[PHP] php encoders

2005-05-23 Thread Dustin Krysak

Can anyone recommend some good php encoders?

A variance in price range would be good.


Thanks in advance!


d

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[PHP] Should this not return true?!?!

2005-05-20 Thread Dustin Krysak
Hi there (newbie here) - I have the following snippet of code..
$sexId = $_POST['sex'];
$fName = $_POST['fName'];
$lName = $_POST['lName'];
if ($status = $db-query(INSERT INTO names (nameId, sexId, fName,  
lName) VALUES ('', $sexId, '$fName', '$lName'))) {
 print Your data was added to the database successfully!;
} else {
 print Your data could not be added to the database!;
}

Assuming my query was successful, should it not return true and print  
the success message?

For some reason it is doing just the opposite. The data is added, but  
it displays the error instead.

Am I misunderstanding something?
d
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[PHP] html editor written in PHP

2005-05-18 Thread Dustin Krysak
Has anyone seen an example of a HTML editor written in PHP (no JS)?  
You know the ones - for adding HTML tags to a text field, etc.

Thanks!
d
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[PHP] learning classes - need pointer

2005-05-16 Thread Dustin Krysak
Hi there - I am slowly converting all of my projects over to a OOP  
based structure with classes. Now I had a quick question.

In my current case, I am trying to create all the generic SQL  
functions (IE insert, update, delete, etc). Now what I am wondering -  
what would be the best way to structure the code so that I can  
accommodate the possibilities for different fields and databases,  
etc? Is it something that I should just pass to the class? Or would  
there be a more efficient way to do it?

d
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[PHP] CMS backend

2005-05-02 Thread Dustin Krysak
Hi there, I was wondering if anyone knows of any existing php/mysql  
cms back-ends (no need for a front end).

I am just looking for one to dissect (for learning purposes) - and  
would prefer to keep the presentation out of it for the sake of not  
having to sort through a 1000 extra files.

Thanks in advance.
d
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[PHP] Re: php-general Digest 18 Apr 2005 08:44:11 -0000 Issue 3404

2005-04-18 Thread DuSTiN KRySaK
check out amfphp (opensource php/flash remoting):
http://www.amfphp.org/
good tutorials here:
http://www.sephiroth.it/tutorials.php
AMFPHP allows you to return info from PHP classes as an actionscript 
object in flash.

d
On 18-Apr-05, at 1:44 AM, [EMAIL PROTECTED] wrote:
From: Matt Babineau [EMAIL PROTECTED]
Date: April 17, 2005 2:15:25 PM PDT
To: php-general@lists.php.net
Subject: Php + flash, need some help making a small .FLA
Hi all -
Does anyone have any experience with integrating php + flash? Or know 
of any
good tutorial sites? Basically what I want to do is have an animated 
loading
screen, and then pull pictures from a database and display text from a
database, text could be scrolling across the bottom like CNN or 
something.
Anyone familiar with some techniques on doing this?

Any examples people may have of this would be great, just send me some
sample .FLA scripts!!
If you've got some examples of exactly what I want to do, and you also 
have
a paypal account, I can make it worth your time :-D

Thanks,
Matt Babineau
Criticalcode
w: http://www.criticalcode.com
p: 858.733.0160
e: [EMAIL PROTECTED]

Re: [PHP] dynamic image will not print properly

2005-04-15 Thread DuSTiN KRySaK
I got it figured out finally!
It is so stupid with what the issue was...
My image was being created exactly as it should have been - and the  
code was fine. Now where my issue was: I had a line of code in there  
that was to prevent people from calling the script directly (had to be  
referred from a particular page). Well IE did not like that for  
printing. Even though the script acted exactly as it should have by  
design. I saved the image to my desktop to test it, and when opening in  
an image app - it would not even open (even though displaying fine in a  
browser). So I changed the file ext of the downloaded file to that of a  
text file and opened it... and what do you know - there was the error  
my php script generates when the page is not called properly.

So I removed that line of code (completely irrelevant to the image  
itself) And win/IE could print like all the other browsers could.

doh!
Dustin
On 14-Apr-05, at 5:41 PM, Richard Lynch wrote:
You'd want to http://php.net/urlencode the text, then.
?php
  $text = This is an example!;
  $text_url = urlencode($text);
  $url = http://example.com/gd_script/text=$text_url/fool_ie.jpg;;
?
On Wed, April 13, 2005 5:42 pm, DuSTiN KRySaK said:
One thing I feel is important to point out before I keep banging my
head off of the wall here...
In the URL parameter that is sent to the file, the url parameter is
just carrying text that is printed into the image. It is not actually
the image name, or anything. The image is generated in the cstl file
(which actually is the image - sends JPEG headers,etc) - with the text
on it (grabbed from the URL parameter).
d
On 13-Apr-05, at 5:03 PM, Richard Lynch wrote:
Yup.
$_PATH['x'] for the items that look like this: .../x=42/
And $PATH (without the underscore) is a string concatenation of all
elements (after the PHP script) that look like this /whatever/
So you might use something like a PHP script named 'scale' and then:
http://example.com/scale/width=100/height=100/images/subdir/ 
bigpic.jpg

and then you know that you want to scale the image in your
images/subdir
naemd bigpic.jpg down to 100x100 at maximum.
You'll have:
$_PATH['width'] - 100
$_PATH['height'] - 100
$PATH = '/images/subdir/bigpic.jpg'

On Tue, April 12, 2005 6:21 pm, DuSTiN KRySaK said:
And then all I should have to do is change my $_REQUESTS to $PATH in
hte cstl file right?
d
On 12-Apr-05, at 5:46 PM, Richard Lynch wrote:
On Mon, April 11, 2005 1:14 pm, DuSTiN KRySaK said:
hey - thanks a lot for the code snip - I am trying to use it  
now

Just to confirm - the $path include file is included in the file
that
calls the cstl file - correct?
Yes.
Something like:
?php require 'pathinfo.inc'; ?
You can use this same technique for not just JPEG, but also PDF,  
SWF
(Ming) and FDF files, all of which Microsoft will screw up if you
don't
fool them with a URL that looks like static content.


