[PHP] fopen url problems
Anyone know what the error means in this snippet? I am attempting to check if a given .asf file exists on another server but get no further than this error. Not sure what 'message too long' refers to. PHP version is 4.2.1/Apache 2/FreeBSD Thanks. Warning: fopen(http://bluestream/bband/testvideo-bband.asf;, r) - Message too long in /usr/local/www/livebrand.co.uk/www/builder/cstudies.php on line 32 - Karl Phillipson Tribal DDB - a BMP DDB Company http://www. http://www.tribalddb.co.uk tribalddb.co.uk - The information given in the above email and / or attachment is provided without warranty of any kind, either expressed or implied on the part of the writer or the Agency.
RE: [PHP] looping through array with list()/each()
while ( list($key, $val) = each($ser) ); --- ; should not be here
-Original Message-
From: Kevin Porter [mailto:[EMAIL PROTECTED]]
Sent: 25 September 2002 12:13
To: Kevin Porter; '[EMAIL PROTECTED]'
Subject: RE: [PHP] looping through array with list()/each()
I meant $key and $val of course :o)
- Kev
-Original Message-
From: Kevin Porter [SMTP:[EMAIL PROTECTED]]
Sent: 25 September 2002 12:00
To: '[EMAIL PROTECTED]'
Subject: [PHP] looping through array with list()/each()
OK so I've done this hundreds of times, but this time I cannot get it to
work.
Please cast an eye over the following code and output and tell me why $k
and
$v are not being set:
Code:
-
$ser = array( 'first', 'second', 'third', 'fourth', 'fifth' );
reset($ser);
while ( list($key, $val) = each($ser) );
{
echo \$key = $key, \$val = $valbr;
}
-
Output:
--
$key = , $val =
--
I tried giving the $ser array numeric keys and string keys, both made no
difference.
thanks,
- Kev
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RE: [PHP] code to see files in directories
p.s this script came from:
// PHP Spider Trapper
// Copyright 2000 MassTraffic.com
// Unlimted Usage Granted By _Owner_
// You May Use the Program For Free
// Under the CAREWARE liceanse.
// Which states that you may use
// the product for free as long
// as you are happy and take care
// of each other This Script!!
==
Karl Phillipson
PHP SQL Programmer
Saffron Hill Ventures
67 Clerkenwell Road
London
EC1R 5BL
Saffron Hill: 0207 693 8300
Direct Line: 0207 693 8318
-Original Message-
From: Karl Phillipson [mailto:[EMAIL PROTECTED]]
Sent: 08 August 2001 15:30
To: 'Eduardo Kokubo'; [EMAIL PROTECTED]
Subject: RE: [PHP] code to see files in directories
Try this
?php
$level1 = 0;
$baseurl = http://$HTTP_HOST;;
$base = './';
$basedir = opendir($base);
while ($file = readdir($basedir)){
if ($file != '.' $file != '..' eregi(.htm,$file))
{ print(a href=$baseurl/$file$baseurl/$file/aBR\n);
flush();
}
if ($file != '.' $file != '..' is_dir($base/$file)
$file != _data)
{
$level1 = $base/$file;
print(a
href=$baseurl/$file$baseurl/$file/aBR\n); flush();
$seconddir = opendir($level1);
while ($folder = readdir($seconddir))
{
if ($folder != '.' $folder != '..'
eregi(.htm,$folder)){ print(a
href=$baseurl/$file/$folder$baseurl/$file/$folder/aBR\n);
flush();
}
if ($folder != '.' $folder != '..'
is_dir($base/$file/$folder) $folder != _data)
{
$level2 = $level1/$folder;
print(a
href=$baseurl/$file/$folder$baseurl/$file/$folder/aBR\n);
flush();
$thirddir = opendir($level2);
while ($this = readdir($thirddir)){
if ($this != '.' $this != '..'
eregi(.htm,$this))
{
print(a
href=$baseurl/$file/$folder/$thibaseurl/$file/$folder/$this$baseurl/$file/$
folder/$this/aBR\n);
flush();
}
if ($this != '.' $this != '..'
