php-general Digest 20 Oct 2010 12:36:59 -0000 Issue 6997
php-general Digest 20 Oct 2010 12:36:59 - Issue 6997
Topics (messages 308865 through 308882):
Re: simple class constructor
308865 by: David McGlone
308866 by: David McGlone
308867 by: David Harkness
308868 by: Tommy Pham
308869 by: David McGlone
308870 by: Jay Blanchard
308871 by: David McGlone
308872 by: David McGlone
Re: Fiscal Years and Quarters
308873 by: admin.buskirkgraphics.com
308875 by: admin.buskirkgraphics.com
Possible foreach bug; seeking advice to isolate the problem
308874 by: Jonathan Sachs
308876 by: richard gray
308877 by: Gary
308881 by: Tommy Pham
Re: PHP stream_socket_client OpenSSL error (unknown ca)
308878 by: Richard
Unicode - Entitiy Encoding
308879 by: Sebastian Detert
Error handler script
308880 by: Teto
Re: Firs Day Of Week UNIX
308882 by: Richard Quadling
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---BeginMessage---
On Tue, 2010-10-19 at 16:53 -0700, Tommy Pham wrote:
-Original Message-
From: David McGlone [mailto:da...@dmcentral.net]
Sent: Tuesday, October 19, 2010 4:32 PM
To: php-gene...@lists.php.net
Subject: Re: [PHP] simple class constructor
On Tue, 2010-10-19 at 17:15 -0400, Paul M Foster wrote:
On Tue, Oct 19, 2010 at 04:12:51PM -0400, David McGlone wrote:
snip
You're trying to instantiate the class. And the way you're doing it
here is correct. When you do this, $test becomes an object of this
class. If you had another function (member) within the class called
myfunction(), you could run it this way (after you instantiate the
class):
$test-myfunction();
Basically I want to learn how I can (if it's possible with this
simple
code) is display the output on a different page.
I tried putting the line: $test=new simpleConstructer(); on the
index page and including the page the class is on, but it causes the
index page to go blank.
You've likely got an error you're not seeing. Fix this first. If the
file your class is in is syntactically correct, and you do
include simpleConstructerFile.php;
in your index.php file, it should flawlessly include the code. Then,
in your index.php, you do this:
$test = new simpleConstructer;
you should see the contents of the echo statement appear on the page.
So you're on the right track. You just need to find the error first.
Ah ha! Thank you! Your mention of an error, was spot on. notice below I
misspelled the class name but got the Object name correct.
Also at first I had the setup like this because it wasn't working and I
thought
I was doing it wrong: (this also added to my confusion)
myclass.php
class simpleConstructer {
function __construct() {
echo running the constructor;
}
}
index.php
require_once 'myclass.php';
$test = new simpleConstructor();
But once I fixed the error I put it all back in myclass.php like so:
myclass.php
class simpleConstructer {
function __construct() {
echo running the constructor;
}
}
$test = new simpleConstructor();
Now I am wondering what you meant when you said:
If you had another function (member) within the class called
myfunction(), you could run it this way (after you instantiate the
class):
$test-myfunction();
If you don't mind my asking, how would you take the above example and
change it to what you describe above?
class simpleConstructer {
function __construct() {
echo running the constructor;
}
function myFunction() {
echo 'this is another function/method within the class simpleConstructor';
}
}
$test = new simpleConstructor();
$test-myfunction();
Thank you Tommy.
Now it all comes together and I believe I understand now.
Does the code immediately after the __construct automatically run, but
when adding more methods to the class, they need to be called with the
$name-Object_name? Is my thinking correct?
--
Blessings
David M.
---End Message---
---BeginMessage---
On Tue, 2010-10-19 at 17:05 -0700, David Harkness wrote:
Note that you still have a typo, but maybe it's only in your email messages:
class simpleConstructer {
function __construct() {
echo running the constructor;
}
}
$test = new simpleConstructor();
The class is misspelled; it should be simpleConstructor. As a side note,
it's common convention to name classes with a leading capital letter, e.g.
SimpleConstructor. That's just convention, though, and I'm sure it differs
in some
Re: [PHP] Possible foreach bug; seeking advice to isolate the problem
On 20/10/2010 05:47, Jonathan Sachs wrote:
I've got a script which originally contained the following piece of
code:
foreach ( $objs as $obj ) {
do_some_stuff($obj);
}
When I tested it, I found that on every iteration of the loop the last
element of $objs was assigned the value of the current element. I was
able to step through the loop and watch this happening, element by
element.
