uot; dollars this week.\n");
?>
Returns:
Today's Date:
1 June 10, 2007
, you will be out 0 dollars this week.
Thanks in advance for any feedback!
"Tijnema" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
My host company must have an installation/configuration issue.
Variables from forms are not being passed to the php scripts that are sent
via
Has anyone heard of this and know of the fix?
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My host company must have an installation/configuration issue.
Variables from forms are not being passed to the php scripts that are sent
via
Has anyone heard of this and know of the fix?
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To unsubscribe, visit: http://www.php.net/unsub.php
Is there a way to attach a file with the mail() function?
Thanks!
Unfortunately, they are indeed enclosed by double quotes
Roy
-Original Message-
From: Jay Blanchard [mailto:[EMAIL PROTECTED]
Sent: Thursday, July 31, 2003 12:58 PM
To: Roy W; [EMAIL PROTECTED]
Subject: RE: [PHP] Escaping nasty quotes
[snip]
Sorry...Because of the double quote near
Thanks, Chris. But I kept what I had and then just added:
$query = addslashes($query);
Doesn't return an error.. But doesn't complete the task.
:-(
-Original Message-
From: Chris Shiflett [mailto:[EMAIL PROTECTED]
Sent: Thursday, July 31, 2003 12:39 PM
To: Roy W; [EMAIL
Sorry...Because of the double quote near the ENCLOSED BY .. It delivers a
PARSE ERROR
?
-Original Message-
From: Jay Blanchard [mailto:[EMAIL PROTECTED]
Sent: Thursday, July 31, 2003 12:38 PM
To: Roy W; [EMAIL PROTECTED]
Subject: RE: [PHP] Escaping nasty quotes
[snip]
$query = "
I have this:
$query = "LOAD DATA LOCAL INFILE '/home/data.txt' INTO TABLE mytable FIELDS
TERMINATED BY ',' ENCLOSED BY '" . '"' . "' ";
$result = MYSQL_QUERY($query);
PRINT "$query2";
The query doesn't take ... but if I cut and paste the printed response into
the mysql server manually ... works
If I have:
$firstdate = "2003-06-28";
then how can I get $firstdate plus 4 days?
Thanks!
Can someone let me know how to return TWO variables from a function
I tried:
return $var1, $var2;
But I get parse errors and other errors.
Thanks!
$amount is a calculated number
If $amount equals for example 52., how do I get that to print as "52.00"
similarly, if amount = 52.5 how do I get that to print as "52.50"
Thanks!
(looked at all sort of type casting manual stuff to no avail)
I have a bunch of variables stuffed in myArray()
I want to run a MySQL SELECT statement ($query=" ..") where it will
access only those records in the database "WHERE" table.fieldname is found
in myArray
Is there a simple one liner? Or do I have to "loop" it through (kinda nasty
as you can
Where can I find a routine or PHP prog that will evaluate the distances
between zip codes or "find within X miles of a zip code"
Any ideas?
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To conta
I have several scripts that when you complete a form it executes a PHP
script.
At the end of each script I have a simple statement saying it's done and
then a place to hyperlink back to a given page:
PRINT "Process complete. Click here to continue";
But what I really wanna do is just have the s
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