I didn't take the time to read your code too thoroughly, but remember to
have your select name to be anything with [] at the end of it, from the
look of your name field you have something inside the [], you need to get
rid of the rec_pd4 and just call it x[] or whatever you would like to call
it as long as the [] is empty :) I hope that made sense!
Rick
From: Tom Beidler [EMAIL PROTECTED]
Date: Fri, 14 Sep 2001 17:26:50 -0700
To: php list [EMAIL PROTECTED]
Subject: [PHP] multiple selections in list/menu field
I'm trying to use a list/menu field with multiple options allowed but I'm
only getting the very last selection.
Here's part of my code to build the list/menu field;
print (tdselect name=\x[rec_pd4]\ multiple size=\15\\n);
print ($option_pd4);
print ( /select/td\n);
Here's the code to build the options;
$pd4arry = array(array(c1,,Bookpacks Daypacks),array(c2,,Mini
Packs/Diaper Bag),array(c3,,Shoulder Bags/Briefcase));
foreach($pd4arry as $value) {
if (($value[0] == $category_code) || ($value[0] == $x[rec_pd4])) {
$option_pd4 .= option
value=\$value[0]\selected$value[1]/option\n;
} else {
$option_pd4 .= option
value=\$value[0]\$value[1]/option\n;
}
}
The field displays fine but I only get the last option. I'm testing with IE
5.
Let me know if this is not a PHP issue but I thought there might be
something that would prevent me from using this type of field with PHP.
Thanks,
Tom
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