is_dir($base/$file/$folder/$this) $this != _data)
{
$level3 = $level2/$this;
print(a
href=$baseurl/$file/$folder/$this$baseurl/$file/$folder/$this/aBR\n);
flush();
$forthdir = opendir($level3);
while ($that = readdir($forthdir))
{
if ($that != '.' $that != '..'
eregi(.htm,$that))
{
print(a
href=$baseurl/$file/$folder/$this/$that$baseurl/$file/$folder/$this/$that/
aBR\n);
flush();
}
if ($that != '.' $that != '..'
is_dir($base/$file/$folder/$this/$that) $that != _data)
{
$level4 = $level3/$that;
print(a
href=$baseurl/$file/$folder/$this/$that$baseurl/$file/$folder/$this/$that/
aBR\n);
flush();
$fithdir = opendir($level4);
while ($some = readdir($fithdir)){
if ($some != '.' $some != '..'
eregi(.htm,$some))
{
print(a
href=$baseurl/$file/$folder/$this/$that/$some$baseurl/$file/$folder/$this/$
that/$some/aBR\n);
flush();
}
if ($some != '.' $some != '..'
is_dir($base/$file/$folder/$this/$that/$some) $some != _data)
{
$level5 = $level4/$some;
print(a
href=$baseurl/$file/$folder/$this/$that/$some$baseurl/$file/$folder/$this/$
that/$some/aBR\n);
flush();
$sixthdir = opendir($level5);
while ($the = readdir($sixthdir))
{
if ($the != '.' $the != '..'
eregi(.htm,$the)){ print(a
href=$baseurl/$file/$folder/$this/$that/$some/$this/$that/$some/$the$baseur
l/$file/$folder/$this/$that/$some/$the/aBR\n);
flush
[PHP] caching and IE 5
Is anyone else having fun and games with IE 5.0 and caching? I have the no-cache code (below) before anything else in my index file. Following that an include file is pulled in that has a form with a text input field that echos the date and time. Whenever I refresh the page the time does not update to reflect the current time, it sticks with the time that was displayed when the page was first loaded. Even when I close the browser and reopen it the time remains the same. Any pointers on this issue? ?php header (Expires: Mon, 14 Jul 1963 05:00:00 GMT);// Date in the past header (Last-Modified: . gmdate(D, d M Y H:i:s) . GMT); // always modified header (Cache-Control: no-cache, must-revalidate); // HTTP/1.1 header (Pragma: no-cache); ? input type=text name=search_name value=?php echo SEARCH .date(F jS Y G:m A) ? Thx in advance. Karl
RE: [PHP] caching and IE 5
Hmmm, I substituted the date(F jS Y G:m A) function for a time() function and this works fine, on refresh the updated timestamp is visible. (btw system is apache 1.20 running on Hed Rat 7.1 - php 4.05) Can anyone explain why the time() function refreshes and returns the correct value but the date(F jS Y G:m A) does not?? Seems the problem might not be an IE5 caching issue at all ?? Regs, Karl == Karl Phillipson PHP SQL Programmer Saffron Hill Ventures 67 Clerkenwell Road London EC1R 5BL Saffron Hill: 0207 693 8300 Direct Line: 0207 693 8318 -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Sent: 09 August 2001 10:37 To: [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Subject: RE: [PHP] caching and IE 5 Try this head META Http-Equiv=Cache-Control Content=no-cache META Http-Equiv=Pragma Content=no-cache META Http-Equiv=Expires Content=0 /head works for me - try loading www.shanghaiguide.com/main/index.php3 - should do time, and display a different image every time. cheers, lawrence. -Original Message- From: Karl Phillipson [mailto:[EMAIL PROTECTED]] Sent: August 9, 2001 5:21 PM To: '[EMAIL PROTECTED]' Subject: [PHP] caching and IE 5 Is anyone else having fun and games with