Hi list!
Yesterday I've installed PHP 4.3.4 and Apache 1.3.29
on my Linux Mandrake 9.1 machine with a standard
procedure:
1. cd apache_1.3.29
2. ./configure
3. cd ../php-4.3.4
4. ./configure --with-apache=../apache_1.3.29
--enable-track-vars make make install
5. cd ../apache_1.3.29
6. ./configure
--activate-module=src/modules/php4/libphp4.a
7. make make install
8. cd ../php-4.3.4
9. cp php.ini-dist /usr/local/lib/php.ini
10. In httpd.conf file: AddType
application/x-httpd-php .php
I've encounterd a problem with this snippet of code,
where I fill a form and I pass the data to a php page
that should visualize it. Here is the code:
//Login.php
html
head
titleTEST/title
/head
form method=post action=second.php
brbrbr
NAME : input type=text name=ident
br
PASSWORD :input type=password name=psw
br
input type=submit name=Submit value=Submit
/form
/body
/html
//second.php
?php
echo NAME = $ident br PASSWORD = $psw;
?
When I execute this code in my web page
http://members.lycos.co.uk/ippo80/Login.php, or in
another Apache server with PHP-4.2.3 not installed by
me, the name and password are correctly visualized
once I click the submit button:
NAME = myname
PASSWORD = mypassword
, but on my recently installed server I obtain
NAME =
PASSWORD =
indicating that variable values are not transmitted.
Have you any idea about the reason of this behaviour?
Thank you very much for the attention,
Giuliano
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