php-general Digest 22 Jun 2010 14:22:54 -0000 Issue 6810
php-general Digest 22 Jun 2010 14:22:54 - Issue 6810 Topics (messages 306302 through 306303): Re: Website content question 306302 by: Ernie Kemp Warning messages on web page. 306303 by: Mike Davies Administrivia: To subscribe to the digest, e-mail: php-general-digest-subscr...@lists.php.net To unsubscribe from the digest, e-mail: php-general-digest-unsubscr...@lists.php.net To post to the list, e-mail: php-gene...@lists.php.net -- ---BeginMessage--- I did put the PHP code. It kind of working. From: ahlin.h...@gmail.com [mailto:ahlin.h...@gmail.com] On Behalf Of Hans Åhlin Sent: June-21-10 9:43 PM To: Ernie Kemp Cc: PHP General List Subject: Re: [PHP] Website content question Did you include the necessary php code? ** Hans Åhlin Tel: +46761488019 icq: 275232967 http://www.kronan-net.com/ irc://irc.freenode.net:6667 - TheCoin ** 2010/6/21 Ernie Kemp ernie.k...@sympatico.ca Error! Filename not specified. This is not a direct PHP question but I will be using PHP in the website. I go to the php list because the wordpress forum does not respond to my questions and I know some of you have a lot of expertise in other areas than PHP. I wish to a my own pages to a theme. I created pages on my PC and added the code at the top of the page for wordpress to use the page for a template page. I than FTP’d the file over to web hosting server template location. Through wordpress “administrator” I added my file called homepage.php. I FTP’d my CSS, images, js and flash folders over to the template location. Went to load the website http://localhost/Michael-8701/site_flash/wordpress/wp-content/homepage.php and all I got was the html code displayed. I tried moving the folder around but same results. Read some docs on this but it’s not clear to me why this will not work. Please help this is new to me and I need to get over this wall. Thanks, /Ernie No virus found in this incoming message. Checked by AVG - www.avg.com Version: 9.0.829 / Virus Database: 271.1.1/2952 - Release Date: 06/21/10 14:36:00 ---End Message--- ---BeginMessage--- Hello, This is my first post to this list and I am a novice at php coding. I can generally follow the code but not good at writing from scratch. I have recently been trying to add to a website which was originally developed by someone else and is written in php and mysql. I am trying to add a 'news' section to the site. This would be similar to an existing 'projects' section so, rather than write it completely from scratch I copied the php and the database tables from the 'project' section and renamed 'project' to 'news'. This is working well except for one thing – I get the following error messages when looking at the detailed news item. This code does not produce this warning in the project section which is using the same php code Warning: reset() [function.reset]: Passed variable is not an array or object in /home/b23aadf/public_html/news/details.php on line 72 Warning: Variable passed to each() is not an array or object in /home/b23aadf/public_html/news/details.php on line 73 The relevant lines are : 72 reset($thumbsarray); 73 while (list($key, $value) = each($thumbsarray)) { The site is at www.aadf.co.uk and select 'News'. Is anyone able to help resolve this? If you let me know what further information you require I can provide it. Mike Davies -- Mike Davies Integra Web Design, Rhynie, By Huntly, AB54 4LS 01464 861535www.integrawebdesign.co.uk ---End Message---
php-general Digest 23 Jun 2010 03:59:06 -0000 Issue 6811
php-general Digest 23 Jun 2010 03:59:06 - Issue 6811 Topics (messages 306304 through 306325): Re: Warning messages on web page. 306304 by: Jim Lucas 306305 by: Shreyas Agasthya 306306 by: Daniel P. Brown 306307 by: Paul M Foster Stripping Characters 306308 by: Rick Dwyer 306309 by: David Èesal 306310 by: Ashley Sheridan 306311 by: Shreyas Agasthya 306312 by: Richard Quadling 306313 by: Nathan Nobbe 306314 by: Richard Quadling 306315 by: Shreyas Agasthya 306316 by: Rick Dwyer 306317 by: Ashley Sheridan 306318 by: Jim Lucas 306319 by: Rick Dwyer 306322 by: Rick Dwyer 306323 by: Ashley Sheridan 306324 by: Rick Dwyer Question about logins and locking 306320 by: James Colannino 306321 by: Tommy Pham In what scenario an extension of a class is useful? 306325 by: Camilo Sperberg Administrivia: To subscribe to the digest, e-mail: php-general-digest-subscr...@lists.php.net To unsubscribe from the digest, e-mail: php-general-digest-unsubscr...@lists.php.net To post to the list, e-mail: php-gene...