[PHP] Str_Replace Command
I have never had this problem before and it is probably something simple...
Please take a look at the two foreach statements. I am at a loss as to why
the second line does not actually remove the quotes. The first foreach
statement does so how are they different.
$StockURL =
http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;;
$StockResults = implode('', file($StockURL));
$Rows = split(\n, $StockResults);
foreach($Rows as $Row) { echo str_replace('',,$Row).br\n; }
foreach($Rows as $Row) { str_replace('',,$Row); echo $Row.br\n; }
Eventually, I need to break apart the $Row into two elements $Symbol and
$Price and then into a two dimensional array. I have done this with the code
below, but so far, I can not get rid of the quotes.
foreach($Rows as $Row){
list($Symbol, $Price) = split(\n, $Row);
$TickerData=array($Symbol=$Price);
}
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Re: [PHP] Str_Replace Command
On Tuesday 03 February 2004 00:14, Christopher J. Crane wrote:
$StockURL =
http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;;
$StockResults = implode('', file($StockURL));
$Rows = split(\n, $StockResults);
foreach($Rows as $Row) { echo str_replace('',,$Row).br\n; }
foreach($Rows as $Row) { str_replace('',,$Row); echo $Row.br\n; }
str_replace() RETURNS the replaced string. It does not alter $Row.
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Re: [PHP] Str_Replace Command
Ok I got around it by the following, but now I have a new problem. I can not
get the two dimensional array working. I want to later be able to output a
variable like this $TickerData[IKN] and it will output the associated
$Price.
$StockURL =
http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;;
$StockResults = implode('', file($StockURL));
$Rows = split(\n, $StockResults);
foreach($Rows as $Row) {
list($Symbol, $Price) = split(,, $Row);
$Symbol = str_replace('', , $Symbol);
$TickerData = array($Symbol=$Ticker);
}
print_r($TickerData);
echo $TickerData[IKN].br\n;
Jason Wong [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
On Tuesday 03 February 2004 00:14, Christopher J. Crane wrote:
$StockURL =
http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;;
$StockResults = implode('', file($StockURL));
$Rows = split(\n, $StockResults);
foreach($Rows as $Row) { echo str_replace('',,$Row).br\n; }
foreach($Rows as $Row) { str_replace('',,$Row); echo
$Row.br\n; }
str_replace() RETURNS the replaced string. It does not alter $Row.
--
Jason Wong - Gremlins Associates - www.gremlins.biz
Open Source Software Systems Integrators
* Web Design Hosting * Internet Intranet Applications Development *
--
Search the list archives before you post
http://marc.theaimsgroup.com/?l=php-general
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power should not become too important in any church.
- Eleanor Roosevelt
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Re: [PHP] Str_Replace Command
On Tuesday 03 February 2004 00:52, Christopher J. Crane wrote: Ok I got around it by the following, but now I have a new problem. I can not get the two dimensional array working. I want to later be able to output a variable like this $TickerData[IKN] and it will output the associated $Price. print_r($TickerData); So what does the above show? If it isn't what you expect, figure out *why*. Like how is $TickerData being assigned. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* We have phasers, I vote we blast 'em! -- Bailey, The Corbomite Maneuver, stardate 1514.2 */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Str_Replace Command
Well this is it and it is really got me...
Echoing out the $Symbol and $Price works just fine one row about the
$TickerData array assignment. Yet it outputs nothing.
Array ( [] = ) is what I get. If I change the line to
$TickerData = array ($Symbol = $Price); I get nothing, or the same
result. If I change the line to
$TickerData = array ('$Symbo'l = '$Price'); I get the following
Array ( [$Symbol] = $Price ) which tells me the assignment works, but it
seems like the $Symbol and $Price variable are blank when assigning to the
array. I know that they are not blank since they echoed out just fine one
line above.GRR
$StockURL =
http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;;
$StockResults = implode('', file($StockURL));
$Rows = split(\n, $StockResults);
foreach($Rows as $Row) {
list($Symbol, $Price) = split(,, $Row);
$Symbol = str_replace('', , $Symbol);
echo $Symbol. - .$Price.br\n;
$TickerData = array ($Symbol = $Price);
}
print_r($TickerData);
Jason Wong [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
On Tuesday 03 February 2004 00:52, Christopher J. Crane wrote:
Ok I got around it by the following, but now I have a new problem. I can
not get the two dimensional array working. I want to later be able to
output a variable like this $TickerData[IKN] and it will output the
associated $Price.
print_r($TickerData);
So what does the above show? If it isn't what you expect, figure out
*why*.