d
On 5-Apr-05, at 5:57 PM, Richard Lynch wrote:
On Tue, April 5, 2005 2:26 pm, DuSTiN KRySaK said:
Hi there - I had my first crack at creating a dynamic image. The
thing
is - the image is displayed fine in the browser, but when you go
to
print it, the image is either missing, or part of it is missing.
Is
there something special needed to print a dynamic image?
What you did, *should* work just fine.
But we're talking *MICROSOFT* here!
These people do *NOT* follow standards.  Period.
Here is a code snippet used to create the image
header(Content-type: image/jpg);
$image = imagecreatefromjpeg(template_cpn.jpg);
$red = imagecolorallocate( $image, 255,0,0 );
imagestring($image, 2, 306, 200, $couponcode, $red);
imagestring($image, 2, 306, 235, $exp, $red);
imagestring($image, 2, 175, 338, $myname, $red);
imagestring($image, 2, 175, 360, $myemail, $red);
imagejpeg($image);
imagedestroy($image);
Now the way I have it set up, is that there is a PHP file that
generates the image (the above code). Then I have a parent PHP
page
that calls that page like so:
$theurl = cstl.php?dk=soemthinghere
echo img src=\$theurl\;
See any issues in my code or setup?
Any ideas?
Here's what you do:  You make it *IMPOSSIBLE* for Microsoft to
screw
up.
This means you make your URL look JUST LIKE any other JPEG URL.
$theurl = cstl/dk=somethinghere/whatever.jpg;
Step 1:
Add/Create an .htaccess file with this:
Files cstl
  ForceType application/x-httpd-php
/Files
This forces Apache to treat the file named 'cstl' as a PHP  
script.

Step 2:
Rename cstl.php to just 'cstl' (see Step 1)
Step 3:
Instead of using $_GET['dk'] do this:
$pathinfo = $_SERVER['PATH_INFO'];
$pathinfo = explode('/', $pathinfo);
//Key-Value pairs:
$_PATH = array();
//Path information buried in URL for source image  
sub-directories:
$PATH = array();
while (list(, $keyval) = each($pathinfo)){
  $parts = explode('=', $keyval);
  switch(count($parts)){
case 0: break; //do nothing with bogus extra '/' in URL
case 1: $PATH[] = $keyval;
default:
  $key = $parts[0];
  unset($parts[0]);
  $_PATH[$key

[PHP] scripting workflow

2005-04-12 Thread DuSTiN KRySaK
I just have a few questions regarding workflow when producing scripts.
First off, do people prefer to have all their code in one file? Or 
multiple separate files? I know functions and classes are good to keep 
in separate files, but i am talking about say for example a news 
system, etc.

Next off, how about when actually assembling the files? Do you produce 
all of your html output, then say build all of your functions - then 
say build the logic?

Does that make sense?
I had in the past use DW for building php apps, and as an exercise to 
myself I am forcing myself to hand code to learn better. But I do 
however want to increase my productivity.

If anyone has any pointers on this type of stuff - it would be much 
appreciated!

Thanks!
d
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Re: [PHP] dynamic image will not print properly

2005-04-11 Thread DuSTiN KRySaK
I just wanted to add something to this
I moved the script over to another host to test, and it worked fine 
there. So to me that says it should be something to do with the host... 
now is there anything in the php.ini that could inflict this kind of 
behavior?

d
On 5-Apr-05, at 5:57 PM, Richard Lynch wrote:
On Tue, April 5, 2005 2:26 pm, DuSTiN KRySaK said:
Hi there - I had my first crack at creating a dynamic image. The thing
is - the image is displayed fine in the browser, but when you go to
print it, the image is either missing, or part of it is missing. Is
there something special needed to print a dynamic image?
What you did, *should* work just fine.
But we're talking *MICROSOFT* here!
These people do *NOT* follow standards.  Period.
Here is a code snippet used to create the image
header(Content-type: image/jpg);
$image = imagecreatefromjpeg(template_cpn.jpg);
$red = imagecolorallocate( $image, 255,0,0 );
imagestring($image, 2, 306, 200, $couponcode, $red);
imagestring($image, 2, 306, 235, $exp, $red);
imagestring($image, 2, 175, 338, $myname, $red);
imagestring($image, 2, 175, 360, $myemail, $red);
imagejpeg($image);
imagedestroy($image);
Now the way I have it set up, is that there is a PHP file that
generates the image (the above code). Then I have a parent PHP page
that calls that page like so:
$theurl = cstl.php?dk=soemthinghere
echo img src=\$theurl\;
See any issues in my code or setup?
Any ideas?
Here's what you do:  You make it *IMPOSSIBLE* for Microsoft to screw 
up.

This means you make your URL look JUST LIKE any other JPEG URL.
$theurl = cstl/dk=somethinghere/whatever.jpg;
Step 1:
Add/Create an .htaccess file with this:
Files cstl
  ForceType application/x-httpd-php
/Files
This forces Apache to treat the file named 'cstl' as a PHP script.
Step 2:
Rename cstl.php to just 'cstl' (see Step 1)
Step 3:
Instead of using $_GET['dk'] do this:
$pathinfo = $_SERVER['PATH_INFO'];
$pathinfo = explode('/', $pathinfo);
//Key-Value pairs:
$_PATH = array();
//Path information buried in URL for source image sub-directories:
$PATH = array();
while (list(, $keyval) = each($pathinfo)){
  $parts = explode('=', $keyval);
  switch(count($parts)){
case 0: break; //do nothing with bogus extra '/' in URL
case 1: $PATH[] = $keyval;
default:
  $key = $parts[0];
  unset($parts[0]);
  $_PATH[$key] = implode('=', $parts);
break;
  }
}
Now you can use $_PATH['dk'] instead of $_GET['dk'] to get your dk 
value
from the URL.  You'll only change $_GET to $_PATH in cstl (formerly
cstl.php) and you're all set.

Now, there is *NO* *WAY* Microsoft can manage to screw up your URL and
decide that it must not be a JPEG because it has GET data, or ends in 
.php
or whatever.

This same technique must be applied to PDF, FDF, SWF/Ming files if you
want to avoid a zillion MS IE bugs related to multi-media.
So you might as well put the code for $_PATH/$PATH in an include file. 
 I
guarantee you'll need it again and again as you use more and more
multi-media in your web-site.

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Re: [PHP] dynamic image will not print properly

2005-04-11 Thread DuSTiN KRySaK
Replying below.
On 11-Apr-05, at 5:05 PM, Richard Lynch wrote:
On Mon, April 11, 2005 3:04 pm, DuSTiN KRySaK said:
I moved the script over to another host to test, and it worked fine
there. So to me that says it should be something to do with the 
host...
now is there anything in the php.ini that could inflict this kind of
behavior?
anything covers a lot of ground...
First:  Did you use the SAME browser and computer to surf in both 
cases.
If not, re-do the test with the SAME browser and computer.
exact same computer.
Second:  Is GD even installed on the non-working server?
Use ?php phpinfo();?
Either you see GD in one of the mini-tables or you don't have GD and 
it
ain't gonna work.
It is installed - as the image displays in the browser as it should, 
but the print output is all messed up.

