php-general Digest 28 Oct 2006 22:12:24 - Issue 4427
Topics (messages 243787 through 243806):
Re: Shopping Cart
243787 by: chris smith
243788 by: CK
243791 by: Stut
243792 by: CK
243793 by: Greg Maruszeczka
243795 by: Ed Lazor
Re: heredoc
On Sat, 2006-10-28 at 14:49 +0900, Dave M G wrote:
PHP List,
I had a file upload script which was working fine. Then, because of
other needs, I changed my local Apache settings so that my local web
site directory structure behaved the same as they do on my web hosting
service.
What I
Hi,
Yes, I have and thought I was seeking the assistance of knowledgeable
colleagues . The solution researched does not offer the desired
features. I was not asking for code, but perhaps some solutions/
applications to explore.
CK
PS
I don't appreciate being scolded.
On Oct 27, 2006,
I don't appreciate being scolded.
Spend some time on the list and see how many times this question (or
type of question) gets asked and how many people actually do *some*
sort of work for themselves and you'll appreciate why people ask this
straight away.
If you had said I found product X Y
Hi,
I'm new to the list, and PHP. My assumption was others who have asked
similar questions, would have, like myself, done research. So I
thought no need to clarify. I'm aware these list are not a do my
homework solution. However, having received a verbally abusive
retort, when
On Thu, 26 Oct 2006 13:10:17 -0400, Robert Cummings wrote:
On Thu, 2006-10-26 at 11:43 +0200, clive wrote:
or you could write it likes this '
echo option value='$day' $selected $day /option;
much easier to read, but slightly more taxing on the server.
Also slightly more taxing on
On Thu, 26 Oct 2006 01:04:25 -0700, Paul Novitski wrote:
It's so interesting that some details bug some people and others bug
others. In an expression such as this:
echo 'option value=' . $day . '' . $selected . '' . $day
. '/option';
...I count eight transitions (instances
CK wrote:
I'm new to the list, and PHP. My assumption was others who have asked
similar questions, would have, like myself, done research. So I thought
no need to clarify. I'm aware these list are not a do my homework
solution. However, having received a verbally abusive retort, when
On Oct 28, 2006, at 8:52 AM, Stut wrote:
CK wrote:
I'm new to the list, and PHP. My assumption was others who have
asked similar questions, would have, like myself, done research.
So I thought no need to clarify. I'm aware these list are not a
do my homework solution. However, having
CK,
With the obligatory chastisement and ensuing defensiveness out of the
way :) you may want to check out Zen Cart (zen-cart.com) and see if it
meets your requirements.
Cheers,
G
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On Thu, 26 Oct 2006 01:04:25 -0700, Paul Novitski wrote:
It's so interesting that some details bug some people and others bug
others. In an expression such as this:
echo 'option value=' . $day . '' . $selected . '' . $day
. '/option';
...I count eight transitions (instances of
Be specific in stating what prior research has been done so that we
may help, if possible. Point noted.
Helping out further, you'll find that this rule applies to almost all
mailing lists.
2) We don't owe you anything. If you decide to go elsewhere for
help don't expect us to feel
Hi everyone.
I´m in a big doubt about uploading files ins a safe way.
I wont give permission for the web server user to write in some folder of my
system and then use move_uploaded_file function in order to keep it secure.
I was using ftp functions to do it but a get a new trouble, in some
Side note on the PHP FTP... I'm sure there are PHP FTP classes out
there for you to use... google php ftp class and you'll see a few
options to explore.
On Oct 28, 2006, at 10:47 AM, João Cândido de Souza Neto wrote:
Hi everyone.
I´m in a big doubt about uploading files ins a safe way.
Check php.ini session settings. There are some options in there for
you to use in your scripts. Set up scripts to test whether session
cookies are being saved and then route accordingly.
On Oct 28, 2006, at 12:41 PM, sit1way wrote:
Hey all.
I run a members-only hockey report that
When I use a normal single file upload form; both of these statements will
continue wether my form is empty or not, why?
if(!empty($_FILES)){
do som checking if its a jpg.
if not exit;
if(isset($_FILES)){
--
---
Børge
Kennel Arivene
http://www.arivene.net
---
--
PHP General
Hey all.
