[PHP] Re: subtracting dates...
yeah, i was thinking that before i decided to post to the newsgroup. i
thought there was some simple way of doing it and id be wasting my time.
obviosuly not
Craig Roberts [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Try something along the lines of
if($current_MM $MM) {
$age = $calculatedage - 1;
}
you'll also need to do something like this with the day of the month if
the
user's bday is in the current month.
at least... i think that works out :$
Craig Roberts
John Ryan [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Hi,
In mySQL, I store dates as -MM-DD, a standard DATE type. It stores
users
date of births. I need to calculate in a PHP script, the users age from
this
DOB. I get a PHP date in the same format as the mySQL and subtract,
which
returns the year rounded off. ie, it doesnt matter if your birthdays in
june
of 1983 and the date is januray 2003, your age is still returned as 20,
when
it should be 19.
Does anyone know how can i get the right age?
--
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[PHP] Re: subtracting dates...
Another idea (slightly simpler)...
how about using mktime(); to create a timestamp from your date info, and
subtract that from the current timestamp - leaving (i think) the person's
age in seconds...
Then just do some math...
hmm... is that really simpler? well it seemed it when i started typing
craig :)
John Ryan [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
yeah, i was thinking that before i decided to post to the newsgroup. i
thought there was some simple way of doing it and id be wasting my time.
obviosuly not
Craig Roberts [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Try something along the lines of
if($current_MM $MM) {
$age = $calculatedage - 1;
}
you'll also need to do something like this with the day of the month if
the
user's bday is in the current month.
at least... i think that works out :$
Craig Roberts
John Ryan [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Hi,
In mySQL, I store dates as -MM-DD, a standard DATE type. It stores
users
date of births. I need to calculate in a PHP script, the users age
from
this
DOB. I get a PHP date in the same format as the mySQL and subtract,
which
returns the year rounded off. ie, it doesnt matter if your birthdays
in
june
of 1983 and the date is januray 2003, your age is still returned as
20,
when
it should be 19.
Does anyone know how can i get the right age?
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: subtracting dates...
On Sat, Aug 02, 2003 at 08:30:34PM +0100, John Ryan wrote: In mySQL, I store dates as -MM-DD, a standard DATE type. It stores users date of births. I need to calculate in a PHP script, the users age from this DOB. I get a PHP date in the same format as the mySQL and subtract, which returns the year rounded off. ie, it doesnt matter if your birthdays in june of 1983 and the date is januray 2003, your age is still returned as 20, when it should be 19. The function you're probably looking for is floor(). Does anyone know how can i get the right age? One quick way would be simple subtraction: $old = 1973-06-02; $new = 2003-08-02; $year = 60*60*24*365.25; // seconds in a year $age = strtotime($new) - strtotime($old); print Age in years: . floor($age / $year) . \n; But you'll run into infrequent problems surrounding leap years. I'm sure there's a more accurate way to do this, perhaps even using MySQL's somewhat more advanced (and less timestamp-centric) date calculation functions, but this is what I can come up with on short notice. Note that strtotime will give NEGATIVE TIMESTAMPS for dates earlier than Jan 1st 1970 at midnight GMT, so this still works for folks over 33. ;) -- Paul Chvostek [EMAIL PROTECTED] it.canadahttp://www.it.ca/ Free PHP web hosting!http://www.it.ca/web/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: subtracting dates...
Try something along the lines of
if($current_MM $MM) {
$age = $calculatedage - 1;
}
you'll also need to do something like this with the day of the month if the
user's bday is in the current month.
at least... i think that works out :$
Craig Roberts
John Ryan [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Hi,
In mySQL, I store dates as -MM-DD, a standard DATE type. It stores
users
date of births. I need to calculate in a PHP script, the users age from
this
DOB. I get a PHP date in the same format as the mySQL and subtract, which
returns the year rounded off. ie, it doesnt matter if your birthdays in
june
of 1983 and the date is januray 2003, your age is still returned as 20,
when
it should be 19.
Does anyone know how can i get the right age?
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Subtracting dates in php
try http://www.phpclasses.org -shiva Mike Mannakee [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Anyone know of an easy way to add or subtract dates in php the way you can in mysql? Easier, that is, than coding the logic by hand? This seems like a total pain. Mike -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
