RE: [PHP] Passing array to function
-Original Message- From: Bill Hudspeth [mailto:[EMAIL PROTECTED]] Sent: 13 August 2002 17:10 [] DESIRED FUNCTION VERSION $elementname=cgroup_1[]; $elementsarray=$chon_group_a; PrintOptionBox($elementname,$elementsarray); Well, looks ok-ish so far -- what's in the PrintOptionBox function, and how exactly does it fail (intended vs actual results)? Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Beckett Park, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] passing array to function?
On Wed, 7 Feb 2001 11:30, Jaxon wrote:
How do you write a function that takes an array as an argument?
Could someone please point me at an example?
Regards,
Jaxon
Try this:
?php
function show_elements($ary) {
while(list($key,$val) = each($ary)) {
echo "$key = $valBR";
}
}
$fruits=array("a"="apple","b"="banana","c"="cucumber","d"="apricot",);
show_elements($fruits);
?
That's pretty much plagiarised from the array functions in the manual :-)
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