@lists.php.net -- ---BeginMessage--- Mike Davies wrote: Hello, This is my first post to this list and I am a novice at php coding. I can generally follow the code but not good at writing from scratch. I have recently been trying to add to a website which was originally developed by someone else and is written in php and mysql. I am trying to add a 'news' section to the site. This would be similar to an existing 'projects' section so, rather than write it completely from scratch I copied the php and the database tables from the 'project' section and renamed 'project' to 'news'. This is working well except for one thing – I get the following error messages when looking at the detailed news item. This code does not produce this warning in the project section which is using the same php code Warning: reset() [function.reset]: Passed variable is not an array or object in /home/b23aadf/public_html/news/details.php on line 72 Warning: Variable passed to each() is not an array or object in /home/b23aadf/public_html/news/details.php on line 73 The relevant lines are : put a var_dump($thumbarray); right here and see what $thumbarray is 72 reset($thumbsarray); 73 while (list($key, $value) = each($thumbsarray)) { The site is at www.aadf.co.uk and select 'News'. Is anyone able to help resolve this? If you let me know what further information you require I can provide it. Mike Davies -- Jim Lucas A: Maybe because some people are too annoyed by top-posting. Q: Why do I not get an answer to my question(s)? A: Because it messes up the order in which people normally read text. Q: Why is top-posting such a bad thing? ---End Message--- ---BeginMessage--- Mike, A couple of things that I could understand reading carefully at the error. 1. reset takes an array as the input and perhaps your $thumbsarray is *not *an array? Reset will set the internal pointer to the start of the array. 2. Warning # 2 is very closely related to #1 since you can iterate on an array and not on a variable. 3. Just FYI - You can control the behavior should or not these warnings/notices/errors in your php.ini file. Do a quick google and you should be happy to see the result. Regards, Shreyas On Tue, Jun 22, 2010 at 7:47 PM, Mike Davies m...@integrawebdesign.co.ukwrote: Hello, This is my first post to this list and I am a novice at php coding. I can generally follow the code but not good at writing from scratch. I have recently been trying to add to a website which was originally developed by someone else and is written in php and mysql. I am trying to add a 'news' section to the site. This would be similar to an existing 'projects' section so, rather than write it completely from scratch I copied the php and the database tables from the 'project' section and renamed 'project' to 'news'. This is working well except for one thing – I get the following error messages when looking at the detailed news item. This code does not produce this warning in the project section which is using the same php code Warning: reset() [function.reset]: Passed variable is not an array or object in /home/b23aadf/public_html/news/details.php on line 72 Warning: Variable passed to each() is not an array or object in /home/b23aadf/public_html/news/details.php on line 73 The relevant lines are : 72 reset($thumbsarray); 73 while (list($key, $value) = each($thumbsarray)) { The site is at www.aadf.co.uk and select 'News'. Is anyone able to help resolve this? If you let me know what further information you require I can provide it. Mike Davies -- Mike Davies Integra Web Design, Rhynie, By Huntly, AB54 4LS
[PHP] Warning messages on web page.
Hello, This is my first post to this list and I am a novice at php coding. I can generally follow the code but not good at writing from scratch. I have recently been trying to add to a website which was originally developed by someone else and is written in php and mysql. I am trying to add a 'news' section to the site. This would be similar to an existing 'projects' section so, rather than write it completely from scratch I copied the php and the database tables from the 'project' section and renamed 'project' to 'news'. This is working well except for one thing – I get the following error messages when looking at the detailed news item. This code does not produce this warning in the project section which is using the same php code Warning: reset() [function.reset]: Passed variable is not an array or object in /home/b23aadf/public_html/news/details.php on line 72 Warning: Variable passed to each() is not an array or object in /home/b23aadf/public_html/news/details.php on line 73 The relevant lines are : 72 reset($thumbsarray); 73 while (list($key, $value) = each($thumbsarray)) { The site is at www.aadf.co.uk and select 'News'. Is anyone able to help resolve this? If you let me know what further information you require I can provide it. Mike Davies -- Mike Davies Integra Web Design, Rhynie, By Huntly, AB54 4LS 01464 861535www.integrawebdesign.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Warning messages on web page.