Third: Compare the *VERSIONS* of GD on both servers. Then PHP versions.
Then Apache versions.
Checking out from the host.
Fourth:  On the broken server, take *OUT* the header() lines in your
script, and surf directly to the image URL.  If you see PHP messages,
well, fix your script to get rid of them.  If you see a bunch of weird
characters, that's what it *should* be -- Pretty much the same as you
would see if you opened up a real JPEG in a text editor.
I get the proper JPG results. As I said earlier - the output is only 
messed in the win/ie combo while printing.

Fifth: Re-test on the server and desktop where it didn't work -- It's
possible that between test 1 and 2 somebody updated the browser out 
from
under you (like Microsoft auto-update, for example)
The tests were done back to back and always testing with the exact same 
setup. Did one test on another win/ie box just to see if it was the 
local machine that was fubar - however it had the same results.

d

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[PHP] php rich text editors

2005-04-07 Thread DuSTiN KRySaK
Can anyone refer me to anything that will work with PHP? Just need it 
for a blog type application.

Thanks!
d
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[PHP] Re: php rich text editors

2005-04-07 Thread DuSTiN KRySaK
Problem with that one - does not work in safari (on the mac).
d
On 7-Apr-05, at 11:22 AM, Ben Ramsey wrote:
DuSTiN KRySaK wrote:
Can anyone refer me to anything that will work with PHP? Just need it 
for a blog type application.
FCKEditor works well, has a PHP version, and is cross-browser:
http://www.fckeditor.net/
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Re: [PHP] php rich text editors

2005-04-07 Thread DuSTiN KRySaK
All of these could work in some form or another - but I am looking for 
a real scaled down one with less options for the users  (or 
somethign with the option to limit available buttons)

Pretty much just bold, italic, bullets, links and images.
Since it is for a blog, I want to keep the look and feel of the site 
somewhat consistent.

d
On 7-Apr-05, at 11:40 AM, Pablo Gosse wrote:
DuSTiN KRySaK wrote:
Can anyone refer me to anything that will work with PHP? Just need it
for a blog type application.
Thanks!
d
Free - http://www.dynarch.com/projects/htmlarea/ (works okay, but code
is different depending on the browser, which can be a real pain).
Cheap - http://www.wysiwygpro.com (works brilliantly - I'm using it in 
a
large CMS with minimal issues)

HTH.
Pablo
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[PHP] dynamic image will not print properly

2005-04-05 Thread DuSTiN KRySaK
Hi there - I had my first crack at creating a dynamic image. The thing 
is - the image is displayed fine in the browser, but when you go to 
print it, the image is either missing, or part of it is missing. Is 
there something special needed to print a dynamic image?

Here is a code snippet used to create the image
header(Content-type: image/jpg);
$image = imagecreatefromjpeg(template_cpn.jpg);
$red = imagecolorallocate( $image, 255,0,0 );
imagestring($image, 2, 306, 200, $couponcode, $red);
imagestring($image, 2, 306, 235, $exp, $red);
imagestring($image, 2, 175, 338, $myname, $red);
imagestring($image, 2, 175, 360, $myemail, $red);
imagejpeg($image);
imagedestroy($image);
Now the way I have it set up, is that there is a PHP file that 
generates the image (the above code). Then I have a parent PHP page 
that calls that page like so:

$theurl = cstl.php?dk=soemthinghere
echo img src=\$theurl\;
See any issues in my code or setup?
Any ideas?
d
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[PHP] Fwd: dynamic image will not print properly

2005-04-05 Thread DuSTiN KRySaK
One thing to add. the issue is only on windows/IE. If it is say 
windows/Firefox - everything works as it should.

d

Begin forwarded message:
From: DuSTiN KRySaK [EMAIL PROTECTED]
Date: April 5, 2005 2:26:14 PM PDT
To: PHP php-general@lists.php.net
Subject: dynamic image will not print properly
Hi there - I had my first crack at creating a dynamic image. The thing 
is - the image is displayed fine in the browser, but when you go to 
print it, the image is either missing, or part of it is missing. Is 
there something special needed to print a dynamic image?

Here is a code snippet used to create the image
header(Content-type: image/jpg);
$image = imagecreatefromjpeg(template_cpn.jpg);
$red = imagecolorallocate( $image, 255,0,0 );
imagestring($image, 2, 306, 200, $couponcode, $red);
imagestring($image, 2, 306, 235, $exp, $red);
imagestring($image, 2, 175, 338, $myname, $red);
imagestring($image, 2, 175, 360, $myemail, $red);
imagejpeg($image);
imagedestroy($image);
Now the way I have it set up, is that there is a PHP file that 
generates the image (the above code). Then I have a parent PHP page 
that calls that page like so:

$theurl = cstl.php?dk=soemthinghere
echo img src=\$theurl\;
See any issues in my code or setup?
Any ideas?
d


[PHP] Re:Re: [PHP] dynamic image will not print properly

2005-04-05 Thread DuSTiN KRySaK
I wondered that myself, but all the other (not dynamic) images print 
fine!

d
On 5-Apr-05, at 4:51 PM, [EMAIL PROTECTED] wrote:
From: Andy Pieters [EMAIL PROTECTED]
Date: April 5, 2005 2:35:22 PM PDT
To: php-general@lists.php.net
Subject: Re: [PHP] dynamic image will not print properly
To test,
cstl.php?dk=somethinghere
and try to print that?
Maybe your browser is configured to NOT print images (or bakckground) ?
Maybe your printer is textonly (just kidding)
Tada
Andy

[PHP] functions vs classes

2005-04-03 Thread DuSTiN KRySaK
Novice PHPer, and i am wondering why one would use a function instead 
of a class (or object)? They seem to server very similar in use.

The way I see it, is a function if for repeated use in a project 
specific manner, where as a class could be used for many projects.

is this correct?
Although one could just include the function library in multiple 
projects.