Are you are using a 'referencing' foreach? i.e.
foreach ($objs as $obj) {
do_some_stuff($obj);
}
or is the above code a direct lift from your script?
Referencing foreach statements can cause problems as the reference to
the last array entry is persistent after the foreach loop has terminated
so any further foreach statements on the same array will overwrite the
previous reference which is still pointing to the last item.
Rich
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Re: [PHP] PHP stream_socket_client OpenSSL error (unknown ca)
Hello again,
Just to say that I have tested the script on php.net manual that
generates a cert and then trys to connect (slightly modified the end of
file [removing the while(true) section to just test the connection]) and
I get exactly the same error.
Source : http://php.net/manual/en/function.stream-socket-server.php
Here is the full test script :
?php
// Hello World! SSL HTTP Server.
// Tested on PHP 5.1.2-1+b1 (cli) (built: Mar 20 2006 04:17:24)
// Certificate data:
$dn = array(
countryName = UK,
stateOrProvinceName = Somerset,
localityName = Glastonbury,
organizationName = The Brain Room Limited,
organizationalUnitName = PHP Documentation Team,
commonName = Wez Furlong,
emailAddress = w...@example.com
);
// Generate certificate
$privkey = openssl_pkey_new();
$cert = openssl_csr_new($dn, $privkey);
$cert = openssl_csr_sign($cert, null, $privkey, 365);
// Generate PEM file
# Optionally change the passphrase from 'comet' to whatever you want,
or leave it empty for no passphrase
$pem_passphrase = 'comet';
$pem = array();
openssl_x509_export($cert, $pem[0]);
openssl_pkey_export($privkey, $pem[1], $pem_passphrase);
$pem = implode($pem);
// Save PEM file
$pemfile = './server.pem';
file_put_contents($pemfile, $pem);
$context = stream_context_create();
// local_cert must be in PEM format
stream_context_set_option($context, 'ssl', 'local_cert', $pemfile);
// Pass Phrase (password) of private key
stream_context_set_option($context, 'ssl', 'passphrase', $pem_passphrase);
stream_context_set_option($context, 'ssl', 'allow_self_signed', true);
stream_context_set_option($context, 'ssl', 'verify_peer', false);
// Create the server socket
$server = stream_socket_client('ssl://test.server.com:978', $errno,
$errstr,30, STREAM_CLIENT_CONNECT, $context);
if($server)
{
print('ok');
}
?
I still get the error :
Warning: stream_socket_client(): SSL operation failed with code 1.
OpenSSL Error messages:
error:14094418:SSL routines:SSL3_READ_BYTES:tlsv1 alert unknown ca in
/home/richard/test.php on line 44
I think this proves that it's not my certificate at fault but maybe a
problem with OpenSSL…
What do you think ?
Thank you,
Richard
Le 19/10/10 20:46, Richard a écrit :
No I didn't have a passphrase on the local cert when I created it.
I noticed that I only sent it to you and then sent the same message to
the list.
Thank you,
Richard
Le 19/10/10 20:28, Tommy Pham a écrit :
-Original Message-
From: Richard [mailto:php_l...@ghz.fr]
Sent: Tuesday, October 19, 2010 11:22 AM
To: Tommy Pham
Subject: Re: [PHP] PHP stream_socket_client OpenSSL error (unknown ca)
I left the pasphrase blank, I've just tried with a blank passphrase but
it
doesn't help.
?php
$context = stream_context_create();
stream_context_set_option($context, 'ssl', 'local_cert',
'./afnic.pem');
stream_context_set_option($context, 'ssl', 'passphrase', '');
stream_context_set_option($context, 'ssl', 'allow_self_signed',
TRUE);
stream_context_set_option($context, 'ssl', 'verify_peer', FALSE);
$connexion = stream_socket_client('ssl://epp.test.nic.fr:700',
$errno, $errstr, 30, STREAM_CLIENT_CONNECT, $context);
if($connexion) {
print('succes');
}
?
What I meant was that did you have a passphrase on your actual local
cert
when you created it?
PS: Please cc the list also so others would know what's going and can
help
troubleshoot and not reiterate what've been tried already.