Mike Davies wrote: Hello, This is my first post to this list and I am a novice at php coding. I can generally follow the code but not good at writing from scratch. I have recently been trying to add to a website which was originally developed by someone else and is written in php and mysql. I am trying to add a 'news' section to the site. This would be similar to an existing 'projects' section so, rather than write it completely from scratch I copied the php and the database tables from the 'project' section and renamed 'project' to 'news'. This is working well except for one thing – I get the following error messages when looking at the detailed news item. This code does not produce this warning in the project section which is using the same php code Warning: reset() [function.reset]: Passed variable is not an array or object in /home/b23aadf/public_html/news/details.php on line 72 Warning: Variable passed to each() is not an array or object in /home/b23aadf/public_html/news/details.php on line 73 The relevant lines are : put a var_dump($thumbarray); right here and see what $thumbarray is 72 reset($thumbsarray); 73 while (list($key, $value) = each($thumbsarray)) { The site is at www.aadf.co.uk and select 'News'. Is anyone able to help resolve this? If you let me know what further information you require I can provide it. Mike Davies -- Jim Lucas A: Maybe because some people are too annoyed by top-posting. Q: Why do I not get an answer to my question(s)? A: Because it messes up the order in which people normally read text. Q: Why is top-posting such a bad thing? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Warning messages on web page.
Mike, A couple of things that I could understand reading carefully at the error. 1. reset takes an array as the input and perhaps your $thumbsarray is *not *an array? Reset will set the internal pointer to the start of the array. 2. Warning # 2 is very closely related to #1 since you can iterate on an array and not on a variable. 3. Just FYI - You can control the behavior should or not these warnings/notices/errors in your php.ini file. Do a quick google and you should be happy to see the result. Regards, Shreyas On Tue, Jun 22, 2010 at 7:47 PM, Mike Davies m...@integrawebdesign.co.ukwrote: Hello, This is my first post to this list and I am a novice at php coding. I can generally follow the code but not good at writing from scratch. I have recently been trying to add to a website which was originally developed by someone else and is written in php and mysql. I am trying to add a 'news' section to the site. This would be similar to an existing 'projects' section so, rather than write it completely from scratch I copied the php and the database tables from the 'project' section and renamed 'project' to 'news'. This is working well except for one thing – I get the following error messages when looking at the detailed news item. This code does not produce this warning in the project section which is using the same php code Warning: reset() [function.reset]: Passed variable is not an array or object in /home/b23aadf/public_html/news/details.php on line 72 Warning: Variable passed to each() is not an array or object in /home/b23aadf/public_html/news/details.php on line 73 The relevant lines are : 72 reset($thumbsarray); 73 while (list($key, $value) = each($thumbsarray)) { The site is at www.aadf.co.uk and select 'News'. Is anyone able to help resolve this? If you let me know what further information you require I can provide it. Mike Davies -- Mike Davies Integra Web Design, Rhynie, By Huntly, AB54 4LS 01464 861535www.integrawebdesign.co.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Regards, Shreyas Agasthya
Re: [PHP] Warning messages on web page.
On Tue, Jun 22, 2010 at 10:17, Mike Davies m...@integrawebdesign.co.uk wrote: [snip!] Warning: reset() [function.reset]: Passed variable is not an array or object in /home/b23aadf/public_html/news/details.php on line 72 [snip!] Is anyone able to help resolve this? If you let me know what further information you require I can provide it. Note the first error (quoted herein). That tells you that the variable ($thumbsarray) is not actually an array. How is it being instantiated and defined? -- /Daniel P. Brown UNADVERTISED DEDICATED SERVER SPECIALS SAME-DAY SETUP Just ask me what we're offering today! daniel.br...@parasane.net || danbr...@php.net http://www.parasane.net/ || http://www.pilotpig.net/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Warning messages on web page.
