18, jtjohnston wrote:
 Still learning! But need syntax help. This works:
  mysql_pconnect($host,MyAccount,MyPassword);
  ...

 This does not:
  mysql_pconnect($host,$MyTable,$MyPassword);

Notice something? :)

-- 
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LGDC Webmaster (http://lgdc.sunsite.dk/)

CPU not found. retry, abort, ignore?

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Re: [PHP] HELP: Still Learning

2001-10-28 Thread speedboy

  Still learning! But need syntax help. This works:

 Notice something? :)

Yep, you forgot to paste the error message into the email.


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Re: [PHP] HELP: Still Learning

2001-10-28 Thread Nikola Karoviæ

$host :)

- Original Message - 
From: Christian Reiniger [EMAIL PROTECTED]
To: jtjohnston [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: 28. listopad 2001 11:15
Subject: Re: [PHP] HELP: Still Learning


On Sunday 28 October 2001 07:18, jtjohnston wrote:
 Still learning! But need syntax help. This works:
  mysql_pconnect($host,MyAccount,MyPassword);
  ...

 This does not:
  mysql_pconnect($host,$MyTable,$MyPassword);

Notice something? :)

-- 
Christian Reiniger
LGDC Webmaster (http://lgdc.sunsite.dk/)

CPU not found. retry, abort, ignore?

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php-general Digest 28 Oct 2001 11:52:35 -0000 Issue 961

2001-10-28 Thread php-general-digest-help


php-general Digest 28 Oct 2001 11:52:35 - Issue 961

Topics (messages 72595 through 72619):

Re: I'm not username, log me out
72595 by: Matthew Loff

Re: FTP or Telnet files/directories with PHP?
72596 by: CC Zona

Re: Replace text
72597 by: DL Neil

Re: command line option f -- how do i get the name of the file?
72598 by: DL Neil

Q: System user and password
72599 by: taipan.shofiah.kusza.edu.my

array_search()
72600 by: Ashley M. Kirchner

Re: help needed for multimania.com
72601 by: Andrew Brampton

Re: include-ing results in variable?
72602 by: Nathaniel Merriam

Multi-dimensional nested arrays in Smarty
72603 by: Chad Guilette

Re: how to recognize local or server execution?
72604 by: John A. Grant

Problem redirecting
72605 by: Don
72606 by: Justin Garrett
72616 by: Nikola Karoviæ

some.php/value - on win32
72607 by: c

Re: problems with sessions (not working)
72608 by: Yasuo Ohgaki

phpmyadmin is installed, now how to access it?
72609 by: Chip
72610 by: Jason Brooke

Re: Still Learning
72611 by: jtjohnston
72617 by: Christian Reiniger
72618 by: speedboy
72619 by: Nikola Karoviæ

Toronto PHP user group active.
72612 by: Dariush

Toronto php users group meeting.
72613 by: Dariush

Re: Arrays
72614 by: Christian Reiniger

Re: Include Precompiled C binaries
72615 by: Christian Reiniger

Administrivia:

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I found sessions to be kind of fussy to get working, perhaps that's just
because I didn't have any experience with them until the last site I
did...

A simple call to session_unset() won't erase the session, but should
clear whatever username/passkey (I say passkey, assuming/hoping it's
encrypted) is stored in the session.



-Original Message-
From: Andy Lewis [mailto:[EMAIL PROTECTED]] 
Sent: Saturday, October 27, 2001 9:45 AM
To: [EMAIL PROTECTED]
Subject: [PHP] I'm not username, log me out


Hello All,

I'm trying to use php sessions to logout a user that may be sharing a
computer with another user.

In other words. I don't want user1 to access my site and then user2 be
able to access user1's account with an auto login because the session
was saved. 

I've seen a few sites that have a URL or button that a user can click on
such as: I'm not Joe Smith, please log me out.

This is what I am trying to accomplish. Can someone point me in the
right
direction? I have sessions implemented using username and password but,
on
my login page since those vars are saved in the session the user
automatically gets logged in.

I also would like to have a checkbox on the login page that, if checked,
doesn't cache the username and password. So if they logout they must
enter
a username and password, instead of getting automatically logged in.

Any help will be highly appreciated.

Andy



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In article [EMAIL PROTECTED],
 [EMAIL PROTECTED] (Jeff Gannaway) wrote:

 Can PHP run some FTP or TELNET commands? 

http://php.net/ftp
http://php.net/fsockopen

-- 
CC




 Hello guys

 function replace_text_smiley(){

 global $comment;
 // To add a relation between a text smiley a an image smiley do this:
 // $faces[text smiley here] = img tag to image smile here;

 $faces[:)] = IMG SRC=\emoticons/smile.gif\;
 $faces[:P] = IMG SRC=\emoticons/tongue.gif\;
 $faces[:D] = IMG SRC=\emoticons/happy.gif\;
 $faces[:(] = IMG SRC=\emoticons/mad.gif\;
 $faces[;)] = IMG SRC=\emoticons/wink.gif\;

 while(list($text,$image) = each($faces))
 {
 $comment = str_replace($text,$image,$comment);
 }

 return $comment;
 }

 this function replaces faces to smilies images

 then in a separete file i use this function and another one to replace urls... the 
url replacement is ok but
it doesn't change the text to smilies..

 any guesses?? :)

=do you really want those quotation marks in the str_replace function call?
=dn






 I am writing a script using php's command line ability and I am lost on 
 how to work with a file when I don't kow what the file's name is.
 
 Example:
 script.php -f file
 
 In my script, how do I reference the file when I have no idea what it's 
 name is going to be?
 
 The scrip will get called by another application: the other application 
 will pipe a file to my scrip and then the scrip has to work with the 
 file and output an altered file with a new filename. I have no idea what 
 the name of the file is going to be beforehand.


lucas

Take a 

Re: [PHP] Excel to MySQL

2001-10-28 Thread dav

I use to save my access data to a dbf file and then use the dbf2mysql (see
www.mysql.com site).
dbf2mysql will create proper tables and export data to the mysql really
faster than odbc.
Very easy.
I have exported someting like 5.000.000 records into 8 differents tables in
4 hours (3 cdroms of access data, 1 cd of dbf data :)
And no need to create the table into mysql (this could be long if the table
is big).

Byez

Daniel Harik [EMAIL PROTECTED] ha scritto nel messaggio
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Guys getting more serious here now, 3 500 000 records, foxPro

 i'll try Jeff's method




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[PHP] Finding out document type for a stored file.

2001-10-28 Thread Alexis Antonakis

Hi all,

I am trying to find out what the mime type is for files that are stored on
my webserver, so I can convert the contents into a database.

Basically, if it is in 'text/richtext' format I want to run one routine, if
it's in 'application/msword' format another routine, and everything else
another.

I can retrieve this fine when a user uploads a file to the server, by using
the 'input type=file name=userfile' command ($userfile_type), but I am
stuck when retrieving the file from the server.

All I can think of is to 're-upload' the file, but there must be a more
efficient way.

Any help would be most appreciated.

Many thanks
Alexis



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[PHP] How Do I Re-Compile PHP4

2001-10-28 Thread Jeff Gannaway

I've always had PHP set up on a shared server before.  Now that I'm leasing
a server that had it installed, I can change the configuration of it.

I need to enable the FTP commands.  I found the command in the FTP section
of the PHP manual, but I'm not sure hwo to actually use it.

I've tried looking at the docs on-line, but can't tell exactly what to do,
and I don't wnat to risk crashing my server since so many of my clients are
running PHP scripts.

The command I found was:
./configure --enable-ftp

I know the directory that my PHP files are found at.  I'm using a
Linux/Apache system.

How do I re-compile???  I assume it's fairly easy since I read so many
messages that say just recompile PHP with --with-blah-blah-blah.

Thanks!
-Jeff Gannaway
___

Save 15% on 2002 Calendars and Holiday Cards!

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RE: [PHP] Toronto PHP user group active.

2001-10-28 Thread Mark Saunders

So is this a monthly thing like Lug meetings?
If it is, then count me in!

-Original Message-
From: Dariush [mailto:[EMAIL PROTECTED]] 
Sent: Sunday, October 28, 2001 2:47 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Toronto PHP user group active.

Toronto PHP user group active.

Welcoming all php developers with questions and answers.

