RE: [PHP] php + javascript hard day together ?
-Original Message- From: David D [mailto:[EMAIL PROTECTED]] Sent: 13 July 2002 16:38 I can manage this script to work. Js warn about listid[], he doesnt like [] in a var name ! Php needs them to collect an array from form checkboxes. form name=test action=check.php input type=button value=partout onClick=this.value=check(this.form.listid[])br use this.form['listid[]'] It seems to be a very little known fact that, by definition, the JavaScript construct x.y is identical to x['y'] so an extended accessor such as w.x.y.z could also be written equally validly in any of the following ways: w.x.y['z'] w.x['y'].z w['x'].y.z w['x'].y['z'] w['x']['y'].z and several other similar combinations! (And, yes, that means that this['form']['listid[]'] should be valid, too!) Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] php + javascript hard day together ?
Hi all,
I can manage this script to work.
Js warn about listid[], he doesnt like [] in a var name !
Php needs them to collect an array from form checkboxes.
Here is my source :
!doctype html public -//W3C//DTD HTML 4.0 //EN
html
head
titleTitle here!/title
SCRIPT LANGUAGE=JavaScript
!-- Begin
var checkflag = false;
function check(field) {
if (checkflag == false) {
for (i = 0; i field.length; i++) {
field[i].checked = true;
}
checkflag = true;
return nowhere; }
else {
for (i = 0; i field.length; i++) {
field[i].checked = false;
}
checkflag = false;
return everywhere; }
}
/script
/head
body
?
print_r($listid); // what in listid ?
?
form name=test action=check.php
input type=button value=partout
onClick=this.value=check(this.form.listid[])br
input type=checkbox name=listid[] value=11br
input type=checkbox name=listid[] value=22br
input type=submit
/form
script
var obj=eval('document.test.listid[]');
alert(obj); // no object !
/script
/body
/html
Thanks.
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Re: [PHP] php + javascript hard day together ?
On Saturday 13 July 2002 23:37, David D wrote:
Hi all,
I can manage this script to work.
Js warn about listid[], he doesnt like [] in a var name !
There's nothing you can do about that.
Php needs them to collect an array from form checkboxes.
You'll just have to rename your checkboxes to something like listid_1,
listid_2 etc. Then loop:
# Untested code, use with caution
for ($i = 1; $i $number_of_checkboxes; $i++) {
if (isset($_GET[listid_$i])) {
echo listid_$i is checkedbr;
}
}
--
Jason Wong - Gremlins Associates - www.gremlins.com.hk
Open Source Software Systems Integrators
* Web Design Hosting * Internet Intranet Applications Development *
/*
Bunker's Admonition:
You cannot buy beer; you can only rent it.
*/
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Re: [PHP] php + javascript hard day together ?
I hack js no need to change in php :
SCRIPT LANGUAGE=JavaScript
!-- Begin
var checkflag = false;
// on va se ballader parmis les elements de formualire et toucher
// au case a cocher
function check(formulaire) {
if (checkflag == false) {
for (i = 0; i formulaire.length; i++) {
if (formulaire.elements[i].type.toLowerCase() == 'checkbox') {
formulaire.elements[i].checked = true;
}
}
checkflag = true;
return Nulpart; }
else {
for (i = 0; i formulaire.length; i++) {
if (formulaire.elements[i].type.toLowerCase() == 'checkbox') {
formulaire.elements[i].checked = false;
}
}
checkflag = false;
return Partout; }
}
/script
I pass teh form to the function and scan its elements
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