Thanks!
Dustin
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[PHP] PHP source code formatter for OS X

2005-03-16 Thread DuSTiN KRySaK
Does anyone know of a PHP source code formatter to clean up sloppy code 
that runs on OS X?

d
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[PHP] mail() takes a long time to process

2005-02-26 Thread Dustin Krysak
Hi there, I have a script that uses the mail() function, but for some 
reason the script takes a really long time to finish processing (like 5 
minutes). there are some other functions performed (like sql insert, 
etc) that happen immediately as they should. But the mail takes some 
time to finish processing. If I remove the mail function, the script 
finishes immediately. Any ideas? I have included my code below (used 
for the mail). ideas?

			$ToMail = $_POST['ccEmail'];
			
			$FromMail = [EMAIL PROTECTED];
			
			$FromName = The Name;
			
			$Subject = Your membership;
			
			$xmailer = PHP mailer;
			
			$headers = From: .$FromName..$FromMail.\r\n;
			$headers .= Reply-To: .$FromName..$FromMail.\r\n;
			$headers .= X-Mailer: .$xmailer.\r\n;
			$headers .= Origin: .$_SERVER['REMOTE_ADDR'].\r\n;
			
			$Message = Dear .$_POST['ccfName'].\n,;
			$Message .= Thanks for joining the Coastal Crew!\n;
			$Message .= Below you will find the information required to verfiy 
your email address.\n;
			$Message .= Upon verification, an e-coupon will be presented to you 
in which you can print;
			$Message .=  off for 20% off of your next purchase.\n\nBy clicking 
on this hyperlink:\n;
			$Message .= $verify_url.\nand follow the directions in your web 
browser.\n\n;
			$Message .= Thank you,\nThe Coastal 
Crew.\n.$_SERVER['SERVER_NAME'];
			
			$mailer = mail($ToMail, $Subject, $Message, $headers);

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[PHP] best flow for this project

2005-01-31 Thread Dustin Krysak
ok, i have a project where:
-a user adds their email address, name, etc to a database.
-a responder sends an email to them to confirm their email address 
(within 72 hrs).
-upon confirmation of their email address, a script will generate a 
store coupon with a random coupon id # in the browser (which they can 
print at that time).

Now I guess my question relates more to the email confirmation. How 
would you go about this? Store it in a database? Every-time the script 
is run it also checks to see which requests are more than 72 hrs old 
and removes their request from the database? And those that are 
confirmed, a flag is added to the database so they are not removed?

Just looking more for ideas on the script flow to accomplish this.
Thanks!
Dustin
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[PHP] class structure.

2005-01-19 Thread Dustin Krysak
Hi there, I am pretty new to writing classes (and pretty new to PHP 
itself), but I was wondering what was the best format for constructing 
classes. Now for example, i have written 2 versions of a class that 
accomplish the exact same thing. And I was just wondering if there are 
any advantages to either, or even if one was formatted more so to 
standards. Just wanting to learn it the proper way from the get go. My 
classes are formatted for use in flash remoting (hence the methodTable 
stuff - you can ignore it). I guess my question refers more towards the 
declaration of properties, etc.

[ VERSION 1 ]
?php
class Sql {
// Set properties
//DB info
var $hostname_local = localhost;
var $database_local = mydb;
var $username_local = root;
var $password_local = password;
var $local;
var $query_rs_biz;
var $rs_biz;
function Sql() {
$this-methodTable = array(
getRecords = array(
description = return a SQL record,
access = remote,
arguments = array()
)
);
}
//SQL
//Create method to retreive records
function getRecords() {
$this-local = mysql_pconnect($this-hostname_local, 
$this-username_local, $this-password_local) or 
trigger_error(mysql_error(),E_USER_ERROR);
mysql_select_db($this-database_local, $this-local);
$this-query_rs_biz = SELECT * FROM directory ORDER BY Business ASC;
$this-rs_biz = mysql_query($this-query_rs_biz, $this-local) or 
die(mysql_error());

//return $this-row_rs_biz;
return $this-rs_biz;
}
}
?
[ VERSION 2 ]
?php
class Sql2 {
// Set properties
//DB info
var $hostname_local = localhost;
var $database_local = Blisting;
var $username_local = root;
var $password_local = URAredneck;
function Sql2() {
$this-methodTable = array(
getRecords = array(
description = return a SQL record,
access = remote,
arguments = array(),
returns = sql records
),
getRecCount = array(
description = return the row count from the 
getRecords method,
access = remote,
arguments = array(),
returns = sql row count
)
);
}
//SQL
//Create method to retreive records
function getRecords() {
$local = mysql_pconnect($this-hostname_local, $this-username_local, 
$this-password_local) or trigger_error(mysql_error(),E_USER_ERROR);
mysql_select_db($this-database_local, $local);
$query_rs_biz = SELECT * FROM directory ORDER BY pID ASC;
$rs_biz = mysql_query($query_rs_biz, $local) or die(mysql_error());

//return results;
return $rs_biz;
}
}
?
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[PHP] php and flash

2004-12-15 Thread Dustin Krysak
Can anyone point to some good tutorials on using PHP with flash? I am 
mostly interested in displaying info from a database in the flash 
movie, as well as loading movies and pictures into the flash file 
(referenced in the database).

thanks!
d
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[PHP] Fwd: variable not being rendered

2004-12-04 Thread Dustin Krysak
Answering within the email below
d
On 4-Dec-04, at 3:16 AM, [EMAIL PROTECTED] wrote:
From: Jason Wong [EMAIL PROTECTED]
Date: December 4, 2004 12:04:18 AM PST
To: [EMAIL PROTECTED]
Subject: Re: [PHP] variable not being rendered
On Saturday 04 December 2004 15:36, Dustin Krysak wrote:
Hi there, I have some code where I am using the $_SERVER['PHP_SELF']
array to reference my script for a form action... now for some reason
the file name is not being rendered out. I am including only small
snippets of my code to see where my error is...
I know this is not your actual code, but did you actually run this? I 
can't
see any errors in it and it should work fine if you're using a recent 
version
of PHP.
I did run it... that is the reason I posted. As I stated, When I view 
source, the result is blank.