If we get enough people we will be setting up meetings but again based
on how many people we can have.

www.realsoftstudio.com
[EMAIL PROTECTED]



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Re: [PHP] how to recognize local or server execution?

2001-10-28 Thread DL Neil

John,

Netscape! Differences between servers AND differences between browsers AND differences 
between in-browser and
command-line operations!
Isn't life fun?

Like you I'm messing around with some of these differences as part of a bid to 
'convert' an existing set of
scripts from browser i/f to command-line. At present I'm putting up with all the HTML 
output - that's a ToDo
'soon' I guess; but have fixed the time-clock base so that everything is converted 
back and forth between
UTC/GMT and local times.

Like you I have rolled-my-own function which uses the following two variables: 
SetSuffix($argv[0],
$GLOBALS[SERVER_NAME]);
$ServerName is used to work out which (Apache) Vserver is running the script, whereas 
$directory is used to work
out where code is being run from (at the command line). The main decision being driven 
from here is whether to
run off the 'production' or 'test' database - I've just tweaked that from code I wrote 
some weeks ago around
another global. I guess I'll now have to emulate your plan and now work out how to 
control all the output, if
not logging, then displaying at the command line/green screen as opposed to the 
browser.

Regards,
=dn

  Thanks for the idea. I have just resurrected and had another play with my
 'testbench.php', running it from both
  IE/Apache and in a DOS box.
 
  It includes the following code:
 [...]

 Thanks (also thanks to the others for the useful comments  ideas).

 I don't have $HTTP_SERVER_VARS[SERVER_NAME]
 or $GLOBALS[SERVER_ADDR] or $SERVER_SOFTWARE
 probably because my server is netscape (nsapi?). They
 are all blank. Yes I declared them 'global'.

 I ended up with these functions which seem to do the trick, at
 least for my server and NT.

 function isonserver()
 {
 global $PHP_SELF,$argc;
 return $argc==0  isset($PHP_SELF)  $PHP_SELF;
 }

 function getpagename()
 {
 global $PHP_SELF,$argv;
 return basename(isonserver() ? $PHP_SELF : $argv[0]);
 }

 function getlinedelimiter()
 {
 return isonserver() ? \n : \r\n;
 }

 The pagename is critical to my site, because the code needs
 the page name to recognize certain suffixes and 'special page
 names.

 Perhaps it is only sufficient to test for $PHP_SELF and not $argc,
 but I threw in $argc==0 anyway.



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Re: [PHP] How Do I Re-Compile PHP4

2001-10-28 Thread Andrew Brampton

I actually have never compiled or re-compiled PHP, but if you are so
concerned about not crashing PHP, how about you set up a test server first,
play with that for a while, and then once you are happy with the results
apply them to the real server...

If you don't have a spare machine to do this on then just use the computer
you are using at the moment. U can more than easily set up a Dual Boot of
Windows  1gig Linux partions...

I think this is allways a good general admin tip to carry out

Andrew
- Original Message -
From: Jeff Gannaway [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Sunday, October 28, 2001 2:51 PM
Subject: [PHP] How Do I Re-Compile PHP4


 I've always had PHP set up on a shared server before.  Now that I'm
leasing
 a server that had it installed, I can change the configuration of it.

 I need to enable the FTP commands.  I found the command in the FTP section
 of the PHP manual, but I'm not sure hwo to actually use it.

 I've tried looking at the docs on-line, but can't tell exactly what to do,
 and I don't wnat to risk crashing my server since so many of my clients
are
 running PHP scripts.

 The command I found was:
 ./configure --enable-ftp

 I know the directory that my PHP files are found at.  I'm using a
 Linux/Apache system.

 How do I re-compile???  I assume it's fairly easy since I read so many
 messages that say just recompile PHP with --with-blah-blah-blah.

 Thanks!
 -Jeff Gannaway
 ___

 Save 15% on 2002 Calendars and Holiday Cards!

 http://www.AvantGifts.com
 Discount Code: hopper22ct
 Offer Good Through October 31, 2001
 ___


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[PHP] How do I prevent remote loading of jpegs from my site

2001-10-28 Thread rodrigo

Hello. I run a site that has lots of pictures (jpegs). It is pretty
popular, but some visitors have gotten into the habit of going to forums
and bulletin boards on other sites and making direct links (you know,
img src=http...) of my pictures there.

My hosting provider is going to charge me extra for that bandwidth, and
I am not getting any benefits since users are not looking at the
pictures on my site.

So, the question is, how do I prevent this remoting loading from
happening.

Please help.
-- 

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Aptdo 1263 * (507)228-9105
Balboa, Ancon  * 612-1103
Republic of Panama * 


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Re: [PHP] How do I prevent remote loading of jpegs from my site

2001-10-28 Thread Duncan Hill

On Sun, 28 Oct 2001, rodrigo wrote:

 So, the question is, how do I prevent this remoting loading from
 happening.

Go to the Apache site (assuming you use apache) and look at the 
rewriting and so on.  You'll find your answer in there.

-- 

Sapere aude
My mind not only wanders, it sometimes leaves completely.


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Re: [PHP] How do I prevent remote loading of jpegs from my site

2001-10-28 Thread Kurt Lieber

On Sunday 28 October 2001 10:26 am, you wrote:
 So, the question is, how do I prevent this remoting loading from
 happening.

Well, since the users are linking directly to your image, then you can't use 
PHP commands to prevent it.  (since that would requuire the user loading a 
PHP page that then loaded the image)

However, Apache has features built in that allow you to filter out all calls 
to a certain directory (such as /images) that don't come from the local 
machine.  Check out the apache docs for more info (httpd.apache.org)

hth

--kurt

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Re: [PHP] How Do I Re-Compile PHP4

2001-10-28 Thread Mike Eheler

I'm not sure if you can add functionality using ./config.status, but 
inside that file is the command line you used to originally compile it, 
so what you can do is copy that ./configure line, then add your 
--enable-ftp, and go.

Might wanna run make clean first (not distclean!)

Mike

Jeff Gannaway wrote:

I've always had PHP set up on a shared server before.  Now that I'm leasing
a server that had it installed, I can change the configuration of it.

I need to enable the FTP commands.  I found the command in the FTP section
of the PHP manual, but I'm not sure hwo to actually use it.

I've tried looking at the docs on-line, but can't tell exactly what to do,
and I don't wnat to risk crashing my server since so many of my clients are
running PHP scripts.

The command I found was:
./configure --enable-ftp

I know the directory that my PHP files are found at.  I'm using a
Linux/Apache system.

How do I re-compile???  I assume it's fairly easy since I read so many
messages that say just recompile PHP with --with-blah-blah-blah.

Thanks!
-Jeff Gannaway
___

Save 15% on 2002 Calendars and Holiday Cards!

http://www.AvantGifts.com
Discount Code: hopper22ct
Offer Good Through October 31, 2001
___ 





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Re: [PHP] RE: overloading variables in child classes

2001-10-28 Thread Alain Dresse

Andrew,

Thanks for your reply. There still is something I don't understand.

I understand that my derived class inherits all the member variables and
functions of the base class. I would expect however that upon redeclaring a
variable in a derived class, the variable in the derived class shadows the
variable in the base class (as it does in java). The PHP behaviour mimics
for variables the behaviour for member functions. This behaviour on
functions is necessary to have polymorphism, but I believe it is dangerous
for variables.

Imagine I define a base class of shapes, in which I declare a variable
called $depth representing the size of my object on the z axis. Assume
someone (could be me) derives a colored_shape class from my shape class, and
declares a variable called $depth to represent the color depth. Evidently,
setting the $depth variable in the class colored_shape will change the shape
of the object, which is probably not the desired behaviour.

The current treatment of member variables in PHP forces a programmer
deriving from a class to know the names of all the variables defined in the
base class and its (recursive) parents in order to avoid corrupting them. It
seems to me that this hinders the reuse of classes, which I believe is one
of the main objectives of OOP.

Regards,

Alain

Andrew Kirilenko [EMAIL PROTECTED] a écrit dans le message de news:
[EMAIL PROTECTED]
 Hello!

  Is there something I don't understand ?
 Yes.

 According OOP concepts, derived class inherits all functionality and data
 from the base. So, if you have $shared variable in the base class, your
 derived class will have it automatically. But PHP allows you to declare
this
 variable once again in the derived class. In C++ you will get comilation
 error in this case.