On Tue, Jun 22, 2010 at 03:17:53PM +0100, Mike Davies wrote: Hello, This is my first post to this list and I am a novice at php coding. I can generally follow the code but not good at writing from scratch. I have recently been trying to add to a website which was originally developed by someone else and is written in php and mysql. I am trying to add a 'news' section to the site. This would be similar to an existing 'projects' section so, rather than write it completely from scratch I copied the php and the database tables from the 'project' section and renamed 'project' to 'news'. This is working well except for one thing – I get the following error messages when looking at the detailed news item. This code does not produce this warning in the project section which is using the same php code Warning: reset() [function.reset]: Passed variable is not an array or object in /home/b23aadf/public_html/news/details.php on line 72 Warning: Variable passed to each() is not an array or object in /home/b23aadf/public_html/news/details.php on line 73 The relevant lines are : 72 reset($thumbsarray); 73 while (list($key, $value) = each($thumbsarray)) { The site is at www.aadf.co.uk and select 'News'. Is anyone able to help resolve this? If you let me know what further information you require I can provide it. Well formed question. Thanks for that. I see too many which aren't. I can't say why it's happening, but the $thumbsarray variable isn't getting built the way it should. You can insert a line just before your errors pop up like: ?php echo '$thumbsarray: '; print_r($thumbsarray); ? or ?php echo '$thumbsarray: '; echo var_dump($thumbsarray); ? or something similar. This will tell you if the variable is set and what type it has. I'm guessing it's not set. You'll have to look earlier to see where it should be built and isn't. Paul -- Paul M. Foster -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Stripping Characters
Hello List. I need to remove characters from a string and replace them with and underscore. So instead of having something like: $moditem = str_replace(--,_,$mystring); $moditem = str_replace(?,_,$mystring); $moditem = str_replace(!,_,$mystring); etc. For every possible character I can think of, is there a way to simply omit any character that is not an alpha character and not a number value from 0 to 9? --Rick -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Stripping Characters
Hello, can this resolve your problem? $trans = array( from = to, another = to); $moditem = StrTr($moditem, $trans); -- http://cz.php.net/manual/en/function.strtr.php David -Original Message- From: Rick Dwyer [mailto:rpdw...@earthlink.net] Sent: Tuesday, June 22, 2010 5:41 PM To: php-general@lists.php.net Subject: [PHP] Stripping Characters Hello List. I need to remove characters from a string and replace them with and underscore. So instead of having something like: $moditem = str_replace(--,_,$mystring); $moditem = str_replace(?,_,$mystring); $moditem = str_replace(!,_,$mystring); etc. For every possible character I can think of, is there a way to simply omit any character that is not an alpha character and not a number value from 0 to 9? --Rick -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Stripping Characters
On Tue, 2010-06-22 at 11:40 -0400, Rick Dwyer wrote: Hello List. I need to remove characters from a string and replace them with and underscore. So instead of having something like: $moditem = str_replace(--,_,$mystring); $moditem = str_replace(?,_,$mystring); $moditem = str_replace(!,_,$mystring); etc. For every possible character I can think of, is there a way to simply omit any character that is not an alpha character and not a number value from 0 to 9? --Rick Use preg_replace(), which allows you to use a regex to specify what you want to match: $find = '/[^a-z0-9]/i'; $replace = '_'; $new_string = preg_replace($find, $replace, $old_string); Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] Stripping Characters
Perhaps, ereg_replace(your regex, replacement_string, String $variable). Regards, Shreyas On Tue, Jun 22, 2010 at 9:10 PM, Rick Dwyer rpdw...@earthlink.net wrote: Hello List. I need to remove characters from a string and replace them with and underscore. So instead of having something like: $moditem = str_replace(--,_,$mystring); $moditem = str_replace(?,_,$mystring); $moditem = str_replace(!,_,$mystring); etc. For every possible character I can think of, is there a way to simply omit any character that is not an alpha character and not a number value from 0 to 9? --Rick -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Regards, Shreyas Agasthya
Re: [PHP] Stripping Characters
