[PHP] multple select forms... going to hit my head against a wall ..
Hi all
I'm having a slight little problem .. I can't seem to solve..
I have a multiple select form .. that i select mutiple options from and then it
creates a variable called $select
now if I display $select .. I only get the last selected value .. here foloows test
code..
?
if ($select==""){
print"
form method=\"post\" name=\"select\" action=\"test.php3\"
SELECT MULTIPLE NAME=\"select\"
Option VALUE=\"Chocolate\"Chocolate/Chocolate Chip
Option VALUE=\"Peanut\"Peanut Brittle/Vanilla
Option Selected VALUE=\"Cookie\"Cookie Batter
Option VALUE=\"Blueberry\"Vanilla/Blueberry
Option VALUE=\"Caramel\"Caramel Swirl
Option VALUE=\"Other\"Other...
/selectbr
input type=\"submit\" name=\"send\" value=\"test\"
/form
";
}else{
print $select;
}
?
I'm de missing something ... can sombody please lend a hand .. thanks
Henti Smith
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Re: [PHP] multple select forms... going to hit my head against a wall ..
hey,
since u are slecting multiple options you'll have to use an array
here's how.i u need explanation,feel free to mail me:
?
if ($select==""){
print"
form method=\"post\" name=\"select\" action=\"test.php3\"
SELECT MULTIPLE NAME=\"select[]\"
Option VALUE=\"Chocolate\"Chocolate/Chocolate Chip
Option VALUE=\"Peanut\"Peanut Brittle/Vanilla
Option Selected VALUE=\"Cookie\"Cookie Batter
Option VALUE=\"Blueberry\"Vanilla/Blueberry
Option VALUE=\"Caramel\"Caramel Swirl
Option VALUE=\"Other\"Other...
/selectbr
input type=\"submit\" name=\"send\" value=\"test\"
/form
";
}else{
///count array
$num = count($select);
file://loop through array
for($i = 0;$i $num;$i++){
print $select[$i] . "br";
}
}
?
- Original Message -----
From: [EMAIL PROTECTED]
To: PHP list [EMAIL PROTECTED]
Sent: Tuesday, January 23, 2001 11:42 AM
Subject: [PHP] multple select forms... going to hit my head against a wall
..
Hi all
I'm having a slight little problem .. I can't seem to solve..
I have a multiple select form .. that i select mutiple options from and
then it creates a variable called $select
now if I display $select .. I only get the last selected value .. here
foloows test code..
?
if ($select==""){
print"
form method=\"post\" name=\"select\" action=\"test.php3\"
SELECT MULTIPLE NAME=\"select\"
Option VALUE=\"Chocolate\"Chocolate/Chocolate Chip
Option VALUE=\"Peanut\"Peanut Brittle/Vanilla
Option Selected VALUE=\"Cookie\"Cookie Batter
Option VALUE=\"Blueberry\"Vanilla/Blueberry
Option VALUE=\"Caramel\"Caramel Swirl
Option VALUE=\"Other\"Other...
/selectbr
input type=\"submit\" name=\"send\" value=\"test\"
/form
";
}else{
print $select;
}
?
I'm de missing something ... can sombody please lend a hand .. thanks
Henti Smith
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
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Re: [PHP] multple select forms... going to hit my head against a wall ..
u ... $select is an array .. so echo $select will just produce
"array" ..
On Tue, Jan 23, 2001 at 12:44:20PM -, Jon Haworth wrote:
Try either:
?
input type="hidden" name="select" value="?php echo $select; ?"
?php
OR
printf ("input type=\"hidden\" name=\"select\" value=\"%s\"",
$select);
HTH
Jon
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: 23 January 2001 12:27
To: Adrian Murphy
Cc: PHP list
Subject: Re: [PHP] multple select forms... going to hit my head against
a wall ..
Having soved this .. thanks .. now for the next question .. *grin*
I have the $select ... but I only use it on the next page .. heheh
so I'm trying the following ..
input type=\"hidden\" name=\"select\" value=\"$select\"
which of course doens't work .. nor does
input type=\"hidden\" name=\"select[]" value=\"$select\"
any idea on how to pass an array on in an input field in a form ?