 Best regards,
 Andrew Kirilenko.

  -Original Message-
  From: Alain Dresse [mailto:[EMAIL PROTECTED]]
  Sent: Saturday, October 27, 2001 10:12 PM
  To: [EMAIL PROTECTED]
  Subject: [PHP] overloading variables in child classes
 
 
  Hi all,
 
  I am a bit puzzled by the way PHP treates variables that have the
  same name
  in a base class and a child class.
  It seems to me that if a child class and its parent both have a variable
  with the same name, then they should be different variables. Instead,
the
  example below indicates that they is only one variable :
  
  class base {
  var $shared;
  function base() {$this-shared = base;}
  function test() {echo(\$shared in base :  . $this-shared .
  br\n);}
  }
 
  class child extends base {
  var $shared;
  function child(){$this-base(); $this-shared = child;}
  function test() {
 echo (\$shared in child :  . $this-shared . br\n);
  parent::test();
  }
  }
 
  $the_child = new child();
  $the_child-test();
  
 
  I would have expected the output to be
  $shared in child : child
  $shared in base : base
 
  instead I have
  $shared in child : child
  $shared in base : child
 
  Is there something I don't understand ?
 
  Regards,
  Alain Dresse
  [EMAIL PROTECTED]




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[PHP] Preventing remote linking of files

2001-10-28 Thread rodrigo

Hello. I found this on the web after a couple of people who answered my
original request pointed me to it. It is a document that tells you how
to prevento people from inserting files directly from your site,
stealing your bandwidth.

I hope it is useful to you.

http://apachetoday.com/news_story.php3?ltsn=2000-06-14-002-01-PS
-- 

Ivan R. Quintero E.* (507)228-3477  
Aptdo 1263 * (507)228-9105
Balboa, Ancon  * 612-1103
Republic of Panama * 


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[PHP] Attaching a file to a form!

2001-10-28 Thread Ben Clumeck

I am trying to let a person attach a file to my form.  Can anyone help?

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FW: [PHP] Trying to create a site-template system.. and..

2001-10-28 Thread Ryan Christensen

Just a refresher.. I never got any feedback on this, and would
appreciate any input anyone has.

Thanks!
Ryan

 -Original Message-
 From: Ryan Christensen [mailto:[EMAIL PROTECTED]] 
 Sent: Friday, October 26, 2001 6:03 PM
 To: [EMAIL PROTECTED]
 Subject: [PHP] Trying to create a site-template system.. and..
 
 
 First.. here's the synopsis of what I'm trying to do:
 
 I'm working on a site where everything is based off a really 
 simple template system I'm using, see the chunk of my index 
 page that deals with the plates for example:
 
 -
 $tmpl_file = fopen (./template.htm, r);
 $tmpl = fread($tmpl_file,16000);
 $tmpl = str_replace({title}, $title, $tmpl);
 $tmpl = str_replace({header}, $header, $tmpl);
 $tmpl = str_replace({header_url}, $header_url, $tmpl); 
 $tmpl = str_replace({header_home}, $header_home, $tmpl); 
 $tmpl = str_replace({header_cat}, $header_cat, $tmpl); 
 $tmpl = str_replace({header_caturl}, $header_caturl, 
 $tmpl); $tmpl = str_replace({header_title}, 
 $header_title, $tmpl); $tmpl = str_replace({pretext}, 
 $pretext, $tmpl); $tmpl = str_replace({content}, 
 $content, $tmpl); $tmpl = str_replace({content_source}, 
 $page_source, $tmpl);
 
 eval(echo \$tmpl;);
 -
 
 The template file looks like blah.. blah.. {title}.. the 
 code above then takes the {blah} tags, and turns them into 
 variables, which are defined in the actual content pages 
 (which are included (via an include(); function..)
 
 The content files appear as:
 
 -
 $title = testing;
 $content = etc;
 -
 
 And so on..
 
 My problem is.. that when I do something like
 
 -
 $content = show_source(/path/to/file);
  // or
 $content = Blah.. blah.. .include(/some/file)... some 
 more blah..;
 -
 
 It includes the files (or executes the code that is assigned 
 to the variable), however it all appears OUTSIDE the 
 template. To see what I'm saying, see 
 http://olypen.com/ryan/go/main/news or 
http://olypen.com/ryan/go/source/source_index .. that will give you a
better idea as to what I'm saying.

Anyone have any thoughts/explanations as to why this is happening? I can
provide more source.. or info if needed.

Thanks in advance!

-Ryan


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[PHP] help measuring time for img creating...

2001-10-28 Thread Christian Dechery

I have a script that generates quite a complex report...

at this script I call several times another script that generates images 
(of course based on the main report script)...

I'd like some ideas on how I can measure the WHOLE time it took the build 
the entire page... because the images are not accounted for in the main 
script... it always returns something like 1 or 2 seconds when it actually 
took 30 or 40 seconds to finish...

any ideas?

_
. Christian Dechery
. . Gaita-L Owner / Web Developer
. . http://www.webstyle.com.br
. . http://www.tanamesa.com.br


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[PHP] HELP: Syntax Needed

2001-10-28 Thread jtjohnston

Jokes aside, I still don't get it.

 $host = localhost;
 $MyAccount = AccountName;
 $MyTable = Table1;
 $MyPassword = beep;

This works:
mysql_pconnect($host,AccountName,beep);
$news = mysql_query(SHOW TABLE STATUS FROM AccountName LIKE 'Table1');

Why doesn;'t this?

 $myconnection = mysql_pconnect($host,$MyTable,$MyPassword);
 ...
 $news = mysql_query(SHOW TABLE STATUS FROM $MyAccount LIKE
 '$MyTable');

I have tried variations with or without  and '. Is there a way to make this
work? Or do I have to do as above every time?

 $host :)

Your telling me to put $host in $host? OK:

 $myconnection = mysql_pconnect($host,$MyAccount,$MyPassword);

It doesn't work?! Neither does:

 $myconnection = mysql_pconnect($host,$MyAccount,$MyPassword);
 $myconnection = mysql_pconnect('$host','$MyAccount','$MyPassword');

If I try this, $stringing just $host, it works!?

mysql_pconnect($host,AccountName,beep);



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[PHP] switch-statement overrides use of global arrays?

2001-10-28 Thread Imar de Vries

Hi all,

a very frustrating problem. For some reason I am not able to pass on an
array between two functions, although I declare it global in both of
them. I suspect my use of a switch statement to control the flow of the
functions is causing some trouble, but I'm not sure. Changing the order
in which I declare the array global did not help, nor the use of
$GLOBALS.

This is a simple representation of what I do:

switch ($action) {
 default:
 main();
 break;
 case test_one:
 test_one();
 break;
}

// ---

function main() {

 $array_test = array();
 global $array_test;

 $array_test[0] = First array, first element;
 $array_test[1] = First array, second element;

 print(Content of first array in the main function is now:br);
 var_dump($array_test);

 print (pform method=\post\ action=\arraytest.php\
enctype=\multipart/form-data\);
 ?
 input type=hidden name=action value=test_one
 input type=submit value=Test tabindex=6
 /form
 ?
}

// ---

function test_one() {

 global $array_test;

// This results in NULL

 print(Content of first array in the first test function is now:br);

 var_dump($array_test);

 $array_test[2] = First array, third element;
 $array_test[3] = First array, fourth element;

// This results in the third and fourth element being shown

 print(pAfter addition, content of first array is:br);
 var_dump($array_test);
}

--
Imar de Vries - [EMAIL PROTECTED] - ICQ 6972439



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[PHP] Re: help measuring time for img creating...

2001-10-28 Thread Henrik Hansen

[EMAIL PROTECTED] (Christian Dechery) wrote:

  I have a script that generates quite a complex report...
  
  at this script I call several times another script that generates
  images (of course based on the main report script)...
  
  I'd like some ideas on how I can measure the WHOLE time it took the
  build the entire page... because the images are not accounted for in
  the main script... it always returns something like 1 or 2 seconds
  when it actually took 30 or 40 seconds to finish...
  
  any ideas?

if i got you right, you can use microtime();

look at

http://www.php.net/manual/en/function.microtime.php

-- 
Henrik Hansen

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Re: [PHP] switch-statement overrides use of global arrays?

