echo(select name='...')
while ($array = mysql_fetcharray($mysql))
{echo(option{$array[catname]}/option);
}
echo(/select)
that's the simple version - you may want to put the
whole lot inside ...
if (mysql_numrows())
{ ...
} else
{echo(warning);
}
I may have got the function names wrong - I use an
abstraction layer these days
Tim Ward
http://www.chessish.com
mailto:[EMAIL PROTECTED]
- Original Message -
From: Steve Jackson [EMAIL PROTECTED]
To: PHP General [EMAIL PROTECTED]
Sent: Tuesday, December 10, 2002 3:24 PM
Subject: [PHP] How do I populate a select?
How do I populate a select list with a list of category names from a DB?
I can select the names using a query but how do I loop through them to
display them in a select?
My query below will return the cat names. (when I do something with it
like echoing the result)
$mysql = mysql_query(SELECT catname FROM categories ORDER BY catid);
But I want to give each catname in the DB a unique name in a form select
and don't know how to go about it.
Tutorials or tips anyone?
Regards,
Steve Jackson
Web Developer
Viola Systems Ltd.
http://www.violasystems.com
[EMAIL PROTECTED]
Mobile +358 50 343 5159
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