Re: [PHP] Math rounding problem

[DL Neil]

Charlie,

 For an arbitrary large number I need to round() it up to the hundreds place
 if it is not divisible by 100 and leave it untouched if it is.
 
 So 1100 would round to 1100 and
 1101 would round to 1200.
 
 Is there a clean way to do this?
 
 Currently I'm:
 $scale = round($scale+49, -2); // round up to hundreds.
 
 But this is messy.


You thought that was messy? Try:

if ( ( intval( $scale  / 100 ) * 100 )  $scale )
{   
   $scale = 1 + ( intval( $scale  / 100 ) * 100 );
}

Regards,
=dn



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RE: [PHP] Math rounding problem

[Charlie Killian]

This equation  from Bogdan is simple and working:

$scale=ceil($scale/100)*100;

Thanks to all those who helped,

Charlie


 -Original Message-
 From: Bogdan Stancescu [mailto:[EMAIL PROTECTED]]
 
 $scale=ceil($scale/100)*100, maybe?
 
 Bogdan

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Re: [PHP] Math rounding problem

[hugh danaher]

ceil() maybe
- Original Message -
From: Charlie Killian [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, February 08, 2002 4:14 PM
Subject: [PHP] Math rounding problem


 For an arbitrary large number I need to round() it up to the hundreds
place
 if it is not divisible by 100 and leave it untouched if it is.

 So 1100 would round to 1100 and
 1101 would round to 1200.

 Is there a clean way to do this?

 Currently I'm:
 $scale = round($scale+49, -2); // round up to hundreds.

 But this is messy.

 Charlie



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 To unsubscribe, visit: http://www.php.net/unsub.php



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