IE 5.0 and caching? I have the no-cache code (below) before anything else in my index file. Following that an include file is pulled in that has a form with a text input field that echos the date and time. Whenever I refresh the page the time does not update to reflect the current time, it sticks with the time that was displayed when the page was first loaded. Even when I close the browser and reopen it the time remains the same. Any pointers on this issue? ?php header (Expires: Mon, 14 Jul 1963 05:00:00 GMT);// Date in the past header (Last-Modified: . gmdate(D, d M Y H:i:s) . GMT); // always modified header (Cache-Control: no-cache, must-revalidate); // HTTP/1.1 header (Pragma: no-cache); ? input type=text name=search_name value=?php echo SEARCH .date(F jS Y G:m A) ? Thx in advance. Karl -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] MySQL: Select ALL
if(!($result=mysql_db_query(SELECT username FROM users $db)))
{
print Error getting rows;
exit();
}
while($row=mysql_fetch_array($result))
{
$username=$row[username];
print $usernamebr;
}
mysql_free_result($result);
kp
==
Karl Phillipson
PHP SQL Programmer
Saffron Hill Ventures
67 Clerkenwell Road
London
EC1R 5BL
Saffron Hill: 0207 693 8300
Direct Line: 0207 693 8318
-Original Message-
From: Tarrant Costelloe [mailto:[EMAIL PROTECTED]]
Sent: 09 August 2001 12:14
To: '[EMAIL PROTECTED]'
Subject: [PHP] MySQL: Select ALL
When saying; mysql_query(SELECT username FROM users,$db); it only show's
one of the first users in the column users.
Could someone please tell me how to make it print out the complete column
list of usernames. I have tried mysql_query(SELECT username(*) FROM
users,$db); - but no luck.
Thanks
Taz
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RE: [PHP] code to see files in directories
/$this/$that/$some/$the/$it$baseurl/$file/$folde
r/$this/$that/$some/$the/$it/aBR\n);
flush();
}
if ($it != '.' $it != '..'
is_dir($base/$file/$folder/$this/$that/$some/$the/$it) $it != _data)
{
$level7 = $level6/$it;
print(a
href=$baseurl/$file/$folder/$this/$that/$some/$the/$it$baseurl/$file/$folde
r/$this/$that/$some/$the/$it/aBR\n); flush();
$eighthdir = opendir($level7);
while ($deep =
readdir($eighthdir)){
if ($deep1 != '.' $deep1 != '..'
eregi(.htm,$deep1)){ print(a
href=$baseurl/$file/$folder/$this/$that/$some/$the/$it/$deep1$baseurl/$file
/$folder/$this/$that/$some/$the/$it/$deep1/aBR\n); flush(); }
if ($deep1 != '.' $deep1 != '..'
is_dir($base/$file/$folder/$this/$that/$some/$the/$it/$deep1) $deep1
!= _data)
{
$level8 = $level7/$deep1;
print(a
href=$baseurl/$file/$folder/$this/$that/$some/$the/$it/$deep1$baseurl/$file
/$folder/$this/$that/$some/$the/$it/$some/$the/$it/$deep1/aBR\n);
flush();
}}
}}
}}
}}
}}
}}
}}
}}
?
==
Karl Phillipson
PHP SQL Programmer
Saffron Hill Ventures
67 Clerkenwell Road
London
EC1R 5BL
Saffron Hill: 0207 693 8300
Direct Line: 0207 693 8318
-Original Message-
From: Eduardo Kokubo [mailto:[EMAIL PROTECTED]]
Sent: 08 August 2001 13:52
To: [EMAIL PROTECTED]
Cc: Eduardo Kokubo
Subject: [PHP] code to see files in directories
I think I saw a code to list the files, subdirectories and the files in the
subdirectories of a simple directory in this list some time ago, but I
didn't save it. Considering the quantitie of messages in this list, It's
quite dificult to find this specific code, so ask the person who did it or
someone else to write this code again.