2001-10-28 Thread Henrik Hudson

Hey-

I would think you would need to define $array_test outside in a global 
environment rather then inside the function since I think/thought it will 
just stay scoped in there and that  global was used to access variables 
which weren't defined inside a functions scope and make it look outside.

In other words

//Define GLOBAL
$array_test = array();

switch(){
BLAH
BLAH

}

function main() {
global $array_test;
BLAH
BLAH

}

function test_one(){
global $array_test;
BLAH
BLAH

}


Hope that helps.

Henrik

On Sunday 28 October 2001 15:17, Imar de Vries wrote:
  Hi all,

  a very frustrating problem. For some reason I am not able to pass on an
  array between two functions, although I declare it global in both of
  them. I suspect my use of a switch statement to control the flow of the
  functions is causing some trouble, but I'm not sure. Changing the order
  in which I declare the array global did not help, nor the use of
  $GLOBALS.

  This is a simple representation of what I do:

  switch ($action) {
   default:
   main();
   break;
   case test_one:
   test_one();
   break;
  }

  // ---

  function main() {

   $array_test = array();
   global $array_test;

   $array_test[0] = First array, first element;
   $array_test[1] = First array, second element;

   print(Content of first array in the main function is now:br);
   var_dump($array_test);

   print (pform method=\post\ action=\arraytest.php\
  enctype=\multipart/form-data\);
   ?
   input type=hidden name=action value=test_one
   input type=submit value=Test tabindex=6
   /form
   ?
  }

  // ---

  function test_one() {

   global $array_test;

  // This results in NULL

   print(Content of first array in the first test function is now:br);

   var_dump($array_test);

   $array_test[2] = First array, third element;
   $array_test[3] = First array, fourth element;

  // This results in the third and fourth element being shown

   print(pAfter addition, content of first array is:br);
   var_dump($array_test);
  }

-- 

Henrik Hudson
[EMAIL PROTECTED]


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Re: [PHP] switch-statement overrides use of global arrays?

2001-10-28 Thread Imar de Vries

Henrik Hudson wrote:

 I would think you would need to define $array_test outside in a global
 environment rather then inside the function since I think/thought it will
 just stay scoped in there and that  global was used to access variables
 which weren't defined inside a functions scope and make it look outside.

 In other words

 //Define GLOBAL
 $array_test = array();

 switch(){
 BLAH
 BLAH

 }

 function main() {
 global $array_test;
 BLAH
 BLAH

 }

 function test_one(){
 global $array_test;
 BLAH
 BLAH

 }

Yes, the only way I could avoid errors that occurred when I tried to manipulate
the array, was to add a $array_test = array(); a few lines before the switch
statement. Alas, this also emptied the array each time I went from one function
to another via the switch statement.

I guess I am trying something that is just not possible (when I insist on using
the switch statement)?
--
Imar de Vries - [EMAIL PROTECTED] - ICQ 6972439



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[PHP] One last kick at the cat

2001-10-28 Thread jtjohnston

Sigh ...

I have functions.inc in which I have Table_Title().

As soon as I put my database connection inside my function called
Table_Title(), my database connection fails. (See second example below.)

My database connection works fine whenever IT IS NOT inside function
Table_Title(). (See first example below.)

It seems that when I try to connect to my database inside function
Table_Title(), my function cannot read the values of $server, $user,
$pass, $db or $table ???

I call it normally??

?php Table_Title() ?

Can anyone help??


--SNIP THIS WORKS FINE! 
?php

$server = localhost;
$user = MyAccount;
$pass = MyPassword;
$db = MyDatabase;
$table = bookmark_unit4;

 $myconnection = mysql_pconnect($server,$user,$pass);
 mysql_select_db($db,$myconnection);
 $news = mysql_query(SHOW TABLE STATUS FROM .$db. LIKE '$table');
 while ($news_story = mysql_fetch_array($news))
 {
$table_comment = $news_story['Comment'];
 }
echo $table_comment;

function Table_Title()
{
echo Nothing;
}
?

-- SNIP THIS DOES NOT WORK 
?php

$server = localhost;
$user = MyAccount;
$pass = MyPassword;
$db = MyDatabase;
$table = bookmark_unit4;

function Table_Title()
{
 $myconnection = mysql_pconnect($server,$user,$pass);
 mysql_select_db($db,$myconnection);

 $news = mysql_query(SHOW TABLE STATUS FROM .$db. LIKE '$table');
 while ($news_story = mysql_fetch_array($news))
 {
$table_comment = $news_story['Comment'];
 }

echo $table_comment;
 //echo Nothing;
}
?


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Re: [PHP] switch-statement overrides use of global arrays?

2001-10-28 Thread Henrik Hudson

Well, the switch statement will only run ONE of the functions, never both. 
The default runs and then you break out of the switch, also: shouldn't 
default be at the bottom of the switch? or is that just convention? Anyways, 
there is no way for main() to ever pass anything to test_one(), since only 
one or the other is called in the switch (unless your switch is in a loop and 
$action changes in that loop).

Oh, your passing it back in via a form and then telling it to use: test_one. 
Oh, ummm, everytime you submit the code you are calling a new instance of 
the script. It will never remember variables between instances unless they 
are passed to the script via POST and hidden fields. At least as far as I 
know...but I might be missing something.

I would try and do whatever you are trying to do without resorting to a 
resubmit or just pass the variable to the function inside main: 
test_one($array_global);

Sorry I couldn't be of more help.




On Sunday 28 October 2001 15:48, you wrote:
  Hi Henrik,

   I would think you would need to define $array_test outside in a global
   environment rather then inside the function since I think/thought it
   will just stay scoped in there and that  global was used to access
   variables which weren't defined inside a functions scope and make it
   look outside.

  Yes, the only way I could avoid errors that occurred when I tried to
 manipulate the array, was to add a $array_test = array(); a few lines
 before the switch statement. Alas, this also emptied the array each time I
 went from one function to another via the switch statement.

  I guess I am trying something that is just not possible (when I insist on
 using the switch statement)?

-- 

Henrik Hudson
[EMAIL PROTECTED]


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Re: [PHP] One last kick at the cat

2001-10-28 Thread Henrik Hudson

Inside your function define:

global $server;
global $pass;
global $user;
etc

It is using variables insides it's own scope and unless you have use 
GLOBAL_VARIABLES defined in your php.config file, it won't go outside of it's 
scope to look for values, hence they are getting asigned NULL and you can't 
connect to a NULL DB :)

Henrik

On Sunday 28 October 2001 14:57, jtjohnston wrote:
  Sigh ...

  I have functions.inc in which I have Table_Title().

  As soon as I put my database connection inside my function called
  Table_Title(), my database connection fails. (See second example below.)

  My database connection works fine whenever IT IS NOT inside function
  Table_Title(). (See first example below.)

  It seems that when I try to connect to my database inside function
  Table_Title(), my function cannot read the values of $server, $user,
  $pass, $db or $table ???

  I call it normally??

  ?php Table_Title() ?

  Can anyone help??


  --SNIP THIS WORKS FINE! 
  ?php

  $server = localhost;
  $user = MyAccount;
  $pass = MyPassword;
  $db = MyDatabase;
  $table = bookmark_unit4;

   $myconnection = mysql_pconnect($server,$user,$pass);
   mysql_select_db($db,$myconnection);
   $news = mysql_query(SHOW TABLE STATUS FROM .$db. LIKE '$table');
   while ($news_story = mysql_fetch_array($news))
   {
  $table_comment = $news_story['Comment'];
   }
  echo $table_comment;

  function Table_Title()
  {
  echo Nothing;
  }
  ?

  -- SNIP THIS DOES NOT WORK 
  ?php

  $server = localhost;
  $user = MyAccount;
  $pass = MyPassword;
  $db = MyDatabase;
  $table = bookmark_unit4;

  function Table_Title()
  {
   $myconnection = mysql_pconnect($server,$user,$pass);
   mysql_select_db($db,$myconnection);

   $news = mysql_query(SHOW TABLE STATUS FROM .$db. LIKE '$table');
   while ($news_story = mysql_fetch_array($news))
   {
  $table_comment = $news_story['Comment'];
   }

  echo $table_comment;
   //echo Nothing;
  }
  ?