Henti
On Tue, Jan 23, 2001 at 12:01:40PM -, Adrian Murphy wrote:
hey,
since u are slecting multiple options you'll have to use an array
here's how.i u need explanation,feel free to mail me:
?
if ($select==""){
print"
form method=\"post\" name=\"select\" action=\"test.php3\"
SELECT MULTIPLE NAME=\"select[]\"
Option VALUE=\"Chocolate\"Chocolate/Chocolate Chip
Option VALUE=\"Peanut\"Peanut Brittle/Vanilla
Option Selected VALUE=\"Cookie\"Cookie Batter
Option VALUE=\"Blueberry\"Vanilla/Blueberry
Option VALUE=\"Caramel\"Caramel Swirl
Option VALUE=\"Other\"Other...
/selectbr
input type=\"submit\" name=\"send\" value=\"test\"
/form
";
}else{
///count array
$num = count($select);
file://loop through array
for($i = 0;$i $num;$i++){
print $select[$i] . "br";
}
}
?
- Original Message -
From: [EMAIL PROTECTED]
To: PHP list [EMAIL PROTECTED]
Sent: Tuesday, January 23, 2001 11:42 AM
Subject: [PHP] multple select forms... going to hit my head against a wall
..
Hi all
I'm having a slight little problem .. I can't seem to solve..
I have a multiple select form .. that i select mutiple options from and
then it creates a variable called $select
now if I display $select .. I only get the last selected value .. here
foloows test code..
?
if ($select==""){
print"
form method=\"post\" name=\"select\" action=\"test.php3\"
SELECT MULTIPLE NAME=\"select\"
Option VALUE=\"Chocolate\"Chocolate/Chocolate Chip
Option VALUE=\"Peanut\"Peanut Brittle/Vanilla
Option Selected VALUE=\"Cookie\"Cookie Batter
Option VALUE=\"Blueberry\"Vanilla/Blueberry
Option VALUE=\"Caramel\"Caramel Swirl
Option VALUE=\"Other\"Other...
/selectbr
input type=\"submit\" name=\"send\" value=\"test\"
/form
";
}else{
print $select;
}
?
I'm de missing something ... can sombody please lend a hand .. thanks
Henti Smith
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
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RE: [PHP] multple select forms... going to hit my head against a wall ..
Sorry, my bad. I should have spotted the cunning way he used the word
"array", really :-)
Eyes closing. More coffee. glug aahaahhhrrrghhh
Cheers
Jon
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: 23 January 2001 12:45
To: Jon Haworth
Cc: '[EMAIL PROTECTED]'
Subject: Re: [PHP] multple select forms... going to hit my head against
a wall ..
u ... $select is an array .. so echo $select will just produce
"array" ..
On Tue, Jan 23, 2001 at 12:44:20PM -, Jon Haworth wrote:
Try either:
?
input type="hidden" name="select" value="?php echo $select; ?"
?php
OR
printf ("input type=\"hidden\" name=\"select\" value=\"%s\"",
$select);
HTH
Jon
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: 23 January 2001 12:27
To: Adrian Murphy
Cc: PHP list
Subject: Re: [PHP] multple select forms... going to hit my head against
a wall ..
Having soved this .. thanks .. now for the next question .. *grin*
I have the $select ... but I only use it on the next page .. heheh
so I'm trying the following ..
input type=\"hidden\" name=\"select\" value=\"$select\"
which of course doens't work .. nor does
input type=\"hidden\" name=\"select[]" value=\"$select\"
any idea on how to pass an array on in an input field in a form ?
Henti
On Tue, Jan 23, 2001 at 12:01:40PM -, Adrian Murphy wrote:
hey,
since u are slecting multiple options you'll have to use an array
here's how.i u need explanation,feel free to mail me:
?
if ($select==""){
print"
form method=\"post\" name=\"select\" action=\"test.php3\"
SELECT MULTIPLE NAME=\"select[]\"
Option VALUE=\"Chocolate\"Chocolate/Chocolate Chip
Option VALUE=\"Peanut\"Peanut Brittle/Vanilla
Option Selected VALUE=\"Cookie\"Cookie Batter
Option VALUE=\"Blueberry\"Vanilla/Blueberry
Option VALUE=\"Caramel\"Caramel Swirl
Option VALUE=\"Other\"Other...
/selectbr
input type=\"submit\" name=\"send\" value=\"test\"
/form
";
}else{
///count array
$num = count($select);
file://loop through array
for($i = 0;$i $num;$i++){
print $select[$i] . "br";
}
}
?
- Original Message -
From: [EMAIL PROTECTED]
To: PHP list [EMAIL PROTECTED]
Sent: Tuesday, January 23, 2001 11:42 AM
Subject: [PHP] multple select forms... going to hit my head against a
wall
..