I'm using this one:
$publico = ftp_nlist ($servidor, public_html/publico);
$cont = 0;
while ($publico[$cont]){
print $publico[$cont]br;
$cont++;}
This code doesn't show the files in the subdirectories and it requires ftp
connection. Not very efficient.
Thanks in advance.
Is there a problem if I just write thanks in advance??? It's easier then
writting back to thanks everybody :)
[PHP] text imports
Hi, I have been given a (notepad generated) text file which contains a list of countries in a format such as: United Kingdom, United States, Blah, Blah, Blah, I have imported the data into a countries table in a mySQL database using the excellent 'mysqlfront' prog. No probs on the import itself except for some pesky pipes that I believe to be carriage returns. Anyone know a way I can strip these out so I have nice clean data. Ta in adavance. Karl Saffron Hill Ventures 67 Clerkenwell Road London EC1R 5BL Saffron Hill: 0207 693 8300
RE: [PHP] text imports
Yup, thanks Wagner. I can do this within PHP itself using trim or chop, I was hoping for a snippet of SQL code that would do it from the command line. This is what have done: LOAD DATA LOCAL INFILE 'C:\MYDIR\countries.txt' INTO TABLE DBNAME.COUNTRY LINES TERMINATED BY ',' (COUNTRY_NAME) == Karl Phillipson PHP SQL Programmer Saffron Hill Ventures 67 Clerkenwell Road London EC1R 5BL Saffron Hill: 0207 693 8300 Direct Line: 0207 693 8318 -Original Message- From: Wagner Tomy [mailto:[EMAIL PROTECTED]] Sent: 07 August 2001 12:00 To: Karl Phillipson; 'Alexander Wagner'; MindHunter; [EMAIL PROTECTED] Subject: Re: [PHP] text imports http://www.php.net/manual/en/function.chop.php Returns the argument string without trailing whitespace, including newlines Wagner Tomy Web Developer Editus S.A. - Original Message - From: Karl Phillipson [EMAIL PROTECTED] To: 'Alexander Wagner' [EMAIL PROTECTED]; MindHunter [EMAIL PROTECTED]; [EMAIL PROTECTED] Sent: Tuesday, August 07, 2001 12:53 PM Subject: [PHP] text imports Hi, I have been given a (notepad generated) text file which contains a list of countries in a format such as: United Kingdom, United States, Blah, Blah, Blah, I have imported the data into a countries table in a mySQL database using the excellent 'mysqlfront' prog. No probs on the import itself except for some pesky pipes that I believe to be carriage returns. Anyone know a way I can strip these out so I have nice clean data. Ta in adavance. Karl Saffron Hill Ventures 67 Clerkenwell Road London EC1R 5BL Saffron Hill: 0207 693 8300 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] text imports
So if this is the way to do it in SQL, is there a way to get rid of the pipe linefeeds using SQL too? If not I s'pose the solution is to run a php 'trim' script, grab the data, perform the modifications and then re-insert the data back into the table Bit long winded but if that's the only way? == Karl Phillipson PHP SQL Programmer Saffron Hill Ventures 67 Clerkenwell Road London EC1R 5BL Saffron Hill: 0207 693 8300 Direct Line: 0207 693 8318 -Original Message- From: Wagner Tomy [mailto:[EMAIL PROTECTED]] Sent: 07 August 2001 12:06 To: Karl Phillipson; [EMAIL PROTECTED] Subject: Re: [PHP] text imports ah k, yes that's the way to do it in SQL ;p Tomy Wagner Web Developer Editus S.A. - Original Message - From: Karl Phillipson [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Tuesday, August 07, 2001 1:08 PM Subject: RE: [PHP] text imports Yup, thanks Wagner. I can do this within PHP itself using trim or chop, I was hoping for a snippet of SQL code that would do it from the command line. This is what have done: LOAD DATA LOCAL INFILE 'C:\MYDIR\countries.txt' INTO TABLE DBNAME.COUNTRY LINES TERMINATED BY ',' (COUNTRY_NAME) == Karl Phillipson PHP SQL Programmer