-- 

Henrik Hudson
[EMAIL PROTECTED]


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Re: [PHP] One last kick at the cat

2001-10-28 Thread Kurt Lieber

On Sunday 28 October 2001 12:57 pm, you wrote:

 It seems that when I try to connect to my database inside function
 Table_Title(), my function cannot read the values of $server, $user,
 $pass, $db or $table ???

you need to declare the variables as global.  See below and also see the 
manual to understand how global works.

 ?php

 $server = localhost;
 $user = MyAccount;
 $pass = MyPassword;
 $db = MyDatabase;
 $table = bookmark_unit4;

 function Table_Title()
 {

   global $server,$user,$pass,$db,$table;


  $myconnection = mysql_pconnect($server,$user,$pass);
  mysql_select_db($db,$myconnection);

  $news = mysql_query(SHOW TABLE STATUS FROM .$db. LIKE '$table');
  while ($news_story = mysql_fetch_array($news))
  {
 $table_comment = $news_story['Comment'];
  }

 echo $table_comment;
  //echo Nothing;
 }
 ?

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Re: [PHP] Trying to create a site-template system.. and..

2001-10-28 Thread Moody

Try this: (see http://www.php.net/manual/en/ref.outcontrol.php for more
info)

  My problem is.. that when I do something like
 
  -
  $content = show_source(/path/to/file);
   // or
  $content = Blah.. blah.. .include(/some/file)... some
  more blah..;
  -
 
  It includes the files (or executes the code that is assigned
  to the variable), however it all appears OUTSIDE the
  template.

ob_start(); // start buffer
eval(?.include (/path/to/file));
$file_content = ob_get_contents();
ob_end_clean(); // delete the buffer

$content = Blah.. blah.. .$file_content... some more blah..;

Hope this helps...




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Re: [PHP] HELP: Syntax Needed

2001-10-28 Thread DL Neil

 Jokes aside, I still don't get it.

=the word it is part of the difficulty everyone faces in thinking about whether they 
could help or not - what
it is, is not apparent
1 there is a problem with a mysql_pconnect() call, and
2 there is a problem with a mysql_query() call.
Which one is it?

=the confusing presentation of the question, even more confused by the lack of 
substance/focus in the rejoinder,
is not helping.

=the very first suggestion that those who have answered more-or-less this exact 
'pconnect' question many times a
week for ..., is a not-so-subtle hint to RTFM (and/or to review the list archives). 
When you read up about how
to write variables and constants, and how to use the mysql_... functions, then more 
will become obvious, and
less sarcasm will come your way.

=worse, you have quoted incomplete/inaccurate code fragments, so immediately the 
question arises: what else has
been left out? (the answer being closely related to it).

=The manual clearly says that missing out certain calls may not matter because MySQL 
will make assumptions and
attempt to carry on, but the instant problems arise, surely it would be better to 
follow all the examples in the
manual - which step through all of the calls, in sequence?

=next point: if you have a problem with a series of instructions, go back to first 
principles, break things down
and throw in echo/printr statements to 'prove' any and all assumptions - particularly 
the first time you try out
some code.

=last point: EVERY call to a client-server function should be checked (there's RTFM 
again), this will show if
the fault lies at 'pconnect', at 'open', and/or at the 'query' stage.

=dn
PS lecture mode off - please take advantage of our 'two-fer' special offer: any two 
well formed questions sent
to the list this week will be answered for the same price as one!



  $host = localhost;
  $MyAccount = AccountName;
  $MyTable = Table1;
  $MyPassword = beep;

 This works:
 mysql_pconnect($host,AccountName,beep);
 $news = mysql_query(SHOW TABLE STATUS FROM AccountName LIKE 'Table1');

 Why doesn;'t this?

  $myconnection = mysql_pconnect($host,$MyTable,$MyPassword);
  ...
  $news = mysql_query(SHOW TABLE STATUS FROM $MyAccount LIKE
  '$MyTable');

 I have tried variations with or without  and '. Is there a way to make this
 work? Or do I have to do as above every time?

  $host :)

 Your telling me to put $host in $host? OK:

  $myconnection = mysql_pconnect($host,$MyAccount,$MyPassword);

 It doesn't work?! Neither does:

  $myconnection = mysql_pconnect($host,$MyAccount,$MyPassword);
  $myconnection = mysql_pconnect('$host','$MyAccount','$MyPassword');

 If I try this, $stringing just $host, it works!?

 mysql_pconnect($host,AccountName,beep);



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Re: [PHP] switch-statement overrides use of global arrays?

2001-10-28 Thread DL Neil

Imar,
The global array is being defined in the mainline, but not populated. What happens if 
you set element 0 to some
value (to take up some storage space first) and then try the switched function calls?
When you say Alas, this also emptied the array each time I went from one function to 
another via the switch
statement. do you mean that the array definition line is inside the same loop that 
causes the switch statement
to be revisited?
(it shouldn't be - put it right at the beginning of the 'mainline' and ensure that it 
is not re-executed (which
would indeed 'reset' the values))
Regards,
=dn



- Original Message -
From: Imar de Vries [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: 28 October 2001 21:49
Subject: Re: [PHP] switch-statement overrides use of global arrays?


 Henrik Hudson wrote:

  I would think you would need to define $array_test outside in a global
  environment rather then inside the function since I think/thought it will
  just stay scoped in there and that  global was used to access variables
  which weren't defined inside a functions scope and make it look outside.
 
  In other words
 
  //Define GLOBAL
  $array_test = array();
 
  switch(){
  BLAH
  BLAH
 
  }
 
  function main() {
  global $array_test;
  BLAH
  BLAH
 
  }
 
  function test_one(){
  global $array_test;
  BLAH
  BLAH
 
  }

 Yes, the only way I could avoid errors that occurred when I tried to manipulate
 the array, was to add a $array_test = array(); a few lines before the switch
 statement. Alas, this also emptied the array each time I went from one function
 to another via the switch statement.

 I guess I am trying something that is just not possible (when I insist on using
 the switch statement)?
 --
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Re: [PHP] phpmyadmin is installed, now how to access it?

2001-10-28 Thread Chip

On Saturday 27 October 2001 23:47, Peter wrote:
 Very easy.

 After I expanded the PhpMyAdmin files in the appropriate directory, 

which is...?
I installed it into /usr/local/apache/htdocs/phpMyAdmin/
is that okay? It doesn't want to work correctly.

 I just
 set the appropriate server name, username and password for SQL server in
 the config.php.inc file

Done.

 Then I accessed the directory with my web browser and I was successfully
 in using PHPMyAdmin.

 Peter

I see all the files are name php3 rather than php. When I access the 
index.php3 of course it my browser doesn't know what to do so it asks if I 
want to download it. So I copied it as index.php and then I get all the code 
and not the actual rendered page.  Then I copied all the php3 files to php 
and still get just the code only. The docs are not clear on this stuff. 
Supposedly just install it to the appropriate directory (which is...?), then 
set the user name and password, and away you go. Hmm, not for me. Do I need 
to do something to my httpd.conf so it will know how to handle php3 files? I 
uncommented the appropriate lines so it will handle php3 as well as php, but 
that did no good. I added AddModule lines for php3, still no good. I don't 
know what to try next.
I'm sure it's easier than I make it out to be, but I don't know how to make a 
php3 program work on a php4 system, and the docs don't cover this.
--
Chip

 On Sat, 27 Oct 2001, Chip wrote:
  I just installed the FreeBSD port for PHPMyAdmin and was reading the docs
  on the php wizard site but cannot figure out how to actually access the
  interface. Is it through a particular port like webmin? Can some clue me
  in please?

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Re: [PHP] switch-statement overrides use of global arrays?

2001-10-28 Thread Imar de Vries

Dl Neil wrote:

 The global array is being defined in the mainline, but not populated. What happens 
if you set element 0 to some
 value (to take up some storage space first) and then try the switched function calls?

This did not produce the desired result, unfortunately. The array is filled correctly 
within the first function,
but is empty after we've passed the switch statement en route to the second function.

 When you say Alas, this also emptied the array each time I went from one function 
to another via the switch
 statement. do you mean that the array definition line is inside the same loop that 
causes the switch statement
 to be revisited?
 (it shouldn't be - put it right at the beginning of the 'mainline' and ensure that 
it is not re-executed (which
 would indeed 'reset' the values))

The array definition line was not inside the same loop as the switch, which it looked 
like of course because there
was a reset at some point, it seemed.