Le 19/10/10 20:16, Tommy Pham wrote :
-Original Message-
From: Richard [mailto:php_l...@ghz.fr]
Sent: Tuesday, October 19, 2010 10:50 AM
To: php-general@lists.php.net
Subject: [PHP] PHP stream_socket_client OpenSSL error (unknown ca)
Hello,
I'm having some problems connecting to a server using the
following php
script :
?php
$context = stream_context_create();
stream_context_set_option($context, 'ssl', 'local_cert',
'./cert.pem');
stream_context_set_option($context, 'ssl', 'allow_self_signed',
TRUE);
stream_context_set_option($context, 'ssl', 'verify_peer', FALSE);
$ctn = stream_socket_client('ssl://distant.server.com:987',
$errno,
$errstr,
30, STREAM_CLIENT_CONNECT, $context);
if($ctn) {
print('Connected !');
}
?
Just curious,
'passphrase string
Passphrase with which your local_cert file was encoded' quoted from
[1].
Regards,
Tommy
[1] http://us3.php.net/manual/en/context.ssl.php
cert.pem is a self signed certificate that I generated a few days
ago,
it
contains both RSA Key and Certificate and I have supplied the
certificate
to
the distant server.
When I launch the script I get the following errors :
Warning: stream_socket_client(): SSL operation failed with code 1.
OpenSSL Error messages:
error:14094418:SSL routines:SSL3_READ_BYTES:tlsv1 alert unknown ca in
/path/to/my/test.php on line 7
As it is a self signed certificate there is no CA so I added the two
lines
:
stream_context_set_option($context, 'ssl', 'allow_self_signed',
TRUE);
stream_context_set_option($context, 'ssl', 'verify_peer',
[PHP] Unicode - Entitiy Encoding
Hi all, I'm stuck with this problem: I am trying to convert a text with any kind of unicode characters to its octet and entity equivalents. For example: Ë is #203; as octet and Euml; as entity Đ is #272; as octet and Dstrok; as entity My code works fine for some characters ( Ë works fine, but Đ fails at entity encoding). Do you have a hint, how to solve this? I try to get the octet encoding with mb_encode_numericentity which works fine for everything $convmap = array( 0x22, 0x22, 0, 0x, # 0x26, 0x27, 0, 0x, # ' 0x3c, 0x3c, 0, 0x, # 0x3d, 0x3d, 0, 0x, # 0x80, 0x, 0, 0x, ); $oct_string = mb_encode_numericentity($test, $convmap, 'UTF-8'); I try to get all entity encodings with htmlentities $entity_string = htmlentities($test, ENT_QUOTES, 'UTF-8'); But that fails for some characters like Đ. Is there a better way to get all entity encodings? Thanks, Sebastian -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Error handler script
Hi, I've been wondering if there was any php project focusing on providing a neat php error handler ? Up to now, I've been coding mine but I've seen videos on the web where a guy was using a really impressive php error_handler. Of course I could code it but if there was something generic I could use in different projets,that could be useful. Thx for any tip matt -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Re: Possible foreach bug; seeking advice to isolate the problem
-Original Message-
From: Gary [mailto:php-gene...@garydjones.name]
Sent: Tuesday, October 19, 2010 11:38 PM
To: php-general@lists.php.net
Subject: [PHP] Re: Possible foreach bug; seeking advice to isolate the
problem
Jonathan Sachs wrote:
I've got a script which originally contained the following piece of
code:
foreach ( $objs as $obj ) {
do_some_stuff($obj);
}
When I tested it, I found that on every iteration of the loop the last
element of $objs was assigned the value of the current element.
I only had a few minutes to look at it, but here is my 2 Euro cents.
It only occurs when you have previously done
,
| foreach ( $objs as $obj ) {
|//anything or nothing here
| }
`
as described in the documentation.
That leaves me with the question: what is going wrong with foreach?
I'm trying to either demonstrate that it's my error, not the PHP
engine's, or isolate the problem in a small script that I can submit
with a bug report.
From the post you reference in the manual's comments:
$a = array('a', 'b','c');
foreach($a as $row){
//you don't have to do anything here
}
print_r($a);
foreach($a as $row){
echo br /.$row;
}
print_r($a);
This suffices.
I tried to eliminate the database by doing a var_export of the array
after I built it, then assigning the exported expression to a variable
immediately before the foreach. That broke the bug -- the loop
behaved correctly.