I run a members-only hockey report that relies on Session variable(s) to
grant/deny access to members-only site content.
Generally members have no trouble accessing members-only content once
logged-in to the site; however, since we have a few thousand members, I
frequently receive
Børge Holen wrote:
When I use a normal single file upload form; both of these statements will
continue wether my form is empty or not, why?
if(!empty($_FILES)){
do som checking if its a jpg.
if not exit;
if(isset($_FILES)){
because it IS set and NOT empty.
Ok. got that thanks.
But that leaves me a bit off to how to tell the script to leave it alone.
Is it possible to check it
or maby even better. Posible to not add an empty field in the submit.
The multifile submit I actually intended this script for, always send the
first field empty so later on
This could also be omitted with the help of NOT use
echo irritating reason
exit
Witch would leave the script running to BREAK on switch out of it all =D
YES. Not an elegant solution... but beats whatever I'm doing right now.
On Saturday 28 October 2006 23:46, Børge Holen wrote:
Ok. got that
Hi,
I have a MySQL database with a date field and a bunch of other fields. The
date field is in the format - 01/01/2006. What I want to do is query the
database and create a table that shows just the year and how many instances
of the year there is. I have been taxing my brain for a simple
Are you just trying to tell whether the form has been submitted? Or
are you just trying to validate form data?
-- verify form submitted -
if (isset($_POST)) {
// form submitted, process data
} else {
// display form
}
I'm trying to validate wether or not to run the image check script.
however empty the file field(s) are This script is started... how do I tell it
there is nothing here, go do other stuff.
for both multiupload forms and single upload forms since they're supposed to
share this script. My logic
On Sat, 2006-10-28 at 13:27 +0200, Nisse Engström wrote:
On Thu, 26 Oct 2006 13:10:17 -0400, Robert Cummings wrote:
On Thu, 2006-10-26 at 11:43 +0200, clive wrote:
or you could write it likes this '
echo option value='$day' $selected $day /option;
much easier to read, but
Robert Cummings wrote:
On Fri, 2006-10-27 at 13:51 +0200, Jochem Maas wrote:
range(1, 31)
Memory waster ;)
any idea as to what the damage is as compared to the classic for loop?
Given that a variable probably costs X and that any variable cane be
stored as Y in an array, and an array would
On Sun, 2006-10-29 at 01:32 +0200, Jochem Maas wrote:
Robert Cummings wrote:
On Fri, 2006-10-27 at 13:51 +0200, Jochem Maas wrote:
range(1, 31)
Memory waster ;)
any idea as to what the damage is as compared to the classic for loop?
Given that a variable probably costs X and that any
You posted this earlier and people, myself included, responded. I
don't know why you're reposting your original message rather than
reply to what we went. If you're not happy with the answers we
provided, please rephrase your question in order that have more luck
in answering it.
On
Use the mysql list :)
On Oct 28, 2006, at 3:01 PM, Beauford wrote:
Hi,
I have a MySQL database with a date field and a bunch of other
fields. The
date field is in the format - 01/01/2006. What I want to do is
query the
database and create a table that shows just the year and how many
Agreed, this should go to a MySQL list. But in the spirit of helping I think
the following should give you a good starting point.
SELECT `year`, COUNT(`year`) AS `count` FROM `tbl` GROUP BY `year` ASC
On 10/28/06, Ed Lazor [EMAIL PROTECTED] wrote:
Use the mysql list :)
On Oct 28, 2006, at
I posted this here as I figured I would need to manipulate this using PHP.
The code below doesn't quite work because the date is in the format of
05/05/2006. So I am getting totals for each date, not each year. I need the
totals for each year, regardless of the day or month. This is why I figured
Look into the MySQL YEAR() function to extract the year from a specific
date.
Start here:
http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html
On 10/28/06, Beauford [EMAIL PROTECTED] wrote:
I posted this here as I figured I would need to manipulate this using PHP.
The code
Try this:
if(!isset($_FILES['userfile']['name'])
|| $_FILES['userfile']['error'] == UPLOAD_ERR_NO_FILE) {
// the file was not uploaded
}
else {
// do your thing,the file has been uploaded
}
Børge Holen wrote:
When I use a normal single file upload form; both of
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