?php
$editFormAction = $_SERVER['PHP_SELF'];
What does print_r($_SERVER) show?
What does print $editFormAction show?
echo $_SERVER['PHP_SELF']; shows the proper result.
print_r($_SERVER['PHP_SELF']); shows the proper result
print $editFormAction ; shows the proper result


print form action=\.$editFormAction.\ method=\post\
name=\ml_form\ id=\ml_form\\n;
As you're not placing variables inside your print statement you might 
as well
use single-quotes:

print 'form action='.$editFormAction.' method=post
name=ml_form id=ml_form'.\n;
This does away with all the backslashes (which gives me a headache).
Well I changed it to:
print 'form action='.$editFormAction.' method=post name=ml_form 
id=ml_form'.\n;

and I still had the same result. the source of the page when viewed in 
the browser was:

form action= method=post name=ml_form id=ml_form
So as you can see the $editFormAction is still not being rendered. So 
I am going to add the following info, I have a page that is required 
once that contains my functions. and I defined a function to print out 
this form. My code for that is:

?php
// create subscribe form
function sub_form() {
print 'form action='.$editFormAction.' method=post name=ml_form 
id=ml_form'.\n;
print 'pinput name=email type=text id=email 
size=25/p'.\n;
print 'pinput type=submit name=Submit 
value=Subscribe/p'.\n;
print '/form';
}
?

So would my issue be that I formatted my function wrong? Or that the 
page is included?

Dustin

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[PHP] Re: variable not being rendered

2004-12-04 Thread Dustin Krysak
Ok - I have been investigating a little more. I now realized it is a 
question of making my variables available outside of the function. So 
one thing I want to point out is that:

$editFormAction = $_SERVER['PHP_SELF']; is contained in one function.
And that:
print 'form action='.$editFormAction.' method=post name=ml_form 
id=ml_form'.\n; is contained in another function.

The first function contains all my code for a SQL query to insert a 
record. And the second function is just to create the form itself.

Now i know i also need to use the result function. But I am sure that 
since I am using a few functions here - there might be more hitches 
than I realize. So I am just asking for some pointers for dealing with 
this.

thanks!
d

From: Dustin Krysak [EMAIL PROTECTED]
Date: December 3, 2004 11:36:56 PM PST
To: PHP [EMAIL PROTECTED]
Subject: variable not being rendered
Hi there, I have some code where I am using the $_SERVER['PHP_SELF'] 
array to reference my script for a form action... now for some reason 
the file name is not being rendered out. I am including only small 
snippets of my code to see where my error is...

?php
$editFormAction = $_SERVER['PHP_SELF'];
print form action=\.$editFormAction.\ method=\post\ 
name=\ml_form\ id=\ml_form\\n;

?
Now there is much more code, but these are the important points. All I 
am doing is assigning a variable a value from the $_SERVER array. Then 
print out a form with PHP, and reference that variable for my form 
action the HTML is rendered as normal. But the form action page is 
not there when I view my source. I am sure it is a SIMPLE error... But 
my brain block is getting larger the more i look at this.

help cries the newbie!
d
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[PHP] variable not being rendered

2004-12-03 Thread Dustin Krysak
Hi there, I have some code where I am using the $_SERVER['PHP_SELF'] 
array to reference my script for a form action... now for some reason 
the file name is not being rendered out. I am including only small 
snippets of my code to see where my error is...

?php
$editFormAction = $_SERVER['PHP_SELF'];
print form action=\.$editFormAction.\ method=\post\ 
name=\ml_form\ id=\ml_form\\n;

?
Now there is much more code, but these are the important points. All I 
am doing is assigning a variable a value from the $_SERVER array. Then 
print out a form with PHP, and reference that variable for my form 
action the HTML is rendered as normal. But the form action page is 
not there when I view my source. I am sure it is a SIMPLE error... But 
my brain block is getting larger the more i look at this.

help cries the newbie!
d
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Re: [PHP] similar function like getimagesize for Quicktime?

2004-11-29 Thread Dustin Krysak
On 29-Nov-04, at 3:54 AM, Marek Kilimajer wrote:
Dustin Krysak wrote:
Hi there - I was wondering if there was some kind of PHP function to 
determine hte pixel size of a quicktime movie. Something like what 
GetImageSize() is to images, but for quicktime.
Not in php. Search for programs that you can execute from command line 
for your platform.
Just for everyone's reference, here is a pretty cool package for 
parsing media files (various video and audio) for common information. 
Works great.

http://www.getid3.org/
d
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[PHP] sql insert into 2 tables

2004-11-28 Thread Dustin Krysak
Hi there - I was wondering if anyone could point me in the right 
direction to be able to add data to two different tables (I am using 
mysql and php V4). I understand joins, etc for the query of the data, 
however adding the data - still getting my head wrapped around it 
(multiple tables).

Thanks!
d
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[PHP] similar function like getimagesize for Quicktime?

2004-11-28 Thread Dustin Krysak
Hi there - I was wondering if there was some kind of PHP function to 
determine hte pixel size of a quicktime movie. Something like what 
GetImageSize() is to images, but for quicktime.

thanks!
d
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[PHP] get image dimensions

2004-11-27 Thread Dustin Krysak
Hi there - I was wondering if there was a way to get PHP to get the 
dimensions of an image? I want to be able to have PHP dynamically write 
the image size (of the IMG tag) so that my pages validate when 
displaying a dynamic image.

Thanks in advance!
d
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Re: [PHP] remove first character in text file

2004-11-24 Thread Dustin Krysak
Just want to add to this with a little more info
my text file is a list of email addresses with a % separating them. 
For example:

[EMAIL PROTECTED]@[EMAIL PROTECTED]
Now sometimes I end up with a % at the beginning. For example:
[EMAIL PROTECTED]@[EMAIL PROTECTED]
Or:
[EMAIL PROTECTED]@[EMAIL PROTECTED]
Now that causes me issues else where in the script. So what I need to 
do is check if the % character exists at the beginning of the file 
and remove any if the % is there.

ideas?
d


Hi there.. I have a text file where I need to remove JUST the
first character in the text file. Can anyone point me to a tutorial?
d

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[PHP] endless loop

2004-11-24 Thread Dustin Krysak
Hi there
I was making a script that had a loop, and ended up with a endless loop 
by accident. Now if that script is executed on the server - does the 
script die as soon as the browser is closed? Or does it keep running as 
a process on the server?