Yup. I guess whatever database code used previously was doing the
equivalent of the first foreach in the previous code snippet.
Can anyone make suggestions on this -- either insights into what's
wrong, or suggestions for producing a portable, reproducible example?
Better. I can tell you how to solve it:
$a = array('a', 'b','c');
foreach($a as $row){
//you don't have to do anything here
}
unset($row); // THIS IS KEY!
Shouldn't that be $row = null since unset will remove the last value, not
just removing the variable also, from the array whereas the $row = null will
tell the reference pointer that it doesn't point to a value.
print_r($a);
foreach($a as $row){
echo br /.$row;
}
print_r($a);
I admit though, it's not obvious, even from reading the manual, and is
definitely a bug in the sense it is unexpected behaviour. Documenting it
and calling it a feature is appalling.
Regards,
Tommy
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Re: [PHP] Firs Day Of Week UNIX
On 19 October 2010 14:59, Don Wieland d...@dwdataconcepts.com wrote:
Hi gang,
I need a bailout.
I have a fields called sys_first_day_of_week and the user can select one
value which will be from a menu with these options:
Monday
Tuesday
Wednesday
Thursday
Friday
Saturday
Sunday
Based on this Preference and TODAYS DATE, I want to calculate the first
day of the week.
So if my preference is Monday and Today's date is 10/19/2010, I want to
return a value of: 1287374400 (which is 10/18/2010)
if my preference is Wednesday and Today's date is 10/19/2010, I want to
return a value of: 1286942400 (which is 10/13/2010)
Appreciate any help.
Don Wieland
D W D a t a C o n c e p t s
~
d...@dwdataconcepts.com
Direct Line - (949) 336-4828
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Developer Support Plan at:
http://www.dwdataconcepts.com/DevSup.html
Appointment 1.0v9 - Powerful Appointment Scheduling for FileMaker Pro 9 or
higher
http://www.appointment10.com
For a quick overview -
http://www.appointment10.com/Appt10_Promo/Overview.html
?php
echo date('r', strtotime('-1 week', strtotime('next sunday'))); //
Sun, 17 Oct 2010 00:00:00 +0100
echo date('r', strtotime('-1 week', strtotime('next monday'))); //
Mon, 18 Oct 2010 00:00:00 +0100
echo date('r', strtotime('-1 week', strtotime('next tuesday'))); //
Tue, 19 Oct 2010 00:00:00 +0100
echo date('r', strtotime('-1 week', strtotime('next wednesday'))); //
Wed, 20 Oct 2010 00:00:00 +0100
echo date('r', strtotime('-1 week', strtotime('next thursday'))); //
Thu, 14 Oct 2010 00:00:00 +0100
echo date('r', strtotime('-1 week', strtotime('next friday'))); //
Fri, 15 Oct 2010 00:00:00 +0100
echo date('r', strtotime('-1 week', strtotime('next saturday'))); //
Sat, 16 Oct 2010 00:00:00 +0100
?
Take 1 week off the next day that they want. If today is the start of
the week, then today will be returned.
--
Richard Quadling
Twitter : EE : Zend
@RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY
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[PHP] Re: Possible foreach bug; seeking advice to isolate the problem
On Wed, 20 Oct 2010 08:37:55 +0200, php-gene...@garydjones.name (Gary)
wrote:
Better. I can tell you how to solve it:
$a = array('a', 'b','c');
foreach($a as $row){
//you don't have to do anything here
}
unset($row); // THIS IS KEY!
print_r($a);
foreach($a as $row){
echo br /.$row;
}
print_r($a);
I don't quite I follow this. I'll have to try it when I have time (I
hope later today) to understand what you're proposing.
Unfortunately it won't work in this, for one or two reasons.
The first possible reason is that I'm not referencing the as
variable with an ampersand. If I'd have to add one to fix this
problem, it might cause other problems.
The second (definite) reason is that I can't read the array
destructively (with an unset). The problem occurs in code that is
preparing the array for later read-only use, so that would be
self-defeating!