On 22 June 2010 16:44, Ashley Sheridan a...@ashleysheridan.co.uk wrote: On Tue, 2010-06-22 at 11:40 -0400, Rick Dwyer wrote: Hello List. I need to remove characters from a string and replace them with and underscore. So instead of having something like: $moditem = str_replace(--,_,$mystring); $moditem = str_replace(?,_,$mystring); $moditem = str_replace(!,_,$mystring); etc. For every possible character I can think of, is there a way to simply omit any character that is not an alpha character and not a number value from 0 to 9? --Rick Use preg_replace(), which allows you to use a regex to specify what you want to match: $find = '/[^a-z0-9]/i'; $replace = '_'; $new_string = preg_replace($find, $replace, $old_string); Thanks, Ash http://www.ashleysheridan.co.uk Watch out for white space in there. Tabs, spaces, new lines, etc. will also be converted to underscore. $find = '/[^\w\s]/i'; [^\w\s] Match a single character NOT present in the list below «[^\w\s]» A word character (letters, digits, and underscores) «\w» A whitespace character (spaces, tabs, and line breaks) «\s» A word character is any letter or digit or the underscore character, that is, any character which can be part of a Perl word. The definition of letters and digits is controlled by PCRE's character tables, and may vary if locale-specific matching is taking place. For example, in the fr (French) locale, some character codes greater than 128 are used for accented letters, and these are matched by \w. -- - Richard Quadling Standing on the shoulders of some very clever giants! EE : http://www.experts-exchange.com/M_248814.html EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498r=213474731 ZOPA : http://uk.zopa.com/member/RQuadling -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Stripping Characters
On Tue, Jun 22, 2010 at 9:40 AM, Rick Dwyer rpdw...@earthlink.net wrote: Hello List. I need to remove characters from a string and replace them with and underscore. So instead of having something like: $moditem = str_replace(--,_,$mystring); $moditem = str_replace(?,_,$mystring); $moditem = str_replace(!,_,$mystring); etc. For every possible character I can think of, is there a way to simply omit any character that is not an alpha character and not a number value from 0 to 9? check the docs, the first parameter may be an array of multiple needles, e.g. $moditem = str_replace(array('-', '?', '!'), '_', $mystring); you could likely do something more elegant w/ preg_replace() tho. -nathan
Re: [PHP] Stripping Characters
Then, when does one use ereg_replace as against preg_replace? I read from one the forums that preg_* is faster and ereg_* is if not faster but simpler. Is that it? Regards, Shreyas On Tue, Jun 22, 2010 at 9:58 PM, Richard Quadling rquadl...@gmail.comwrote: A word character is any letter or digit or the underscore character, that is, any character which can be part of a Perl word. The definition of letters and digits is controlled by PCRE's character tables, and may vary if locale-specific matching is taking place. For example, in the fr (French) locale, some character codes greater than 128 are used for accented letters, and these are matched by \w. The above becomes ... _A _word_ character is any letter or digit or the underscore character_ that is_ any character which can be part of a Perl _word__ The definition of letters and digits is controlled by PCRE_s character tables_ and may vary if locale_specific matching is taking place_ For example_ in the _fr_ _French_ locale_ some character codes greater than 128 are used for accented letters_ and these are matched by _w__ -- - Richard Quadling Standing on the shoulders of some very clever giants! EE : http://www.experts-exchange.com/M_248814.html EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498r=213474731 ZOPA : http://uk.zopa.com/member/RQuadling -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Regards, Shreyas Agasthya
Re: [PHP] Stripping Characters
Thanks to everyone who responded. Regarding the myriad of choices, isn't Ashley's, listed below, the one most like to guarantee the cleanest output of just letters and numbers? --Rick On Jun 22, 2010, at 11:44 AM, Ashley Sheridan wrote: On Tue, 2010-06-22 at 11:40 -0400, Rick Dwyer wrote: Use preg_replace(), which allows you to use a regex to specify what you want to match: $find = '/[^a-z0-9]/i'; $replace = '_'; $new_string = preg_replace($find, $replace, $old_string); Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] Stripping Characters