Saffron Hill Ventures 67 Clerkenwell Road London EC1R 5BL Saffron Hill: 0207 693 8300 Direct Line: 0207 693 8318 -Original Message- From: Wagner Tomy [mailto:[EMAIL PROTECTED]] Sent: 07 August 2001 12:00 To: Karl Phillipson; 'Alexander Wagner'; MindHunter; [EMAIL PROTECTED] Subject: Re: [PHP] text imports http://www.php.net/manual/en/function.chop.php Returns the argument string without trailing whitespace, including newlines Wagner Tomy Web Developer Editus S.A. - Original Message - From: Karl Phillipson [EMAIL PROTECTED] To: 'Alexander Wagner' [EMAIL PROTECTED]; MindHunter [EMAIL PROTECTED]; [EMAIL PROTECTED] Sent: Tuesday, August 07, 2001 12:53 PM Subject: [PHP] text imports Hi, I have been given a (notepad generated) text file which contains a list of countries in a format such as: United Kingdom, United States, Blah, Blah, Blah, I have imported the data into a countries table in a mySQL database using the excellent 'mysqlfront' prog. No probs on the import itself except for some pesky pipes that I believe to be carriage returns. Anyone know a way I can strip these out so I have nice clean data. Ta in adavance. Karl Saffron Hill Ventures 67 Clerkenwell Road London EC1R 5BL Saffron Hill: 0207 693 8300 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] user's ip
Read this: http://www.php.net/manual/en/function.getenv.php $ip = getenv (REMOTE_ADDR); == Karl Phillipson PHP SQL Programmer Saffron Hill Ventures 67 Clerkenwell Road London EC1R 5BL Saffron Hill: 0207 693 8300 Direct Line: 0207 693 8318 -Original Message- From: Adrian D'Costa [mailto:[EMAIL PROTECTED]] Sent: 07 August 2001 11:25 To: php general list Subject: [PHP] user's ip Hi, I am trying to get the ip address of any user browsing a particular page. I tried $REMOTE_ADDR but that give me only the remote address. What would be the best way? Adrian -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Split array
you could use implode http://www.php.net/manual/en/function.implode.php == Karl Phillipson PHP SQL Programmer Saffron Hill Ventures 67 Clerkenwell Road London EC1R 5BL Saffron Hill: 0207 693 8300 Direct Line: 0207 693 8318 -Original Message- From: Veniamin Goldin [mailto:[EMAIL PROTECTED]] Sent: 07 August 2001 13:02 To: [EMAIL PROTECTED] Subject: [PHP] Split array hello ! Please help me. How do I split array so, that I'll get string variable with , delimeter of each array value ? Thank you! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP] Best way to take a copy of a Database from Server to server
This might be of some use? http://www.mysql.com/doc/m/y/mysqlhotcopy.html == Karl Phillipson PHP SQL Programmer Saffron Hill Ventures 67 Clerkenwell Road London EC1R 5BL Saffron Hill: 0207 693 8300 Direct Line: 0207 693 8318 -Original Message- From: elias [mailto:[EMAIL PROTECTED]] Sent: 07 August 2001 14:53 To: [EMAIL PROTECTED] Subject: [PHP] Best way to take a copy of a Database from Server to server Hello. I have two MySql databases running on different servers. I have no root access and only PHP + Mysql and MysqlAdmin. How can i take a dump of first database (which is about 1MB) and restore that dump on the second one? Actually, I'm doing a structure dump, but the outputed SQL text is very big!..I'm not able to paste it all in the second server's sql query textbox. Any ideas? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] php and javascript
Does anyone know how to pass php variables to a javascript for processing. I have a DHTML menu system that requires variables be attached to the url contained within it. Using echo does not print the variable to the url. Is there another way? Thx in advance. Karl == Karl Phillipson PHP SQL Programmer Saffron Hill Ventures 67 Clerkenwell Road London EC1R 5BL ==
