I've just added another record to the table. Now they're a total of 3
records matching the WHERE emp_id='$emp_login_id criteria. When I
print_r(array_values($emp_login_grp_id)); I get the following values:
Array ( [0] = 222 [1] = 333 ). For some reason, it seems to be skipping
the first record.
O From Now 'Till Then,
\-Reginald Alex Mullin
/\ 212-894-1690
-Original Message-
From: Mullin, Reginald
Sent: Monday, March 18, 2002 2:29 PM
To: 'Mark Heintz PHP Mailing Lists'; [EMAIL PROTECTED]
Subject: RE: [PHP] Creating arrays using results from MySQL query
Mark,
I'm still experiencing the same problem. Only one record is being added
to the arrays. There are currently two records in the DB workgroups table
matching the WHERE emp_id='$emp_login_id criteria.
Here's the 2 records in the DB workgroups table:
FIELDSValue#1 Value#2
wkgrp_id 1 4
grp_id111 222
emp_id39 39
wkgrp_create_date 2002-03-16 23:45:43 -00-00 00:00:00
wkgrp_change_date 2002-03-16 23:45:43 -00-00 00:00:00
wkgrp_change_by webmaster webmaster
wkgrp_create_by webmaster webmaster
role_id 1 1
I'm only getting back Value#2.
Here's the modified PHP code:
File: login.php
if ($employee_2){
$emp_login_wkgrp_id = array();
$emp_login_grp_id = array();
$emp_login_role_id = array();
$i = 0;
while($employee_2 = mysql_fetch_array($result_2)){
$emp_login_wkgrp_id[$i] = $employee_2[wkgrp_id];
$emp_login_grp_id[$i] = $employee_2[grp_id];
$emp_login_role_id[$i] = $employee_2[role_id];
$i++;
}
session_register('emp_login_wkgrp_id');
session_register('emp_login_grp_id');
session_register('emp_login_role_id');
}
O From Now 'Till Then,
\-Reginald Alex Mullin
/\ 212-894-1690
-Original Message-
From: Mark Heintz PHP Mailing Lists [SMTP:[EMAIL PROTECTED]]
Sent: Monday, March 18, 2002 1:26 PM
To: Mullin, Reginald
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Creating arrays using results from MySQL query
You have to call mysql_fetch_array for each record in your result set...
$emp_login_wkgrp_id = array ();
$emp_login_grp_id = array ();
$emp_login_role_id = array ();
$i = 0;
while($employee_2 = mysql_fetch_array($result_2)){
$emp_login_wkgrp_id[$i] = $employee_2[wkgrp_id];
$emp_login_grp_id[$i] = $employee_2[grp_id];
$emp_login_role_id[$i] = $employee_2[role_id];
$i++;
}
mysql_fetch_array will return false when you run out of results, breaking
the while loop.
Check the manual for more info:
http://www.php.net/manual/en/function.mysql-fetch-array.php
mh.
On Mon, 18 Mar 2002, Mullin, Reginald wrote:
Hi Guys,
I've been experiencing some problems when trying to build 3 arrays with
the
ID values of all of the groups a user belongs to. (I then want to
register
these arrays into the current session). The arrays only appear to be
getting the first value (group ID) instead of all of the values the user
belongs to. What am I doing wrong here?
My code looks like this:
File: login.php
# if $employee_1, query db workgroups table to check if $emp_login_id
belongs to any groups
$sql_2 = SELECT * FROM workgroups WHERE emp_id='$emp_login_id';
$result_2 = @mysql_query($sql_2) or die (mysql_error());
$rows = mysql_num_rows($result_2);
$employee_2 = mysql_fetch_array($result_2);
# if match, set workgroups login variables in array, then register
workgroups login variables in session
if ($employee_2){
$emp_login_wkgrp_id = array ();
$emp_login_grp_id = array ();
$emp_login_role_id = array ();
for ($i=0; $i$rows; $i++){
$emp_login_wkgrp_id[$i] = $employee_2[wkgrp_id];
$emp_login_grp_id[$i] = $employee_2[grp_id];
$emp_login_role_id[$i] = $employee_2[role_id];
}
session_register('emp_login_wkgrp_id');
session_register('emp_login_grp_id');
session_register('emp_login_role_id');
}
O From Now 'Till Then,
\-Reginald Alex Mullin
/\ 212-894-1690
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