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[PHP] Weird Behavior
Little help please ;) $CD = 1287583899 $q1s = 1283313600 $q1e = 1291093200 $q2s = 1291179600 $q2e = 1298869200 $q3s = 1298955600 $q3e = 1306814400 $q4s = 1306900800 $q4e = 1314763200 Why does the following not return the value 1 in the $qCur var // Current Quarter if($CD = $q1s $CD = $q1e) $qCur = 1; if($CD = $q2s $CD = $q2e) $qCur = 2; if($CD = $q3s $CD = $q3e) $qCur = 3; if($CD = $q4s $CD = $q4e) $qCur = 4; it returns 4 Don Wieland -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Weird Behavior
On Wed, Oct 20, 2010 at 10:35, Don Wieland d...@dwdataconcepts.com wrote: Little help please ;) $CD = 1287583899 $q1s = 1283313600 $q1e = 1291093200 $q2s = 1291179600 $q2e = 1298869200 $q3s = 1298955600 $q3e = 1306814400 $q4s = 1306900800 $q4e = 1314763200 Why does the following not return the value 1 in the $qCur var // Current Quarter if($CD = $q1s $CD = $q1e) $qCur = 1; if($CD = $q2s $CD = $q2e) $qCur = 2; if($CD = $q3s $CD = $q3e) $qCur = 3; if($CD = $q4s $CD = $q4e) $qCur = 4; it returns 4 That will return 1 if you add semicolons to the end of your variable definition block lines. Otherwise you'll get an unexpected T_VARIABLE error. In fact, I just tested it and it returned 1 as expected. -- /Daniel P. Brown Network Infrastructure Manager Documentation, Webmaster Teams http://www.php.net/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Weird Behavior
On Wed, Oct 20, 2010 at 07:35:26AM -0700, Don Wieland wrote: Little help please ;) $CD = 1287583899 $q1s = 1283313600 $q1e = 1291093200 $q2s = 1291179600 $q2e = 1298869200 $q3s = 1298955600 $q3e = 1306814400 $q4s = 1306900800 $q4e = 1314763200 Why does the following not return the value 1 in the $qCur var // Current Quarter if($CD = $q1s $CD = $q1e) $qCur = 1; if($CD = $q2s $CD = $q2e) $qCur = 2; if($CD = $q3s $CD = $q3e) $qCur = 3; if($CD = $q4s $CD = $q4e) $qCur = 4; it returns 4 No, $qCur is set to 1. You've forgot the semicolons if you're testing with this. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Weird Behavior
it returns 1 for me. Did you put the simicolon after the values? $CD = 1287583899; $q1s = 1283313600; $q1e = 1291093200; $q2s = 1291179600; $q2e = 1298869200; $q3s = 1298955600; $q3e = 1306814400; $q4s = 1306900800; $q4e = 1314763200; -Original Message- From: Don Wieland [mailto:d...@dwdataconcepts.com] Sent: Wednesday, October 20, 2010 9:35 AM To: php-general@lists.php.net Subject: [PHP] Weird Behavior Little help please ;) $CD = 1287583899 $q1s = 1283313600 $q1e = 1291093200 $q2s = 1291179600 $q2e = 1298869200 $q3s = 1298955600 $q3e = 1306814400 $q4s = 1306900800 $q4e = 1314763200 Why does the following not return the value 1 in the $qCur var // Current Quarter if($CD = $q1s $CD = $q1e) $qCur = 1; if($CD = $q2s $CD = $q2e) $qCur = 2; if($CD = $q3s $CD = $q3e) $qCur = 3; if($CD = $q4s $CD = $q4e) $qCur = 4; it returns 4 Don Wieland -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Calendar Logic Help
I'm having problems getting my head around some login for a calendar. Specifically, the problem is drawing weekly views for events that span multiple days. I've gotten it so that if an event starts in the week being viewed, the days draw correctly for the remainder of the week. However, if the event goes into the next week, its start date is now outside my date range and so it doesn't display. I know how to say the logic, I'm not sure how to write it! The logic would be: if any date between the start and end dates of the event are within the week being displayed, show the event. I'd like to put the logic into my MySQL query so I don't have to get all events from the calendar to see what should be displayed. Any ideas? Thanks! Floyd -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Calendar Logic Help
-Original Message- From: Floyd Resler [mailto:fres...@adex-intl.com] Sent: Wednesday, October 20, 2010 9:17 AM To: PHP Subject: [PHP] Calendar Logic Help I'm having problems getting my head around some login for a calendar. Specifically, the problem is drawing weekly views for events that span multiple days. I've gotten it so that if an event starts in the week being viewed, the days draw correctly for the remainder of the week. However, if the event goes into the next week, its start date is now outside my date range and so it doesn't display. I know how to say the logic, I'm not sure how to write it! The logic would be: if any date between the start and end dates of the event are within the week being displayed, show the event. I'd like to put the logic into my MySQL query so I don't have to get all events from the calendar to see what should be displayed. Any ideas? Thanks! Floyd It's hard to give you hints without knowing some actual PHP code and SQL table columns but here goes: PHP logic: $event['startDate'] = $weekEnd $event['endDate'] = $weekStart Query logic: SELECT * FROM event_table WHERE `start_date` = @weekEnd and `end_date` = @weekStart week* is the week being viewed. You may have to use the DateTime class or one of the date_* functions to compare the date for the PHP logic. @ is the input query parameter. This assumes you have table columns for the event: start_date end_date. Adjust the query as needed for multi table joins. Regards, Tommy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Possible foreach bug; seeking advice to isolate the problem
