Re: [PHP] Pop up window in PHP code

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Re: [PHP] Pop up window in PHP code

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Re: [PHP] preg_replace();

) and the (space) chars where are between (double-quotes) by an underscore _ with the preg_replace(); funtction. Can someone help me to find the correct regex. Thanks in advance Seb -- Best regards, mailto:[EMAIL PROTECTED] -- PHP General Mailing List (http

Re[2]: [PHP] preg_replace();

I have tasted the code and it worked fine (if I got you right): $old_string=lazy \|\ dog; $new_string=str_replace('|', '_', $old_string); print $new_string; I got lazy_dog Ed Friday, February 2, 2007, 10:01:14 PM, you wrote: Thanks, but I think that I must use preg_replace because the

Re[4]: [PHP] preg_replace();

Try this one: $old_string=lazy \some chars|some chars\ dog; $new_string=str_replace('|', '_', $old_string); print $new_string; Ed Friday, February 2, 2007, 10:39:59 PM, you wrote: ok, but : $old_string=lazy \some chars|some chars\ dog; $new_string=str_replace('|', '_', $old_string);

[PHP] proxy

Hi list, I am trying to create a link checker that would look for broken URLs with help of the following code $handle = @fopen(http://www.circle.am;, r); if ($handle): print OK; else: print Error; endif; The problem is that I want to check if the links are accessible under certain proxy, so is

Re[2]: [PHP] proxy

Thank you Roman and Jochem, I'll try both. Best regards, Ed Sunday, January 21, 2007, 6:27:44 PM, you wrote: # [EMAIL PROTECTED] / 2007-01-21 17:29:56 +0300: I am trying to create a link checker that would look for broken URLs with help of the following code $handle =