Henriks answer at 23:17 seems to have hit the nail in the head: each time the variable 
$action is changed (using a
FORM), this causes the switch statement to run another function, but this also creates 
a new instance of the
script, in which the variables from the older instance are not known.

I'm now working on a solution that uses the same form to pass on some data I need. A 
bit complex maybe, but I'll
leave the code cleaning for version 2.0 of my software :)
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Re: [PHP] One last kick at the cat

2001-10-28 Thread Imar de Vries

Henrik Hudson wrote:

 Inside your function define:

 global $server;
 global $pass;
 global $user;
 etc

 It is using variables insides it's own scope and unless you have use
 GLOBAL_VARIABLES defined in your php.config file, it won't go outside of it's
 scope to look for values, hence they are getting asigned NULL and you can't
 connect to a NULL DB :)

Looking at the content of this post and my post above this one, it seems like it
is global day/night again g
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[PHP] php.ini executable

2001-10-28 Thread jtjohnston

Has anyone made a Windows executable to configure the php.ini? ... just
asking, before I find myself doing it myself.



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[PHP] RE: It's ok

2001-10-28 Thread jdg117


Unsecured Visa or Mastercard with credit line up to $1000, 
Guaranteed! 
GO HERE! --
http://creditcardnow.com0to=4u=6@1089728774/-ci58MM4/



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[PHP] Create images jpeg

2001-10-28 Thread Luz Lopez

Hi All

I have installed package GD, I am creating images with imagejpeg, but when I 
load the browser a messager error appear:

ImageJpeg: No JPG support in this PHP build in

I read the GD readme and say:
 gd 1.8.3 creates PNG, JPEG and WBMP images, not
 GIF images. This is a good thing. PNG is a more compact format, and
 full compression is available. JPEG works well with photographic
 images, and is still more compatible with the major Web browsers
 than even PNG is.

I need to give format jpeg because is more work with more version of 
browser.

How can I do it?

Thanks in Advanced,

Regards,


_
Get your FREE download of MSN Explorer at http://explorer.msn.com/intl.asp


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Re: [PHP] Breaking a string

2001-10-28 Thread David Robley

On Fri, 26 Oct 2001 22:36, Dan McCullough wrote:
 I was looking to take a string like Dan or Dan is great and return it
 like

 D
 a
 n

 or

 D
 a
 n

 i
 s

 g
 r
 e
 a
 t

 is it the str function that does that and if so does someone have an
 example?

 thanks

You can dealt with the string as if it were an array of characters.
Or you could use substr to work your way through the string.
-- 
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CENTRE FOR INJURY STUDIES  Flinders University, SOUTH AUSTRALIA  

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Re: [PHP] Create images jpeg

2001-10-28 Thread speedboy

 ImageJpeg: No JPG support in this PHP build in

No jpeg support. Isn't it obvious?

Recompile php --with-jpeg-dir=/usr/local

For more information:

http://database.sourceforge.net/documentation/installing_apache_with_gd_zlib_png_jpg_tiff_pdf_support.html


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Re: [PHP] phpmyadmin is installed, now how to access it?

2001-10-28 Thread Moody


 I see all the files are name php3 rather than php. When I access the
 index.php3 of course it my browser doesn't know what to do so it asks if I
 want to download it.

Sounds like you need to add .php3 to your AddType directive in the
httpd.conf file
i.e.the line in httpd.conf that says:

AddType application/x-httpd-php .php

Should be changed to:

AddType application/x-httpd-php .php .php3

This should solve the problem with .php3 scripts not executing on your
server :-)
 Otherwise, if you want/have to change all the extensions to .php, you'll
have to change all the requires and includes in the phpMyAdmin scripts to
reflect these changes.



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[PHP] SSI

2001-10-28 Thread Gary

How do you get a SSI to work on a php page?

TIA
Gary


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Re: [PHP] Breaking a string

2001-10-28 Thread speedboy

 I was looking to take a string like Dan or Dan is great and return it
 like

 D
 a
 n...

http://www.php.net/manual/en/function.wordwrap.php


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Re: [PHP] php-mysql question

2001-10-28 Thread David Robley

On Fri, 26 Oct 2001 23:27, Gerard Onorato wrote:
 Hello,

 I am a recent return to the list. Wow has the traffic grown! This is
 awesome.

 I have a couple of questions and one may be a RTFM but I can't find the
 answer.

 #1) While I thought I was extremely familiar with the MYSQL functions
 available in PHP I found on e in a code snippet that I have not used
 before and can't find. It is simply MYSQL(dbname, querystring). On a
 *nix box with Apache it is returning a resource ID but on a w2k box
 with apache (or iss) it is returning nothing at all. It does execute
 the query however. Any ideas or any pointer as to where I can actually
 find this function would be appreciated! Thanks.

An older version of the docs here shows that mysql is available for 
downwards compatibility, from mysql_db_query, which is deprecated since 
4.06. Changing to mysql_query is recommended.

 #2) Does anyone know of a convention / conference which will have any
 PHP coverage in the North East?

Northeast of where :-)

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CENTRE FOR INJURY STUDIES  Flinders University, SOUTH AUSTRALIA  

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Re: [PHP] sending email to php script

2001-10-28 Thread David Robley

On Sat, 27 Oct 2001 03:23, JSheble wrote:
 A while ago an email came through here about how to parse out email
 message from a php script.  The thing that was mostly of interest to me
 is the ability to send an email to a php script, I guess through a
 sendmail alias?  I asked how to accomplish this, and never saw an
 answer come through.  So I'd like to ask again :o)

 Does anybody know what would be required or necessary to send an email
 to an address that would run a php script?

You say sendmail, so do it thusly:

Edit /etc/aliases and add a line like

phpmail: | /pathto/your/php/script

and run newaliases to update your alias database.

You'll also need to compile php as a standalone, and put as the first 
line of your php script

#!/path/to/php -q

Cheers
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CENTRE FOR INJURY STUDIES  Flinders University, SOUTH AUSTRALIA  

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Re: [PHP] SMTP

2001-10-28 Thread David Robley

On Sat, 27 Oct 2001 18:51, Lucas Chan wrote:
 Hi,

 I have PHP running on my Debian (unstable distribution) box.  I'm
 trying to generate an email via the mail() function.

 It keeps failing because I do not have a properly installed/configured
 SMTP daemon on my machine.  This is despite the fact that I have
 modified the SMTP variable in the php.ini file to point to my ISP's
 SMTP server.

 Has anyone else experienced this problem before?

 Regards,

 [ lucas ]

The *nix version of php expects to find a functional mail transport agent 
on the local host; the SMTP setting in the ini file is (or should be) 
clearly marked as Windows only.

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CENTRE FOR INJURY STUDIES  Flinders University, SOUTH AUSTRALIA  

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Re: [PHP] SMTP

2001-10-28 Thread Lucas Chan

 The *nix version of php expects to find a functional mail transport agent
 on the local host

Hrm.

Yeah.  I think that's kind've umm, I dunno silly.

Regards,

[ lucas ]



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Re: [PHP] SSI

2001-10-28 Thread Christian Dechery

At 19:04 28/10/01 -0500, Gary wrote:
How do you get a SSI to work on a php page?

you don't need SSI if you're running PHP... just use include()...

_
. Christian Dechery
. . Gaita-L Owner / Web Developer
. . http://www.webstyle.com.br
. . http://www.tanamesa.com.br


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Re: [PHP] SSI

2001-10-28 Thread Gary

Yes I do, it is to run a pre-exiting program. I figured it out. I was 
uing double quotes in the ssi and excaping them when echoing. I should 
of been using single quotes.

Thanks
Gary

Christian Dechery wrote:

 At 19:04 28/10/01 -0500, Gary wrote:
 
 How do you get a SSI to work on a php page?
 
 
 you don't need SSI if you're running PHP... just use include()...
 
 _
 . Christian Dechery
 . . Gaita-L Owner / Web Developer
 . . http://www.webstyle.com.br
 . . http://www.tanamesa.com.br
 


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[PHP] How to determine a valid Date

2001-10-28 Thread Carlos Fernando Scheidecker Antunes

Hello all,

Is there any built-in function to determine a valid date?

If there's not I will have to translate one that I've wrote with DrScheme to PHP.

I just want to save time :)

thanks again,

Carlos Fernando.