Thanks!
d
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[PHP] remove first character in text file

2004-11-23 Thread Dustin Krysak
Hi there.. I have a text file where I need to remove JUST the first 
character in the text file. Can anyone point me to a tutorial?

d
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[PHP] isset opposite

2004-11-16 Thread Dustin Krysak
Hi there.. I am pretty new to PHP, and I am familiar with php isset 
option now i was wondering (I have looked at the PHP site - but 
can not find it) how can you check if something is not set? I need to 
test if a $_GET is not set (not just empty).

thanks in advance!
d
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Re: [PHP] isset opposite

2004-11-16 Thread Dustin Krysak
Thanks!
perfect!
d
On 16-Nov-04, at 4:13 PM, Robby Russell wrote:
On Tue, 2004-11-16 at 15:11 -0800, Dustin Krysak wrote:
Hi there.. I am pretty new to PHP, and I am familiar with php isset
option now i was wondering (I have looked at the PHP site - 
but
can not find it) how can you check if something is not set? I need to
test if a $_GET is not set (not just empty).

thanks in advance!
d
isset() returns a boolean.
so...try,
if (!isset($x))
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Re: [PHP] isset opposite

2004-11-16 Thread Dustin Krysak
Yeah as soon as I saw this example, I figured that was the case for 
example something like

if (!empty())
and so on.
d
On 16-Nov-04, at 5:26 PM, Robby Russell wrote:
On Tue, 2004-11-16 at 17:19 -0800, Dustin Krysak wrote:
Thanks!
perfect!
d
For future reference, just about any function that uses is at the
beginning should return a boolean result. So if (is_array()) can also 
be
checked with if (!is_array())

This should apply to all the php included functions that start with is.
-Robby
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[PHP] Re: Recommendations for php email list managers?

2004-09-22 Thread Dustin Krysak
I am interested in the postfix/php solution as well for a MLM, as well 
as just form processing.

d


I wonder why aren't you using PHP to send the messages via Postfix.
Anyway, he did not say that he was using a platform that can run 
Postfix. If he is using Windows 2000 or later with IIS/Exchange, he 
can actually queue messages much faster than piping to postfix.

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[PHP] flash php

2004-09-22 Thread Dustin Krysak
Can anyone recommend any good tutorials on using flash mx 2004 with PHP 
to display MYsql content using PHP? Including loading and displaying 
JPGs and movies (referenced in the database).

thanks in advance!
d
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[PHP] link to append to form

2004-09-21 Thread Dustin Krysak
Hi there I have a VERY simple blogging system, and I want to add a 
link that will append a br into the end of the existing text 
whenever it is clicked.. that way users do not need to remember the 
HTML code.

How would i go about this?
Thanks!
d
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[PHP] Re: php - no results - display other message

2004-09-15 Thread Dustin Krysak
Actually, after some searching I got it figured out... here is the way 
I ended up doing it

Obviously the RSdel and the MLemail are specific to my record set 
and my database field.


  ?php if ($row_RSdel['MLemail'] !=  ) { ?
  Show result from database.
   ?php
}
else { ?
  No matching email address in the database!
   ?php
}
?
Thanks everyone! appreciate the help!
Dustin
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[PHP] checking multiple URL parameters

2004-09-15 Thread Dustin Krysak
Hi there, I am currently using the following code to display content 
based on the URL parameters

?php
if (isset($_REQUEST['mov'])) {
$movie = ($_REQUEST['mov'])
?
   HTML CONTENT
?php
  }
  else {
  ?
  OTHER HTML CONTENT
?php
}
?
now what I need to do is modify the code so that the script checks 2 
URL parameters, and has 2 variables defined (from the URL parameter)...

So I need to also check if $_REQUEST['year'] is set as well as the 
original (both need to be set to get the first HTML content) AND I also 
need to set the variable of $year = ($_REQUEST['year']

direction?
d
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[PHP] php/MYSQL remove duplicate records

2004-09-14 Thread Dustin Krysak
Hi there - I have an extremely simple table that has a unique Id and an 
email address. what I am looking for is an example of a PHP script 
that will poll the MYSQL database and delete the duplicate records 
leaving only 1 unique (email) record.

can someone point me to the right place?
thanks!
d
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[PHP] php - no results - display other message

2004-09-14 Thread Dustin Krysak
Hi there... I have a simple search page (mysql database), and I can get 
it to display the results no issues, but i was wondering how I could 
display a message stating there were no results, instead of just having 
the field blank. I am familiar with IF and ELSE statements, but I am 
not sure how to test the no result option from the results of a SQL 
query

thanks!
d
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[PHP] unexpected T_VARIABLE

2004-08-13 Thread Dustin Krysak
Hi there, I am working with a script that I found online to export a 
SQL statement (results) to an excel file., now everytime i run the 
script, i get the error:

Parse error: parse error, unexpected T_VARIABLE in 
/var/www/html/siteadmin/mysql_export/export.php on line 11

Now the code that is located at (and around) that line is (I have 
included the line numbers for reference):

10for ($i = 0; $i  $count; $i++) {
11   $header .= mysql_field_name($result, $i).\t;
12}
Now just in case you guys want to reference the entire script - I have 
included it below:


?php
//Written by Dan Zarrella. Some additional tweaks provided by JP 
Honeywell
//pear excel package has support for fonts and formulas etc.. more 
complicated
//this is good for quick table dumps (deliverables)

include('../../Connections/db_connection.php');
$result = mysql_query('select * from dealers', $linkID);
$count = mysql_num_fields($result);
for ($i = 0; $i  $count; $i++) {
$header .= mysql_field_name($result, $i).\t;
}
while($row = mysql_fetch_row($result)){
  $line = '';
  foreach($row as $value){
if(!isset($value) || $value == ){
  $value = \t;
}else{
# important to escape any quotes to preserve them in the data.
  $value = str_replace('', '', $value);
# needed to encapsulate data in quotes because some data might be multi 
line.
# the good news is that numbers remain numbers in Excel even though 
quoted.
  $value = '' . $value . '' . \t;
}
$line .= $value;
  }
  $data .= trim($line).\n;
}
# this line is needed because returns embedded in the data have \r
# and this looks like a box character in Excel
  $data = str_replace(\r, , $data);

# Nice to let someone know that the search came up empty.
# Otherwise only the column name headers will be output to Excel.
if ($data == ) {
  $data = \nno matching records found\n;
}
# This line will stream the file to the user rather than spray it 
across the screen
header(Content-type: application/octet-stream);

# replace excelfile.xls with whatever you want the filename to default 
to
header(Content-Disposition: attachment; filename=export_dealers.xls);
header(Pragma: no-cache);
header(Expires: 0);

echo $header.\n.$data;
?
Any ideas?
d

[PHP] reading txt file - certain lines

2004-07-28 Thread Dustin Krysak
Hi there.. .I am displaying info (on music) from a text file with the 
following code...

