Thanks! That worked almost. It removed everything except for the 2 %
signs.
How might I remove those as well?
"Leif K-Brooks" <[EMAIL PROTECTED]> wrote in message
news:<[EMAIL PROTECTED]>...
> Try this (entirely untested!):
> $final_footer =
> preg_replace('%INCLUDE_FILE\\[[^\\]]*\\]%','',$final_footer);
>
> Nate wrote:
>
> >hi,
> >
> >i need to search $final_footer for a string such as
> >%INCLUDE_FILE[/path/to/file]% (where /path/to/file could be anything)
> >and delete it from the string. it being %INCLUDE_FILE[/path/to/file]%
> >(not just
> >/path/to/file)
> >
> >im new to regexps but im guessing I should use preg_match for this?
> >
> >Can someone give me a code example?
> >
> >thanks much
> >Nate
> >
> >
> >
> >
> >
>
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