[PHP] ImageCreateFromJpeg error
I am trying to use the following piece of code: $img_resized = imagecreate($img_new_width, $img_new_height); $img_source = ImageCreateFromJpeg($pa_strDocroot.$pa_strReadFold./.$this-Name); imagecopyresized($img_resized, $img_source, 0 , 0 , 0 , 0, $img_new_width, $img_new_height, $this-Width, $this-Height); The code runs fine on my Windows machine, but ImageCreateFromJpeg() errors on the server. I am sharing a server, and they have it set to not show any errors, so I can't tell you what the exact error message is. I have been able to establish that: - GD is installed--the other image functions work; - I believe it is a later version of GD that supports JPEGs, since ImageCreateFromJpeg exists as a function [does that follow?]; - The paths are correct, since they work on my machine, and work in other places; - The write folder has full permissions set, just to be safe; - The images in the read folder have read permissions set. Is there some sort of a temporary directory as well, where permissions have to be set? A few sites have mentioned a --with-jpeg-dir configuration setting. Do the permissions for that need to be checked? Any help would be appreciated. Scott -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] ImageCreateFromJpeg error
On Friday 22 November 2002 03:21, Scott Nagel wrote:
I am trying to use the following piece of code:
$img_resized = imagecreate($img_new_width, $img_new_height);
$img_source =
ImageCreateFromJpeg($pa_strDocroot.$pa_strReadFold./.$this-Name);
imagecopyresized($img_resized, $img_source, 0 , 0 , 0 , 0, $img_new_width,
$img_new_height, $this-Width, $this-Height);
The code runs fine on my Windows machine, but ImageCreateFromJpeg() errors
on the server. I am sharing a server, and they have it set to not show any
errors, so I can't tell you what the exact error message is.
Just use:
ini_set(display_errors, TRUE);
somewhere near the top of your page.
I have been
able to establish that:
- GD is installed--the other image functions work;
- I believe it is a later version of GD that supports JPEGs, since
ImageCreateFromJpeg exists as a function [does that follow?];
- The paths are correct, since they work on my machine, and work in other
places;
- The write folder has full permissions set, just to be safe;
Don't forget it needs the execute flag set as well ('x').
- The images in the read folder have read permissions set.
Ditto.
Is there some sort of a temporary directory as well, where permissions have
to be set? A few sites have mentioned a --with-jpeg-dir configuration
setting.
That's only of relevance when /compiling/ php.
Do the permissions for that need to be checked?
No.
--
Jason Wong - Gremlins Associates - www.gremlins.biz
Open Source Software Systems Integrators
* Web Design Hosting * Internet Intranet Applications Development *
/*
Logic is the chastity belt of the mind!
*/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] ImageCreateFromJpeg error
Thanks for the help. Didn't know about the ini_set() function. The error
was 'No JPEG support in this PHP build'.
Jason Wong [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]...
On Friday 22 November 2002 03:21, Scott Nagel wrote:
I am trying to use the following piece of code:
$img_resized = imagecreate($img_new_width, $img_new_height);
$img_source =
ImageCreateFromJpeg($pa_strDocroot.$pa_strReadFold./.$this-Name);
imagecopyresized($img_resized, $img_source, 0 , 0 , 0 , 0,
$img_new_width,
$img_new_height, $this-Width, $this-Height);
The code runs fine on my Windows machine, but ImageCreateFromJpeg()
errors
on the server. I am sharing a server, and they have it set to not show
any
errors, so I can't tell you what the exact error message is.
Just use:
ini_set(display_errors, TRUE);
somewhere near the top of your page.
I have been
able to establish that:
- GD is installed--the other image functions work;
- I believe it is a later version of GD that supports JPEGs, since
ImageCreateFromJpeg exists as a function [does that follow?];
- The paths are correct, since they work on my machine, and work in
other
places;
- The write folder has full permissions set, just to be safe;
Don't forget it needs the execute flag set as well ('x').
- The images in the read folder have read permissions set.
Ditto.
Is there some sort of a temporary directory as well, where permissions
have
to be set? A few sites have mentioned a --with-jpeg-dir configuration
setting.
That's only of relevance when /compiling/ php.
Do the permissions for that need to be checked?
No.
--
Jason Wong - Gremlins Associates - www.gremlins.biz
Open Source Software Systems Integrators
* Web Design Hosting * Internet Intranet Applications Development *
/*
Logic is the chastity belt of the mind!
*/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