Hi all
I'm having a slight little problem .. I can't seem to solve..
I have a multiple select form .. that i select mutiple options from
and
then it creates a variable called $select
now if I display $select .. I only get the last selected value .. here
foloows test code..
?
if ($select==""){
print"
form method=\"post\" name=\"select\" action=\"test.php3\"
SELECT MULTIPLE NAME=\"select\"
Option VALUE=\"Chocolate\"Chocolate/Chocolate Chip
Option VALUE=\"Peanut\"Peanut Brittle/Vanilla
Option Selected VALUE=\"Cookie\"Cookie Batter
Option VALUE=\"Blueberry\"Vanilla/Blueberry
Option VALUE=\"Caramel\"Caramel Swirl
Option VALUE=\"Other\"Other...
/selectbr
input type=\"submit\" name=\"send\" value=\"test\"
/form
";
}else{
print $select;
}
?
I'm de missing something ... can sombody please lend a hand .. thanks
Henti Smith
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail:
[EMAIL PROTECTED]
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Re: [PHP] multple select forms... going to hit my head against a wall ..
If you don't put it in a session var, and need to transport it you can use
f. x. :
input type=hidden name='user_selections' value='?=implode( "||",
$select )?'
This puts double pipe-chars between the array variables. You can later (when
u need to use the vars again) use: $select = explode( "||",
$user_selections );
to put it into an array again.
-J
- Original Message -
From: [EMAIL PROTECTED]
To: "Adrian Murphy" [EMAIL PROTECTED]
Cc: "PHP list" [EMAIL PROTECTED]
Sent: Tuesday, January 23, 2001 1:26 PM
Subject: Re: [PHP] multple select forms... going to hit my head against a
wall ..
Having soved this .. thanks .. now for the next question .. *grin*
I have the $select ... but I only use it on the next page .. heheh
so I'm trying the following ..
input type=\"hidden\" name=\"select\" value=\"$select\"
which of course doens't work .. nor does
input type=\"hidden\" name=\"select[]" value=\"$select\"
any idea on how to pass an array on in an input field in a form ?
Henti
On Tue, Jan 23, 2001 at 12:01:40PM -, Adrian Murphy wrote:
hey,
since u are slecting multiple options you'll have to use an array
here's how.i u need explanation,feel free to mail me:
?
if ($select==""){
print"
form method=\"post\" name=\"select\" action=\"test.php3\"
SELECT MULTIPLE NAME=\"select[]\"
Option VALUE=\"Chocolate\"Chocolate/Chocolate Chip
Option VALUE=\"Peanut\"Peanut Brittle/Vanilla
Option Selected VALUE=\"Cookie\"Cookie Batter
Option VALUE=\"Blueberry\"Vanilla/Blueberry
Option VALUE=\"Caramel\"Caramel Swirl
Option VALUE=\"Other\"Other...
/selectbr
input type=\"submit\" name=\"send\" value=\"test\"
/form
";
}else{
///count array
$num = count($select);
file://loop through array
for($i = 0;$i $num;$i++){
print $select[$i] . "br";
}
}
?
- Original Message -
From: [EMAIL PROTECTED]
To: PHP list [EMAIL PROTECTED]
Sent: Tuesday, January 23, 2001 11:42 AM
Subject: [PHP] multple select forms... going to hit my head against a
wall
..
Hi all
I'm having a slight little problem .. I can't seem to solve..
I have a multiple select form .. that i select mutiple options from
and
then it creates a variable called $select
now if I display $select .. I only get the last selected value .. here
foloows test code..
?
if ($select==""){
print"
form method=\"post\" name=\"select\" action=\"test.php3\"
SELECT MULTIPLE NAME=\"select\"
Option VALUE=\"Chocolate\"Chocolate/Chocolate Chip
Option VALUE=\"Peanut\"Peanut Brittle/Vanilla
Option Selected VALUE=\"Cookie\"Cookie Batter
Option VALUE=\"Blueberry\"Vanilla/Blueberry
Option VALUE=\"Caramel\"Caramel Swirl
Option VALUE=\"Other\"Other...
/selectbr
input type=\"submit\" name=\"send\" value=\"test\"
/form
";
}else{
print $select;
}
?
I'm de missing something ... can sombody please lend a hand .. thanks
Henti Smith
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail:
[EMAIL PROTECTED]
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