On Tue, 2010-06-22 at 13:35 -0400, Rick Dwyer wrote: Thanks to everyone who responded. Regarding the myriad of choices, isn't Ashley's, listed below, the one most like to guarantee the cleanest output of just letters and numbers? --Rick On Jun 22, 2010, at 11:44 AM, Ashley Sheridan wrote: On Tue, 2010-06-22 at 11:40 -0400, Rick Dwyer wrote: Use preg_replace(), which allows you to use a regex to specify what you want to match: $find = '/[^a-z0-9]/i'; $replace = '_'; $new_string = preg_replace($find, $replace, $old_string); Thanks, Ash http://www.ashleysheridan.co.uk It is clean, but as Richard mentioned, it won't handle strings outside of the traditional 128 ASCII range, so accented characters and the like will be converted to an underscore. Also, spaces might become an issue. However, if you are happy that your input won't go beyond the a-z0-9 range, then it should do what you need. Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] Stripping Characters
Shreyas Agasthya wrote: Then, when does one use ereg_replace as against preg_replace? I read from one the forums that preg_* is faster and ereg_* is if not faster but simpler. BUT, all the ereg_* has been depricated. DO NOT USE THEM if you want your code to work in the future. :) Is that it? Regards, Shreyas On Tue, Jun 22, 2010 at 9:58 PM, Richard Quadling rquadl...@gmail.comwrote: A word character is any letter or digit or the underscore character, that is, any character which can be part of a Perl word. The definition of letters and digits is controlled by PCRE's character tables, and may vary if locale-specific matching is taking place. For example, in the fr (French) locale, some character codes greater than 128 are used for accented letters, and these are matched by \w. The above becomes ... _A _word_ character is any letter or digit or the underscore character_ that is_ any character which can be part of a Perl _word__ The definition of letters and digits is controlled by PCRE_s character tables_ and may vary if locale_specific matching is taking place_ For example_ in the _fr_ _French_ locale_ some character codes greater than 128 are used for accented letters_ and these are matched by _w__ -- - Richard Quadling Standing on the shoulders of some very clever giants! EE : http://www.experts-exchange.com/M_248814.html EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498r=213474731 ZOPA : http://uk.zopa.com/member/RQuadling -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Jim Lucas A: Maybe because some people are too annoyed by top-posting. Q: Why do I not get an answer to my question(s)? A: Because it messes up the order in which people normally read text. Q: Why is top-posting such a bad thing? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Question about logins and locking
Hey everyone, I have a question about logins. Let's say that I want to allow each user account to login only once at a time. I would then need some kind of locking mechanism to make sure that the same user can't login again somewhere else until first logging off. What's a good way to achieve this? I want to be able to handle situations in which the user closes their browser without first logging off, where I would want to count that as a logout. Perhaps I could do some kind of periodic polling in Javascript, combined with a query to the database that sets a value when the user logs in and when the user logs out? I'm just looking for some conceptual ideas. Thanks everyone! James -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Question about logins and locking
-Original Message- From: James Colannino [mailto:ja...@colannino.org] Sent: Tuesday, June 22, 2010 2:29 PM To: php-general@lists.php.net Subject: [PHP] Question about logins and locking Hey everyone, I have a question about logins. Let's say that I want to allow each user account to login only once at a time. I would then need some kind of locking mechanism to make sure that the same user can't login again somewhere else until first logging off. What's a good way to achieve this? I want to be able to handle situations in which the user closes their browser without first logging off, where I would want to count that as a logout. Perhaps I could do some kind of periodic polling in Javascript, combined with a query to the database that sets a value when the user logs in and when the user logs out? I'm just looking for some conceptual ideas. Thanks everyone! James James, 1) Set an encrypted (to prevent hijacking and eavesdropping) cookie to expire when browser closes 2) Have a table in the DB backend to keep track if the user is logged in or not and when was the last time the validated user access your site (this gets updated when the user visit a link on your site by checking the cookie and the DB entry of the session ID) 3) Set your session