?php
//open the file handler
$fp02=fopen(assets/lib/php/itunes/recent.txt,r);
//Read the track info
$recent=fgets($fp02);
//close the file.
echo $recent;
fclose($fp02);
?

Now the contents of said text file would read something like the 
following:

bLiar/bbrby ibSex Pistols/bibriNever Mind The 
Bollocks/ibrPlayed: 2004/07/28, 1:48:29 
PMbr--brbLet's Rave On/bbrby ibThe 
Raveonettes/bibriChain Gang Of Love/ibrPlayed: 
2004/07/28, 1:46:37 PMbr--brbNo Remorse/bbrby 
ibMetallica/bibriKill 'Em All/ibrPlayed: 2004/07/28, 
1:40:17 PMbr--brbThis Is Our Emergency/bbrby 
ibPretty Girls Make Graves/bibriThe New 
Romance/ibrPlayed: 2004/07/28, 1:36:37 
PMbr--brbFreestylin'/bbrby 
ibGreyboy/bibriFreestylin'/ibrPlayed: 2004/07/28, 
1:30:25 PMbr--brbIn My Head/bbrby ibNaked 
Raygun/bibriRaygun...Naked Raygun (Reissue)/ibrPlayed: 
2004/07/28, 1:26:37 PMbr--brbLust To Love/bbrby 
ibThe Go-Go's/bibriReturn To The Valley Of The 
Go-Go's/ibrPlayed: 2004/07/28, 1:23:13 PMbr--brbKim 
You Bore Me To Death/bbrby ibGrandaddy/bibriConcrete 
Dunes/ibrPlayed: 2004/07/28, 1:18:37 
PMbr--brbSonderkommando/bbrby 
ibGwar/bibriThis Toilet Earth/ibrPlayed: 2004/07/28, 
1:13:49 PMbr--br

Now what I want to do is read this file, but only say read 5 songs 
worth, then I would place the PHP code in (another table) and display 
the next 5 songs and so on This just allows for a more flexible 
layout in the final presentation. the way I am having the text files 
written, there is no way to get it to produce seperate text files - 
otherwise this would be easy to do

Is this possible?
Thanks in advance!
Dustin
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Re: Re: [PHP] reading txt file - certain lines

2004-07-28 Thread Dustin Krysak
Yeah I do not really have the option to use a database here since the 
way the data is output is limited to a text file.. the files are 
populated by a program that takes the currently playing tracks out of 
Itunes (mp3 player) on my mac.

d
On 28-Jul-04, at 3:26 PM, [EMAIL PROTECTED] wrote:

From: John Nichel [EMAIL PROTECTED]
Date: July 28, 2004 2:05:51 PM PDT
To: PHP [EMAIL PROTECTED]
Subject: Re: [PHP] reading txt file - certain lines
Dustin Krysak wrote:
Hi there.. .I am displaying info (on music) from a text file with the 
following code...
?php
//open the file handler
$fp02=fopen(assets/lib/php/itunes/recent.txt,r);
//Read the track info
$recent=fgets($fp02);
//close the file.
echo $recent;
fclose($fp02);
?
Now the contents of said text file would read something like the 
following:
bLiar/bbrby ibSex Pistols/bibriNever Mind The 
Bollocks/ibrPlayed: 2004/07/28, 1:48:29 
PMbr--brbLet's Rave On/bbrby ibThe 
Raveonettes/bibriChain Gang Of Love/ibrPlayed: 
2004/07/28, 1:46:37 PMbr--brbNo Remorse/bbrby 
ibMetallica/bibriKill 'Em All/ibrPlayed: 
2004/07/28, 1:40:17 PMbr--brbThis Is Our 
Emergency/bbrby ibPretty Girls Make Graves/bibriThe 
New Romance/ibrPlayed: 2004/07/28, 1:36:37 
PMbr--brbFreestylin'/bbrby 
ibGreyboy/bibriFreestylin'/ibrPlayed: 2004/07/28, 
1:30:25 PMbr--brbIn My Head/bbrby ibNaked 
Raygun/bibriRaygun...Naked Raygun (Reissue)/ibrPlayed: 
2004/07/28, 1:26:37 PMbr--brbLust To Love/bbrby 
ibThe Go-Go's/bibriReturn To The Valley Of The 
Go-Go's/ibrPlayed: 2004/07/28, 1:23:13 
PMbr--brbKim You Bore Me To Death/bbrby 
ibGrandaddy/bibriConcrete Dunes/ibrPlayed: 
2004/07/28, 1:18:37 PMbr--brbSonderkommando/bbrby 
ibGwar/bibriThis Toilet Earth/ibrPlayed: 
2004/07/28, 1:13:49 PMbr--br
Now what I want to do is read this file, but only say read 5 songs 
worth, then I would place the PHP code in (another table) and display 
the next 5 songs and so on This just allows for a more flexible 
layout in the final presentation. the way I am having the text files 
written, there is no way to get it to produce seperate text files - 
otherwise this would be easy to do
Is this possible?
Yes, possible.  Worth the time?  No.  Can you put all that info in a 
database?

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[PHP] export from mysql to csv file

2004-06-11 Thread Dustin Krysak
Can anyone point me to an existing script or tutorial to learn this?
Thanks in advance!
d
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[PHP] Re: Re: drop down menu populated from a directory

2004-05-31 Thread Dustin Krysak
I gave it a go, and I got the error:
Parse error: parse error, unexpected '}'
This was on the last }. Now I am brand new at php, but should there 
not be an opening and closing curly bracket? in this code there are one 
{ and three }

So I made my code:
?php
if ($handle = opendir('../../../mov')) {
   while (false !== ($file = readdir($handle)))
   if ($file != '.'  $file != '..')
   $fileName = str_replace('.mov', '', $file);
   echo 'option value=' . $file . '' . $fileName . 
'/option';
   closedir($handle);
}
?