On Wed, Oct 20, 2010 at 5:00 AM, Tommy Pham tommy...@gmail.com wrote: Shouldn't that be $row = null since unset will remove the last value, not just removing the variable also, from the array whereas the $row = null will tell the reference pointer that it doesn't point to a value. No, that would assign null to the last array element. References allow you to assign any value--including null--to the container they reference. Unsetting a reference breaks the reference without affecting whatever it references. $x = 5; $y = $x; $y = null; print_r($x); var_dump($x); -- NULL David
Re: [PHP] Calendar Logic Help
On Oct 20, 2010, at 12:47 PM, Tommy Pham wrote: -Original Message- From: Floyd Resler [mailto:fres...@adex-intl.com] Sent: Wednesday, October 20, 2010 9:17 AM To: PHP Subject: [PHP] Calendar Logic Help I'm having problems getting my head around some login for a calendar. Specifically, the problem is drawing weekly views for events that span multiple days. I've gotten it so that if an event starts in the week being viewed, the days draw correctly for the remainder of the week. However, if the event goes into the next week, its start date is now outside my date range and so it doesn't display. I know how to say the logic, I'm not sure how to write it! The logic would be: if any date between the start and end dates of the event are within the week being displayed, show the event. I'd like to put the logic into my MySQL query so I don't have to get all events from the calendar to see what should be displayed. Any ideas? Thanks! Floyd It's hard to give you hints without knowing some actual PHP code and SQL table columns but here goes: PHP logic: $event['startDate'] = $weekEnd $event['endDate'] = $weekStart Query logic: SELECT * FROM event_table WHERE `start_date` = @weekEnd and `end_date` = @weekStart week* is the week being viewed. You may have to use the DateTime class or one of the date_* functions to compare the date for the PHP logic. @ is the input query parameter. This assumes you have table columns for the event: start_date end_date. Adjust the query as needed for multi table joins. Regards, Tommy That worked perfect! Thanks! Floyd -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Possible foreach bug; seeking advice to isolate the problem
On Wed, Oct 20, 2010 at 10:44 AM, David Harkness davi...@highgearmedia.com wrote: On Wed, Oct 20, 2010 at 5:00 AM, Tommy Pham tommy...@gmail.com wrote: Shouldn't that be $row = null since unset will remove the last value, not just removing the variable also, from the array whereas the $row = null will tell the reference pointer that it doesn't point to a value. No, that would assign null to the last array element. References allow you to assign any value--including null--to the container they reference. Unsetting a reference breaks the reference without affecting whatever it references. $x = 5; $y = $x; $y = null; print_r($x); var_dump($x); -- NULL David hmm.. About 8-9 years ago I did a project where I used the reference in a foreach loop as the OP. unset not only remove the variable but also the value in the array. I tried several methods at that time and ended up assigning null to get what I wanted without modifying the array. I'll have to dig up that project later to see. Thanks, Tommy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] I need some thoughts on code duplication and separation
Hi. I am working on a small system where I am both trying to avoid code duplication and at the same time I am trying to keep the presentation logic separated from the application logic. I am using sessions and are avoiding headers already sent problem by keeping the HTML out of the application. For example, I would like to have a common header.php file, but it is difficult to create this since one file needs to have some specific Javascript located in the head /head tags, but the other files doesn't need this. Another file needs to have a specific onload call in the body tag, while yet another file also needs to have an onload call, but with different attributes. I have been looking around in other systems to see what kinds of solutions are being used - as inspiration. I have been thinking about the following solutions: 1. Create only ONE header.php file that contains a lot of conditionals depending on what file is including it - the output of HTML/Javascript changes. I believe this would turn into a very ugly hack. Difficult to maintain. 2. Create a HTML generating class with a set of methods that each contains an adequate amount of parameters. Each method maintains its own HTML tag. For example, docType($type) would generate the doctype specification. I believe this is a cleaner solution, but the problem with code duplication isn't avoided. Some of the presentation logic contains conditionals and the HTML changes when the conditional changes, hence the header content changes, but the doctype, html, and head doesn't necessarily change and they would get duplicated a couple of times in some files. 3. Avoid the problem all together, use output buffering and completely forget about separation between application and presentation. I hope I make sense. Any thoughts on these kinds of problems? Best regards. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] I need some thoughts on code duplication and separation