timeout accordingly to you security requirement 4) Have a javascript on a timeout to self-logoff should the user is AFK longer than your session timeout. If another user or if the same user tries to login with a different browser, you can check the status of the user. If the user is logged in, you can deny it after the authentication. Should the user closes the browser without having to logoff, you can check when was the last time the user accessed your site and see if it's been longer than your session timeout. For security purposes, you can optionally send a courtesy email notifying that the user didn't logout properly since last accessed. This way, you can track whether if the user's system is compromised in some way or not. It all depends on what kind of application, service, user level access, and the strict security you require. Regards, Tommy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Stripping Characters
Hello again list. My code for stripping characters is below. I'm hoping to get feedback as to how rock solid it will provide the desired output under any circumstance: My output must look like this (no quotes): This-is-my-string-with-lots-of-junk-characters-in-it The code with string looks like this: $old_string = 'This is my $string -- with ƒ lots˙˙˙of junk characters in it¡™£¢∞§¶•ªºœ∑´®† ¥¨ˆøπ“‘ååß∂ƒ©˙∆˚¬…æ`__'; $find = '/[^a-z0-9]/i'; $replace = ' '; $new_string = preg_replace($find, $replace, $old_string); $new_string = preg_replace(/ {2,}/, -, $new_string); $new_string = preg_replace(/ {1,}/, -, $new_string); $new_string = rtrim($new_string, -); $new_string = ltrim($new_string, -); echo $new_string; Will the logic above capture and remove every non alpha numeric character and place a SINGLE hyphen between the non contiguous alpha numeric characters? Thanks for the help on this. --Rick On Jun 22, 2010, at 4:52 PM, Rick Dwyer wrote: On Jun 22, 2010, at 1:41 PM, Ashley Sheridan wrote: It is clean, but as Richard mentioned, it won't handle strings outside of the traditional 128 ASCII range, so accented characters and the like will be converted to an underscore. Also, spaces might become an issue. However, if you are happy that your input won't go beyond the a- z0-9 range, then it should do what you need. No, actually I'm fairly confident characters outside the 128 range are what are causing me problems now. So I will try Richard's method. Thanks to all. --Rick -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Stripping Characters
On Tue, 2010-06-22 at 20:03 -0400, Rick Dwyer wrote: Hello again list. My code for stripping characters is below. I'm hoping to get feedback as to how rock solid it will provide the desired output under any circumstance: My output must look like this (no quotes): This-is-my-string-with-lots-of-junk-characters-in-it The code with string looks like this: $old_string = 'This is my $string -- with ƒ lots˙˙˙of junk characters in it¡™£¢∞§¶•ªºœ∑´®† ¥¨ˆøπ“‘ååß∂ƒ©˙∆˚¬…æ`__'; $find = '/[^a-z0-9]/i'; $replace = ' '; $new_string = preg_replace($find, $replace, $old_string); $new_string = preg_replace(/ {2,}/, -, $new_string); $new_string = preg_replace(/ {1,}/, -, $new_string); $new_string = rtrim($new_string, -); $new_string = ltrim($new_string, -); echo $new_string; Will the logic above capture and remove every non alpha numeric character and place a SINGLE hyphen between the non contiguous alpha numeric characters? Thanks for the help on this. --Rick On Jun 22, 2010, at 4:52 PM, Rick Dwyer wrote: On Jun 22, 2010, at 1:41 PM, Ashley Sheridan wrote: It is clean, but as Richard mentioned, it won't handle strings outside of the traditional 128 ASCII range, so accented characters and the like will be converted to an underscore. Also, spaces might become an issue. However, if you are happy that your input won't go beyond the a- z0-9 range, then it should do what you need. No, actually I'm fairly confident characters outside the 128 range are what are causing me problems now. So I will try Richard's method. Thanks to all. --Rick You can remove the second line of code, as the third one is replacing what line 2 does anyway. Also, instead of a rtrim and ltrim, you can merge the two with a single call to trim, which will work on both ends of the string at once. Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] Stripping Characters