Linux User #207984




[PHP] feature sugestion

2001-10-28 Thread Ray Todd Stevens

A lot of visually based editors support embeded java scripts.  This 
can easily be used to make the system support php with one 
problem.  Most of these system use the concept that these scripts 
ignore html comments to help them ignore the code.  How about 
making the php engine ignore these to.  That is any string like !-- 
or //-- is treated as white space.

Ray Todd Stevens Specialists in Network and Security 
Consulting
Senior ConsultantSoftware audit service available
Stevens Services
Suite 21
3754 Old State Rd 37 N
Bedford, IN 47421
(812) 279-9394
[EMAIL PROTECTED]

Thought for the day:
Communist (n): one who has given up all hope
of becoming a Capitalist.


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[PHP] Problem appending data in a file with fopen(ftp://...,a)

2001-10-28 Thread Dave Létourneau

I am able to create the file when it is not already there but I got a file
exists error when I try to fopen it in append mode the second time.  I
wrote this to store a log of the traffic on my site (userid in a
cookie+timestamp) in a file.  Don't know if i'm using the good technique but
it's very frustrating.  I tried with 2 different FTP servers where I have
all the necessary rights.

Is it possible to solve this problem or it's a feature in PHP?

Dave Létourneau
[EMAIL PROTECTED]



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[PHP] now I can compile

2001-10-28 Thread Ray Todd Stevens

I asked for help because I could not compile php 4.  I now have this 
working thanks to several nifty helpers.  Thr problem was that in the 
src directory there is a directory for each version of linux, and then 
a symlink called linux to the version that is currently running.  This 
symlink had not been added some how or rather.  Got the proper 
link and everything is going great guns.

Thanks to all.

Ray Todd Stevens Specialists in Network and Security 
Consulting
Senior ConsultantSoftware audit service available
Stevens Services
Suite 21
3754 Old State Rd 37 N
Bedford, IN 47421
(812) 279-9394
[EMAIL PROTECTED]

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Advertising (n): the science of arresting the human
intelligence for long enough to get money from it.
   -- Stephen Leacock.


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Re: [PHP] Problem appending data in a file with fopen(ftp://...,a)

2001-10-28 Thread Kurt Lieber

On Sunday 28 October 2001 06:41 pm, you wrote:
 Is it possible to solve this problem or it's a feature in PHP?

If I understand your problem, you are trying to open the same file twice.  
I'm not sure why you would want to do that, but assuming you have a good 
reason, you need to make sure you fclose($filename) before you try to 
fopen($filename) again.  Otherwise, PHP maintains the file open for reading 
(and writing, if that's how you opened it.)

hth

--kurt 

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[PHP] Attention Die-Hard SEC Fans!

2001-10-28 Thread cdubbayou

Dear [EMAIL PROTECTED],

Are You A Crazed SEC Football or Sports Fan?

If you are, then go to: http://www.sectraditions.com to find out 
about the most comprehensive books on SEC sports ever written.

A Tailgater's Guide To SEC Football
and SEC Baseball History  Tradition

by sports writer Chris Warner

Forthcoming by November, 2001, SEC Basketball History  Tradition,
that has an afterword with Dale Brown

Visit http://www.sectraditions.com for more info.

THESE BOOKS MAKE GREAT GIFTS FOR ANY OCCASION!

Books can also be found in Barnes  Nobles, Books-A-Million  Amazon.com.

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Re: [PHP] feature sugestion

2001-10-28 Thread Kurt Lieber

On Sunday 28 October 2001 06:10 pm, Ray Todd Stevens wrote:
 How about
 making the php engine ignore these to.  That is any string like !--
 or //-- is treated as white space.

Um...maybe I don't understand your statement but php already has commenting 
built in.  Anything between /* and */ is ignored by the scripting engine.  
(just like !-- and -- in HTML)

--kurt

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Re: [PHP] Problem appending data in a file with fopen(ftp://...,a)

2001-10-28 Thread Dave Létourneau

I only fopen my file once...

My program checks if there is a specific session cookie.  If not (it's a new
user that browse the site) I set a cookie and try to store the unique ID of
this user (other cookie) in a file with a timestamp to track which user came
and when (+ nb of times...).  That's where I use my fopen() then I fclose
the file.  The fopen(..., a) creates the file if it's not already there
but once it's created, it cannot append a new line (User;timestamp) to this
file : Error : File exists.

:((


Kurt Lieber [EMAIL PROTECTED] a écrit dans le message news:
[EMAIL PROTECTED]
 On Sunday 28 October 2001 06:41 pm, you wrote:
  Is it possible to solve this problem or it's a feature in PHP?

 If I understand your problem, you are trying to open the same file twice.
 I'm not sure why you would want to do that, but assuming you have a good
 reason, you need to make sure you fclose($filename) before you try to
 fopen($filename) again.  Otherwise, PHP maintains the file open for
reading
 (and writing, if that's how you opened it.)

 hth

 --kurt



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Re: [PHP] phpmyadmin is installed, now how to access it?

2001-10-28 Thread Chip

On Sunday 28 October 2001 15:52, Moody wrote:
  I see all the files are name php3 rather than php. When I access the
  index.php3 of course it my browser doesn't know what to do so it asks if
  I want to download it.

 Sounds like you need to add .php3 to your AddType directive in the
 httpd.conf file
 i.e.the line in httpd.conf that says:

 AddType application/x-httpd-php .php

 Should be changed to:

 AddType application/x-httpd-php .php .php3

 This should solve the problem with .php3 scripts not executing on your
 server :-)
  Otherwise, if you want/have to change all the extensions to .php, you'll
 have to change all the requires and includes in the phpMyAdmin scripts to
 reflect these changes.

Interesting that it only worked after adding .php3 to the existing .php line. 
Earlier I had uncommented the lines just above that one which is almost 
identical except it is for .php3, but that didn't do the trick.

Thanks for the help,
--
Chip W.

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[PHP] Re: How to determine a valid Date

2001-10-28 Thread Julio Nobrega

checkdate();

http://www.php.net/manual/en/function.checkdate.php

--


  Julio Nobrega.

Um dia eu chego lá:
http://sourceforge.net/projects/toca

Carlos Fernando Scheidecker Antunes [EMAIL PROTECTED] wrote in
message 009e01c16013$d2627ec0$0a505ad1@Nando4">news:009e01c16013$d2627ec0$0a505ad1@Nando4...
Hello all,

Is there any built-in function to determine a valid date?

If there's not I will have to translate one that I've wrote with DrScheme to
PHP.

I just want to save time :)

thanks again,

Carlos Fernando.


Linux User #207984





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Re: [PHP] How to determine a valid Date

2001-10-28 Thread David Robley

On Mon, 29 Oct 2001 11:21, Carlos Fernando Scheidecker Antunes wrote:
 Hello all,

 Is there any built-in function to determine a valid date?

 If there's not I will have to translate one that I've wrote with
 DrScheme to PHP.

 I just want to save time :)

Quicker to ask online than look in the manual, is it?

http://www.php.net/manual/en/function.checkdate.php



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Re: [PHP] Problem appending data in a file with fopen(ftp://...,a)

2001-10-28 Thread David Robley

On Mon, 29 Oct 2001 13:59, Dave Létourneau wrote:
 I only fopen my file once...

 My program checks if there is a specific session cookie.  If not (it's
 a new user that browse the site) I set a cookie and try to store the
 unique ID of this user (other cookie) in a file with a timestamp to
 track which user came and when (+ nb of times...).  That's where I use
 my fopen() then I fclose the file.  The fopen(..., a) creates the
 file if it's not already there but once it's created, it cannot append
 a new line (User;timestamp) to this file : Error : File exists.

 :((

 Kurt Lieber [EMAIL PROTECTED] a écrit dans le message news:
 [EMAIL PROTECTED]

  On Sunday 28 October 2001 06:41 pm, you wrote:
   Is it possible to solve this problem or it's a feature in PHP?
 
  If I understand your problem, you are trying to open the same file
  twice. I'm not sure why you would want to do that, but assuming you
  have a good reason, you need to make sure you fclose($filename)
  before you try to fopen($filename) again.  Otherwise, PHP maintains
  the file open for

 reading

  (and writing, if that's how you opened it.)
 
  hth
 
  --kurt

This may be a 'feature' of your ftp target. There may be limitations on 
what you can do via ftp including overwrite existing files. If you have 
control of the box, or admin access, check /etc/ftpaccess if it is a *nix 
OS. About BillOS, I have no idea.