On Thu, 2010-10-21 at 04:05 +0200, Rico Secada wrote: Hi. I am working on a small system where I am both trying to avoid code duplication and at the same time I am trying to keep the presentation logic separated from the application logic. I am using sessions and are avoiding headers already sent problem by keeping the HTML out of the application. For example, I would like to have a common header.php file, but it is difficult to create this since one file needs to have some specific Javascript located in the head /head tags, but the other files doesn't need this. Another file needs to have a specific onload call in the body tag, while yet another file also needs to have an onload call, but with different attributes. I have been looking around in other systems to see what kinds of solutions are being used - as inspiration. I have been thinking about the following solutions: 1. Create only ONE header.php file that contains a lot of conditionals depending on what file is including it - the output of HTML/Javascript changes. I believe this would turn into a very ugly hack. Difficult to maintain. 2. Create a HTML generating class with a set of methods that each contains an adequate amount of parameters. Each method maintains its own HTML tag. For example, docType($type) would generate the doctype specification. I believe this is a cleaner solution, but the problem with code duplication isn't avoided. Some of the presentation logic contains conditionals and the HTML changes when the conditional changes, hence the header content changes, but the doctype, html, and head doesn't necessarily change and they would get duplicated a couple of times in some files. 3. Avoid the problem all together, use output buffering and completely forget about separation between application and presentation. I hope I make sense. Any thoughts on these kinds of problems? sounds like a job for smarty http://www.smarty.net/ I've used smarty and it's nice. -- Blessings David M. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] I need some thoughts on code duplication and separation
-Original Message- From: David McGlone [mailto:da...@dmcentral.net] Sent: Wednesday, October 20, 2010 7:59 PM To: php-general@lists.php.net Subject: Re: [PHP] I need some thoughts on code duplication and separation On Thu, 2010-10-21 at 04:05 +0200, Rico Secada wrote: Hi. I am working on a small system where I am both trying to avoid code duplication and at the same time I am trying to keep the presentation logic separated from the application logic. I am using sessions and are avoiding headers already sent problem by keeping the HTML out of the application. For example, I would like to have a common header.php file, but it is difficult to create this since one file needs to have some specific Javascript located in the head /head tags, but the other files doesn't need this. Another file needs to have a specific onload call in the body tag, while yet another file also needs to have an onload call, but with different attributes. I have been looking around in other systems to see what kinds of solutions are being used - as inspiration. I have been thinking about the following solutions: 1. Create only ONE header.php file that contains a lot of conditionals depending on what file is including it - the output of HTML/Javascript changes. I believe this would turn into a very ugly hack. Difficult to maintain. 2. Create a HTML generating class with a set of methods that each contains an adequate amount of parameters. Each method maintains its own HTML tag. For example, docType($type) would generate the doctype specification. I believe this is a cleaner solution, but the problem with code duplication isn't avoided. Some of the presentation logic contains conditionals and the HTML changes when the conditional changes, hence the header content changes, but the doctype, html, and head doesn't necessarily change and they would get duplicated a couple of times in some files. 3. Avoid the problem all together, use output buffering and completely forget about separation between application and presentation. I hope I make sense. Any thoughts on these kinds of problems? sounds like a job for smarty http://www.smarty.net/ I've used smarty and it's nice. -- Blessings David M. Thanks David! I was looking for something like that too! Regards, Tommy -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