And it does display the name in the menu... so that is a good start, 
but the link doesn't work when selected. So I am assuming hte code does 
need those brackets, and I rather need to open the opening one...

d

On 31-May-04, at 2:39 AM, [EMAIL PROTECTED] wrote:
From: Torsten Roehr [EMAIL PROTECTED]
Date: May 30, 2004 5:14:28 PM PDT
To: [EMAIL PROTECTED]
Subject: Re: drop down menu populated from a directory
Dustin Krysak [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Hi there
What I am hoping to do is have a drop down menu that would be 
populated
from the contents of a directory via php. Now The link names would be
generated by the file name minus the file extension. Has anyone seen a
tutorial on accomplishing something like this? All of the links would
be to quicktime movies, but I am hoping to have them embedded in HTML
(or PHP). So the movie is displayed in a browser

thanks in advance!
This should do the trick:
// opening select tag goes here...
if ($handle = opendir('/path/to/files')) {
   while (false !== ($file = readdir($handle)))
   if ($file != '.'  $file != '..')
   $fileName = str_replace('.mov', '', $file);
   echo 'option value=' . $file . '' . $fileName . 
'/option';
   }
   }
   closedir($handle);
}

// closing select tag goes here
Haven't tested it. Hope it works and helps ;)
Regards,
Torsten Roehr
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[PHP] Re: drop down menu populated from a directory

2004-05-31 Thread Dustin Krysak
ok, I added brackets and made my code to:
?php
if ($handle = opendir('../../../mov')) {
   while (false !== ($file = readdir($handle))) {
   if ($file != '.'  $file != '..') {
   $fileName = str_replace('.mov', '', $file);
   echo 'option value=../../../mov/' . $file . '' . 
$fileName . '/option';
   }
   }
   closedir($handle);
}
?

when viewing my page in a browser, it worked! Now what I am hoping to 
do is put this menu on a PHP page, and have a qt movie placeholder and 
when this menu is used - replace the placeholder with the selected qt 
movie... I am just not sure how to do this.

Thanks in advance!
d

On 31-May-04, at 10:26 AM, Dustin Krysak wrote:
I gave it a go, and I got the error:
Parse error: parse error, unexpected '}'
This was on the last }. Now I am brand new at php, but should there 
not be an opening and closing curly bracket? in this code there are 
one { and three }

So I made my code:
?php
if ($handle = opendir('../../../mov')) {
   while (false !== ($file = readdir($handle)))
   if ($file != '.'  $file != '..')
   $fileName = str_replace('.mov', '', $file);
   echo 'option value=' . $file . '' . $fileName . 
'/option';
   closedir($handle);
}
?

And it does display the name in the menu... so that is a good start, 
but the link doesn't work when selected. So I am assuming hte code 
does need those brackets, and I rather need to open the opening one...

d

On 31-May-04, at 2:39 AM, [EMAIL PROTECTED] wrote:
From: Torsten Roehr [EMAIL PROTECTED]
Date: May 30, 2004 5:14:28 PM PDT
To: [EMAIL PROTECTED]
Subject: Re: drop down menu populated from a directory
Dustin Krysak [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Hi there
What I am hoping to do is have a drop down menu that would be 
populated
from the contents of a directory via php. Now The link names would be
generated by the file name minus the file extension. Has anyone seen 
a
tutorial on accomplishing something like this? All of the links would
be to quicktime movies, but I am hoping to have them embedded in HTML
(or PHP). So the movie is displayed in a browser

thanks in advance!
This should do the trick:
// opening select tag goes here...
if ($handle = opendir('/path/to/files')) {
   while (false !== ($file = readdir($handle)))
   if ($file != '.'  $file != '..')
   $fileName = str_replace('.mov', '', $file);
   echo 'option value=' . $file . '' . $fileName . 
'/option';
   }
   }
   closedir($handle);
}

// closing select tag goes here
Haven't tested it. Hope it works and helps ;)
Regards,
Torsten Roehr

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[PHP] Re: drop down menu populated from a directory

2004-05-31 Thread Dustin Krysak
Ok - here is the relevant Quicktime code:
!-- START QUICKTIME CONTENT --
object classid=clsid:02BF25D5-8C17-4B23-BC80-D3488ABDDC6B 
width=320 height=256 
codebase=http://www.apple.com/qtactivex/qtplugin.cab;
  param name=autoplay value=true
  param name=controller value=true
  param name=pluginspage 
value=http://www.apple.com/quicktime/download/indext.html;
  param name=target value=myself
  param name=type value=video/quicktime
  param name=src value=../../../mov/THElostART.mov
  embed src=../../../mov/THElostART.mov width=320 height=256 
autoplay=true controller=true border=0 
pluginspage=http://www.apple.com/quicktime/download/indext.html; 
target=myself/embed
/object
!-- END QUICKTIME CONTENT --

Now I figure - getting the file name in there would be pretty easy (for 
the most part), but the thing is getting the dimensions of the movie in 
there... as it is possible that not all movies are the same dimensions. 
I am hoping to have just the one PHP that will change dynamically for 
the QT content - I would like to avoid having a php or html file for 
each QT movie.

d
PS - please CC me directly as I am subscribed in digest mode.. thanks 
much!




On 31-May-04, at 3:08 PM, [EMAIL PROTECTED] wrote:
Dustin Krysak [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
ok, I added brackets and made my code to:
?php
if ($handle = opendir('../../../mov')) {
while (false !== ($file = readdir($handle))) {
if ($file != '.'  $file != '..') {
$fileName = str_replace('.mov', '', $file);
echo 'option value=../../../mov/' . $file . '' .
$fileName . '/option';
}
}
closedir($handle);
}
?
when viewing my page in a browser, it worked! Now what I am hoping to
do is put this menu on a PHP page, and have a qt movie placeholder and
when this menu is used - replace the placeholder with the selected qt
movie... I am just not sure how to do this.
This should be easy. Please post your QT placeholder (HTML) code. Then 
we
can help.

Regards, Torsten
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[PHP] drop down menu populated from a directory

2004-05-30 Thread Dustin Krysak
Hi there
What I am hoping to do is have a drop down menu that would be populated 
from the contents of a directory via php. Now The link names would be 
generated by the file name minus the file extension. Has anyone seen a 
tutorial on accomplishing something like this? All of the links would 
be to quicktime movies, but I am hoping to have them embedded in HTML 
(or PHP). So the movie is displayed in a browser

thanks in advance!
Dustin
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[PHP] * populate menu from directory *

2004-02-16 Thread Dustin Krysak
Hi there - I am a REAL new PHP coder (yeah I mostly use dreamweaver). I 
was wondering if anyone could point me in the right direction... What I 
want to do is have a generic template page for say a bunch of quicktime 
movies... it would have a movie embedded, and a drop down menu below to 
select the movie you want to watch.. what I was hoping to do was have 
the menu populated by pulling the file names from the movies in the 
directory on the server. I want to be able to simply FTP a new movie 
onto the server, and then have the menu update itself. possible? I 
would also be looking to do something similar with JPGS.

d

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