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David Robley  Techno-JoaT, Web Maintainer, Mail List Admin, etc
CENTRE FOR INJURY STUDIES  Flinders University, SOUTH AUSTRALIA  

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Re: [PHP] Problem appending data in a file with fopen(ftp://...,a)

2001-10-28 Thread Kurt Lieber

On Sunday 28 October 2001 07:29 pm, you wrote:
 I only fopen my file once...

 My program checks if there is a specific session cookie.  If not (it's a
 new user that browse the site) I set a cookie and try to store the unique
 ID of this user (other cookie) in a file with a timestamp to track which
 user came and when (+ nb of times...).  That's where I use my fopen() then
 I fclose the file.  The fopen(..., a) creates the file if it's not
 already there but once it's created, it cannot append a new line
 (User;timestamp) to this file : Error : File exists.

Aha -- I understand.  I also didn't see the first time that you're using FTP. 
 You can't fopen() a file for read/write through FTP.  You can do one, or the 
other, but not both.  

http://www.php.net/manual/en/function.fopen.php

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[PHP] MySQL command log

2001-10-28 Thread Richard Baskett

I've done it before, but I cant remember how to view the commands that have
been sent to MySQL.  I normally try not to ask MySQL questions here even
though it's pretty much a standard with PHP :)  But I have exhausted myself
in researching the problem and I hope one of you might have the answer.  A
friend had his server hacked and they thought it would be funny to change
the username and password to the mysql table in mysql plus a couple other
tables  We're hunting now ;)

Thanks ahead of time!

Rick


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Re: [PHP] MySQL command log

2001-10-28 Thread David Robley

On Mon, 29 Oct 2001 14:59, Richard Baskett wrote:
 I've done it before, but I cant remember how to view the commands that
 have been sent to MySQL.  I normally try not to ask MySQL questions
 here even though it's pretty much a standard with PHP :)  But I have
 exhausted myself in researching the problem and I hope one of you might
 have the answer.  A friend had his server hacked and they thought it
 would be funny to change the username and password to the mysql table
 in mysql plus a couple other tables  We're hunting now ;)

 Thanks ahead of time!

 Rick

If you have logging enabled for mysql, check that log. It might be in 
your mysql/data directory. Also check ~/.mysql_history for caommands ent 
via the mysql command line monitor.

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[PHP] Array's

2001-10-28 Thread De Necker Henri

Please help!

Im have been trying to get a multi-dimentional array for so time now and
dont seems to get a right!

I have the following :

while($row=db_range()){
  list($co_id,$surname,$init,$ba) = $row;

  $acid[$i] = array($a=array($co_id),
$b=array($surname,$init),  // does it work like
this ???
$c=array($ba)) ;

  $i++;
}//end while 1

I have 4 fields that i want to to put in an array and about 3000 records.
How can i list the fields in an array and retrive the values out of the
array

PLS help!



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[PHP] Re: Array's

2001-10-28 Thread _lallous

 $b=array($surname,$init),  // does it work
like
it does work like that, but you're creating an array of one item which is a
string holding to values comma seperated.
you can do this too:
 $b=array($surname,$init),  // does it work like
w/o the quotes.
and also no need to put quotes around the $b or $a.
and when you're storing one element no need to put it in an array like you
did for this:
 = array($a=array($co_id),
do directly:
array($a = $co_id, ...

 I have 4 fields that i want to to put in an array and about 3000 records.
 How can i list the fields in an array and retrive the values out of the
 array

$values = array();
$i =0;
while (getting the rows)
{
  list($id, $surname, $ba) = $row;
  $values[$i]['surname'] = $surname;
  $values[$i]['id'] = $id;
  $values[$i]['ba'] = $ba;
  $i++;
}

retrieve any element as:
$values[INDEX HERE]['surname'] for example.


De Necker Henri [EMAIL PROTECTED] wrote in message
3A8ED7A62794D311AA7700508B6164EC08DCA35E@SCPTS01">news:3A8ED7A62794D311AA7700508B6164EC08DCA35E@SCPTS01...
 Please help!

 Im have been trying to get a multi-dimentional array for so time now and
 dont seems to get a right!

 I have the following :

 while($row=db_range()){
   list($co_id,$surname,$init,$ba) = $row;

   $acid[$i] = array($a=array($co_id),
 $b=array($surname,$init),  // does it work
like
 this ???
 $c=array($ba)) ;

   $i++;
 }//end while 1

 I have 4 fields that i want to to put in an array and about 3000 records.
 How can i list the fields in an array and retrive the values out of the
 array

 PLS help!





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[PHP] Re: php.ini executable

2001-10-28 Thread _lallous

go for it...even if someone did a visual tool for that.

my question goes, has anyone made a *nix program to configure php.ini ? ;)
before i 

Jtjohnston [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Has anyone made a Windows executable to configure the php.ini? ... just
 asking, before I find myself doing it myself.





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[PHP] Re: Random

2001-10-28 Thread _lallous

$ceiling is too big.

try to do this and see:
echo getrandmax();
you might get 32767 as an output!

therefore, $ceiling must be = getrandmax();

try to scale down your floor and ceiling,
ie:
$max = $ceiling - $floor;
$random = rand(0, $max) + $floor;

Andrew Duck [EMAIL PROTECTED] wrote in message
005f01c15ea6$30375800$017f@localhost">news:005f01c15ea6$30375800$017f@localhost...
#Create Random number
  $floor = 10;
  $ceiling = 99;
  srand((double)microtime()*100);
  $random = rand($floor, $ceiling);

Warning: rand(): Invalid range: 10..99 in c:\my
documents\ezone\testing\signup2.php on line 49

Can someone please tell me where i went wonr gin this coding.

Thanks




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[PHP] RE: Array

2001-10-28 Thread De Necker Henri

Now i did the following :
My output is only null or blank values!,but my data is there!

 while($row=db_range()){
  list($co_id,$surname,$init,$ba) = $row;
  echo $co_id $surnamebr;  # This works perfect!
  $values[$i]['id'] = $co_id;
  $values[$i]['surname'] = $surname;
  $values[$i]['init'] = $init;
  $values[$i]['ba'] = $ba;
  $cid = $values[$i]['id'];
  echo $idbr  ;   # Doesnt wanna work
  list($a,$b,$c,$d) = $values[$i];
  echo $a ; # Doesnt wanna work
  $i++; 
}//end while 1

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[PHP] Re: Array

2001-10-28 Thread _lallous

   $values[$i]['id'] = $co_id;
you didn't initialize the $i did you?
should put $i =0; before the while loop.

   echo $idbr  ;   # Doesnt wanna work
what is $id ? i don't see it defined in your code, i see $cid instead.

   list($a,$b,$c,$d) = $values[$i];
sure won't work, try:
   list($a,$b,$c,$d) = each($values[$i]);


De Necker Henri [EMAIL PROTECTED] wrote in message
3A8ED7A62794D311AA7700508B6164EC08DCA35F@SCPTS01">news:3A8ED7A62794D311AA7700508B6164EC08DCA35F@SCPTS01...
 Now i did the following :
 My output is only null or blank values!,but my data is there!

  while($row=db_range()){
   list($co_id,$surname,$init,$ba) = $row;
   echo $co_id $surnamebr;  # This works perfect!
   $values[$i]['id'] = $co_id;
   $values[$i]['surname'] = $surname;
   $values[$i]['init'] = $init;
   $values[$i]['ba'] = $ba;
   $cid = $values[$i]['id'];
   echo $idbr  ;   # Doesnt wanna work
   list($a,$b,$c,$d) = $values[$i];
   echo $a ; # Doesnt wanna work
   $i++;
 }//end while 1



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[PHP] POSTing values to file

2001-10-28 Thread Michiel van Heusden

anybody help me please...

how can I open a file from php (something like require, but without closing
the php-file)
and then send some string to that file with POST
is thispossible?/?



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[PHP] Re: POSTing values to file

2001-10-28 Thread _lallous

see http://www.php.net/fopen

Michiel Van Heusden [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 anybody help me please...

 how can I open a file from php (something like require, but without
closing
 the php-file)
 and then send some string to that file with POST
 is thispossible?/?





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