Like how is $TickerData being assigned.
--
Jason Wong - Gremlins Associates - www.gremlins.biz
Open Source Software Systems Integrators
* Web Design Hosting * Internet Intranet Applications Development *
--
Search the list archives before you post
http://marc.theaimsgroup.com/?l=php-general
--
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We have phasers, I vote we blast 'em!
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Re: [PHP] Str_Replace Command
On Tuesday 03 February 2004 01:09, Christopher J. Crane wrote:
Well this is it and it is really got me...
Echoing out the $Symbol and $Price works just fine one row about the
$TickerData array assignment. Yet it outputs nothing.
Array ( [] = ) is what I get. If I change the line to
$TickerData = array ($Symbol = $Price); I get nothing, or the same
result. If I change the line to
$TickerData = array ('$Symbo'l = '$Price'); I get the following
Array ( [$Symbol] = $Price ) which tells me the assignment works, but it
seems like the $Symbol and $Price variable are blank when assigning to the
array. I know that they are not blank since they echoed out just fine one
line above.GRR
Are you sure that the line: echo $Symbol ...
is displaying something sensible for each $Row?
You're overwriting $TickerData at each iteration of the foreach-loop thus if
your last $Row doesn't contain something sensible neither would $TickerData.
You probably want to use this assignment instead:
$TickerData[$Symbol] = $Price;
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Jason Wong - Gremlins Associates - www.gremlins.biz
Open Source Software Systems Integrators
* Web Design Hosting * Internet Intranet Applications Development *
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Search the list archives before you post
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Re: [PHP] Str_Replace Command
snip
$StockURL =
http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;;
$StockResults = implode('', file($StockURL));
$Rows = split(\n, $StockResults);
foreach($Rows as $Row) {
list($Symbol, $Price) = split(,, $Row);
$Symbol = str_replace('', , $Symbol);
echo $Symbol. - .$Price.br\n;
$TickerData = array ($Symbol = $Price);
}
print_r($TickerData);
/snip
why not replace:
$TickerData = array ($Symbol = $Price);
that line reassigns $TickerData to a array with one element in it
everytime you call it. The last time through your loop, $Symbol = ''
and $Price = '', so you get Array ( [] = ) when you print_r
with this:
$TickerData[$Symbol] = $Price;
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RE: [PHP] Str_Replace Command
Matt:
This worked perfect. Thank you. I didn't realize it was reassigning, I
thought it would work similar to array_push and add to the existing data. I
get it now, thanks to you.
Thanks again. I had been so frustrated I was losing my objectivity.
Christopher J. Crane
Network Manager - Infrastructure Services
IKON Document Efficiency at Work
-Original Message-
From: Matt Matijevich [mailto:[EMAIL PROTECTED]
Sent: Monday, February 02, 2004 12:25 PM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: Re: [PHP] Str_Replace Command
snip
$StockURL =
http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;;
$StockResults = implode('', file($StockURL));
$Rows = split(\n, $StockResults);
foreach($Rows as $Row) {
list($Symbol, $Price) = split(,, $Row); $Symbol = str_replace('',
, $Symbol);
echo $Symbol. - .$Price.br\n;
$TickerData = array ($Symbol = $Price);
}
print_r($TickerData);
/snip
why not replace:
$TickerData = array ($Symbol = $Price);
that line reassigns $TickerData to a array with one element in it everytime
you call it. The last time through your loop, $Symbol = ''
and $Price = '', so you get Array ( [] = ) when you print_r
with this:
$TickerData[$Symbol] = $Price;
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