Very good. Thank you. --Rick On Jun 22, 2010, at 8:14 PM, Ashley Sheridan wrote: On Tue, 2010-06-22 at 20:03 -0400, Rick Dwyer wrote: Hello again list. My code for stripping characters is below. I'm hoping to get feedback as to how rock solid it will provide the desired output under any circumstance: My output must look like this (no quotes): This-is-my-string-with-lots-of-junk-characters-in-it The code with string looks like this: $old_string = 'This is my $string -- with ƒ lots˙˙˙of junk characters in it¡™£¢∞§¶•ªºœ∑´®† ¥¨ˆøπ“‘ååß∂ƒ©˙∆˚¬… æ`__'; $find = '/[^a-z0-9]/i'; $replace = ' '; $new_string = preg_replace($find, $replace, $old_string); $new_string = preg_replace(/ {2,}/, -, $new_string); $new_string = preg_replace(/ {1,}/, -, $new_string); $new_string = rtrim($new_string, -); $new_string = ltrim($new_string, -); echo $new_string; Will the logic above capture and remove every non alpha numeric character and place a SINGLE hyphen between the non contiguous alpha numeric characters? Thanks for the help on this. --Rick On Jun 22, 2010, at 4:52 PM, Rick Dwyer wrote: On Jun 22, 2010, at 1:41 PM, Ashley Sheridan wrote: It is clean, but as Richard mentioned, it won't handle strings outside of the traditional 128 ASCII range, so accented characters and the like will be converted to an underscore. Also, spaces might become an issue. However, if you are happy that your input won't go beyond the a- z0-9 range, then it should do what you need. No, actually I'm fairly confident characters outside the 128 range are what are causing me problems now. So I will try Richard's method. Thanks to all. --Rick You can remove the second line of code, as the third one is replacing what line 2 does anyway. Also, instead of a rtrim and ltrim, you can merge the two with a single call to trim, which will work on both ends of the string at once. Thanks, Ash http://www.ashleysheridan.co.uk
[PHP] In what scenario an extension of a class is useful?
Hello everybody :) I'm really intrigued on something... In what real-world applications could an extension of a class be really useful? Let's say I have this code: class foo { function hello_world($a) { echo 'foo hello world'; } function bye_world() { echo 'foo bye world'; } } class bar extends foo { function hello_world($a,$b) { echo 'bar hello world'; } } Point 1: Why not just overwrite the hello_world method in the foo class in the first place? Wouldn't that save code and possible incompatibility or consistency issues between the code you've already written and between the two classes ? (Assuming that you do some things based on the $a and $b values). Point 2: On the other hand, maybe I could apply different operations to both (e.g.: return 1 in foo and 2 in bar), without breaking the basic functionality already achieved in the foo class. (Maybe considering that I want to apply an update or patch to an already existing application, however, is this is the scenario, I should always fix the old code wherever I invoke the foo class which returns us to point 1). Point 3: Ok, maybe I don't want a specific class to be so huge and I separate it into pieces of classes. But then again, wouldn't it be simpler to just save some code and keeping only one file with the entire class? Is it just that or do I miss something else? I'm not saying it is useless, it sounds indeed fantastic to work with... but I just can't imagine in what real-world cases this would be useful. Greetings ! -- Mailed by: UnReAl4U - unreal4u ICQ #: 54472056 www1: http://www.chw.net/ www2: http://unreal4u.com/
Re: [PHP] Question about logins and locking
Tommy Pham wrote: 1) Set an encrypted (to prevent hijacking and eavesdropping) cookie to expire when browser closes 2) Have a table in the DB backend to keep track if the user is logged in or not and when was the last time the validated user access your site (this gets updated when the user visit a link on your site by checking the cookie and the DB entry of the session ID) 3) Set your session timeout accordingly to you security requirement 4) Have a javascript on a timeout to self-logoff should the user is AFK longer than your session timeout. If another user or if the same user tries to login with a different browser, you can check the status of the user. If the user is logged in, you can deny it after the authentication. Should the user closes the browser without having to logoff, you can check when was the last time the user accessed your site and see if it's been longer than your session timeout. For security purposes, you can optionally send a courtesy email notifying that the user didn't logout properly since last accessed. This way, you can track whether if the user's system is compromised in some way or not. It all depends on what kind of application, service, user level access, and the strict security you require. Thanks Tommy. That was very helpful, and some of it is similar to how I was thinking of doing it. James -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php