Re: [PHP] GD Library and outputing image

[tedd]

At 9:17 PM +0100 6/13/07, Ross wrote:

Never really used the GD much before very straightforward but how do I
output the image on a page. This is  fine on a php page on its own but what
about one where the headers are already sent?


Ross:

That's not a problem. See this:

http://xn--nvg.com/rotated_text  -- if your browser chokes, get a 
better browser


The image code (text.php) is:

?php
Header (Content-type: image/gif);
$im = imagecreate (150, 150);
$background = ImageColorAllocate ($im, 238, 238, 238);
$text_color = ImageColorAllocate ($im, 00, 51, 102);//#036 00 33 66 HEX
ImageTTFText ($im, 20, 45, 30, 130, $text_color, arial.ttf,
  Hello World...);
ImageGif ($im);
ImageDestroy ($im);
?

and it's called from html like this:

img src=text.php

If you put this into your site, you'll need arial.tff to make it 
work, but you can find it in lot's of places.


Cheers,

tedd


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[PHP] GD Library and outputing image

[Ross]

Never really used the GD much before very straightforward but how do I 
output the image on a page. This is  fine on a php page on its own but what 
about one where the headers are already sent?


I take it I can do something like  this img 
scr=get_image.php?url=$img_url/a. Anyone got a better method?




$image = imagecreatefromjpeg($img_url);
if ($image === false) { die ('Unable to open image'); }

// Get original width and height
echo $width = imagesx($image);
echo $height = imagesy($image);

// New width and height
$new_width = 200;
$new_height = 150;

// Resample
$image_resized = imagecreatetruecolor($new_width, $new_height);
imagecopyresampled($image_resized, $image, 0, 0, 0, 0, $new_width, 
$new_height, $width, $height);

// Display resized image
header('Content-type: image/jpeg');
imagejpeg($image_resized);
die();

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Re: [PHP] GD Library and outputing image

[Daniel Brown]

On 6/13/07, Ross [EMAIL PROTECTED] wrote:

Never really used the GD much before very straightforward but how do I
output the image on a page. This is  fine on a php page on its own but what
about one where the headers are already sent?


I take it I can do something like  this img
scr=get_image.php?url=$img_url/a. Anyone got a better method?




$image = imagecreatefromjpeg($img_url);
if ($image === false) { die ('Unable to open image'); }

// Get original width and height
echo $width = imagesx($image);
echo $height = imagesy($image);

// New width and height
$new_width = 200;
$new_height = 150;

// Resample
$image_resized = imagecreatetruecolor($new_width, $new_height);
imagecopyresampled($image_resized, $image, 0, 0, 0, 0, $new_width,
$new_height, $width, $height);

// Display resized image
header('Content-type: image/jpeg');
imagejpeg($image_resized);
die();

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   Aside from perhaps changing die(); to exit;, though not necessary,
I'd say that it looks like you're right on track.  Until you find a
better way to have HTML display an image than through IMG SRC=..., I
think it's good to go.

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[office] (570-) 587-7080 Ext. 272
[mobile] (570-) 766-8107

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Re: [PHP] GD Library and outputing image

[Stephen]

Ross [EMAIL PROTECTED] wrote:Never really used the GD much before very 
straightforward but how do I 
output the image on a page. This is fine on a php page on its own but what 
about one where the headers are already sent?
   
  Save the image as file, first.
   
  The href src= etc

Re: [PHP] GD Library and outputing image

[Daniel Brown]

On 6/13/07, Stephen [EMAIL PROTECTED] wrote:



Ross [EMAIL PROTECTED] wrote:Never really used the GD much before very 
straightforward but how do I
output the image on a page. This is fine on a php page on its own but what
about one where the headers are already sent?

  Save the image as file, first.

  The href src= etc



   If space isn't an issue, that's an alternative answer

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Daniel P. Brown
[office] (570-) 587-7080 Ext. 272
[mobile] (570-) 766-8107

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